JEE Main 2025 · previous year paper

JEE Main 2025 — 24 January, Morning Shift

71 questions with the verified answer key. Open any question for its step-by-step solution.

  1. Question 1Mathematics· Vector Algebra

    Let a→=i^+2j^+3k^,b→=3i^+j^−k^\overrightarrow{\mathrm{a}}=\hat{\mathrm{i}}+2 \hat{\mathrm{j}}+3 \hat{\mathrm{k}}, \overrightarrow{\mathrm{b}}=3 \hat{\mathrm{i}}+\hat{\mathrm{j}}-\hat{\mathrm{k}} and c→\overrightarrow{\mathrm{c}} be three vectors such that c⃗\vec{c} is coplanar with a⃗\vec{a} and b⃗\vec{b}. If the vector

    c→\overrightarrow{\mathrm{c}} is perpendicular to b⃗\vec{b} and a→⋅c→=5\overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{c}}=5, then ∣c→∣|\overrightarrow{\mathbf{c}}| is equal to

    1. Option A:

      132\frac{1}{3 \sqrt{2}}

    2. Option B:

      18

    3. Option C:

      16

    4. Option D:

      116\sqrt{\frac{11}{6}}

  2. Question 2Mathematics· Definite Integration

    In I(m,n)=∫01xm−1(1−x)n−1dx,m,n>0I(m, n)=\int_{0}^{1} x^{m-1}(1-x)^{n-1} d x, m, n>0, then I(9,14)+I(10,13)\mathrm{I}(9,14)+\mathrm{I}(10,13) is

    1. Option A:

      I(9,1)I(9,1)

    2. Option B:

      I(19,27)I(19,27)

    3. Option C:

      I(1,13)I(1,13)

    4. Option D:

      I(9,13)I(9,13)

  3. Question 3Mathematics· Limits, Continuity and Differentiability

    Let f:R−{0}→R\mathrm{f}: \mathbb{R}-\{0\} \rightarrow \mathbb{R} be a function such that f(x)−6f(1x)=353x−52f(x)-6 f\left(\frac{1}{x}\right)=\frac{35}{3 x}-\frac{5}{2}. If the

    lim⁡x→0(1αx+f(x))=β;\lim _{x \rightarrow 0}\left(\frac{1}{\alpha x}+f(x)\right)=\beta ; α,β∈R\alpha, \beta \in \mathbb{R}, then α+2β\alpha+2 \beta is equal to

    1. Option A:

      3

    2. Option B:

      5

    3. Option C:

      4

    4. Option D:

      6

  4. Question 4Mathematics· Sequence and Series

    Let Sn=12+16+112+120+…\mathrm{S}_{\mathrm{n}}=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\ldots upto n terms. If the sum of the first six terms of an A.P. with first

    term -p and common difference p is 2026 S2025\sqrt{2026 \mathrm{~S}_{2025}}, then the absolute difference between 20th 20^{\text {th }} and 15th 15^{\text {th }}

    terms of the A.P. is

    1. Option A:

      25

    2. Option B:

      90

    3. Option C:

      20

    4. Option D:

      45

  5. Question 5Mathematics· Functions

    Let f(x)=2x+2+1622x+1+2x+4+32f(x)=\frac{2^{x+2}+16}{2^{2 x+1}+2^{x+4}+32}. Then the value of 8(f(115)+f(215)+…+f(5915))8\left(\mathrm{f}\left(\frac{1}{15}\right)+\mathrm{f}\left(\frac{2}{15}\right)+\ldots+\mathrm{f}\left(\frac{59}{15}\right)\right) is equal to

    1. Option A:

      118118

    2. Option B:

      9292

    3. Option C:

      102102

    4. Option D:

      108108

  6. Question 6Mathematics· Quadratic Equations

    If α\alpha and β\beta are the roots of the equation 2z2−3z−2i=02 z^{2}-3 z-2 i=0, where i=−1i=\sqrt{-1}, then 16.Re⁡(α19+β19+α11+β11α15+β15)⋅Im⁡(α19+β19+α11+β11α15+β15)\operatorname{Re}\left(\frac{\alpha^{19}+\beta^{19}+\alpha^{11}+\beta^{11}}{\alpha^{15}+\beta^{15}}\right) \cdot \operatorname{Im}\left(\frac{\alpha^{19}+\beta^{19}+\alpha^{11}+\beta^{11}}{\alpha^{15}+\beta^{15}}\right) is equal to

    1. Option A:

      398

    2. Option B:

      312

    3. Option C:

      409

    4. Option D:

      441

  7. Question 7Mathematics· Limits, Continuity and Differentiability

    lim⁡x→0cosec⁡x(2cos⁡2x+3cos⁡x−cos⁡2x+sin⁡x+4)\lim _{x \rightarrow 0} \operatorname{cosec} x\left(\sqrt{2 \cos ^{2} x+3 \cos x}-\sqrt{\cos ^{2} x+\sin x+4}\right) is

    1. Option A:

      0

    2. Option B:

      125\frac{1}{2 \sqrt{5}}

    3. Option C:

      115\frac{1}{\sqrt{15}}

    4. Option D:

      −125-\frac{1}{2 \sqrt{5}}

  8. Question 8Mathematics· 3D Geometry

    Let in a △ABC\triangle A B C, the length of the side ACA C be 6 , the vertex BB be (1,2,3)(1,2,3) and the vertices A,CA, C lie on the line x−63=y−72=z−7−2\frac{x-6}{3}=\frac{y-7}{2}=\frac{z-7}{-2}. Then the area (in sq. units) of △ABC\triangle A B C is

    1. Option A:

      42

    2. Option B:

      21

    3. Option C:

      56

    4. Option D:

      17

  9. Question 9Mathematics· Differential Equations

    Let y=y(x)\mathrm{y}=\mathrm{y}(\mathrm{x}) be the solution of the differential equation (xy−5x21+x2)dx+(1+x2)dy=0\left(x y-5 x^{2} \sqrt{1+x^{2}}\right) d x+\left(1+x^{2}\right) d y=0, y(0)=0y(0)=0.

    Then y(3)y(\sqrt{3}) is equal to

    1. Option A:

      532\frac{5 \sqrt{3}}{2}

    2. Option B:

      143\sqrt{\frac{14}{3}}

    3. Option C:

      222 \sqrt{2}

    4. Option D:

      152\sqrt{\frac{15}{2}}

  10. Question 10Mathematics· Ellipse

    Let the product of the focal distances of the point (3,12)\left(\sqrt{3}, \frac{1}{2}\right) on the ellipse x2a2+y2 b2=1,(a>b)\frac{\mathrm{x}^{2}}{\mathrm{a}^{2}}+\frac{\mathrm{y}^{2}}{\mathrm{~b}^{2}}=1,(\mathrm{a}>\mathrm{b}), be 74\frac{7}{4}. Then the absolute difference of the eccentricities of two such ellipses is

    1. Option A:

      3−2232\frac{3-2 \sqrt{2}}{3 \sqrt{2}}

    2. Option B:

      1−32\frac{1-\sqrt{3}}{\sqrt{2}}

    3. Option C:

      3−2223\frac{3-2 \sqrt{2}}{2 \sqrt{3}}

    4. Option D:

      1−223\frac{1-2 \sqrt{2}}{\sqrt{3}}

  11. Question 11Mathematics· Probability

    A and B alternately throw a pair of dice. A wins if he throws a sum of 5 before B throws a sum of 8, and B wins if he throws a sum of 8 before A throws a sum of 5. The probability, that A wins if A makes the first throw, is

    1. Option A:

      917\frac{9}{17}

    2. Option B:

      919\frac{9}{19}

    3. Option C:

      817\frac{8}{17}

    4. Option D:

      819\frac{8}{19}

  12. Question 12Mathematics· Area under the Curves

    Consider the region R={(x,y):x≤y≤9−113x2,x≥0}R=\left\{(x, y): x \leq y \leq 9-\frac{11}{3} x^{2}, x \geq 0\right\}. The area, of the largest rectangle of sides parallel to the coordinate axes and inscribed in RR, is :

    1. Option A:

      625111\frac{625}{111}

    2. Option B:

      730119\frac{730}{119}

    3. Option C:

      567121\frac{567}{121}

    4. Option D:

      821123\frac{821}{123}

  13. Question 13Mathematics· Area under the Curves

    The area of the region {(x,y):x2+4x+2≤y≤∣x+2∣}\left\{(\mathrm{x}, \mathrm{y}): \mathrm{x}^{2}+4 \mathrm{x}+2 \leq \mathrm{y} \leq|\mathrm{x}+2|\right\} is equal to

    1. Option A:

      7

    2. Option B:

      24/524 / 5

    3. Option C:

      20/320 / 3

    4. Option D:

      5

  14. Question 14Mathematics· Probability

    For a statistical data x1,x2,…,x10x_{1}, x_{2}, \ldots, x_{10} of 10 values, a student obtained the mean as 5.5 and ∑i=110xi2=371\sum_{i=1}^{10} \mathrm{x}_{\mathrm{i}}^{2}=371. He later found that he had noted two values in the data incorrectly as 4 and 5 , instead of the correct values 6 and 8 , respectively. The variance of the corrected data is

    1. Option A:

      7

    2. Option B:

      4

    3. Option C:

      9

    4. Option D:

      5

  15. Question 15Mathematics· Circles

    Let circle CC be the image of x2+y2−2x+4y−4=0x^{2}+y^{2}-2 x+4 y-4=0 in the line 2x−3y+5=02 x-3 y+5=0 and AA be the point on CC such that OA is parallel to xx-axis and AA lies on the right hand side of the centre OO of CC. If B(α,β)B(\alpha, \beta), with β<4\beta<4, lies on CC such that the length of the arc AB is (1/6)th (1 / 6)^{\text {th }} of the perimeter of C , then β−3α\beta-\sqrt{3} \alpha is

    equal to

    1. Option A:

      3

    2. Option B:

      3+33+\sqrt{3}

    3. Option C:

      4−34-\sqrt{3}

    4. Option D:

      4

  16. Question 16Mathematics· Binomial Theorem

    For some n≠10,n \neq 10, let the coefficients of the 5th,6th5^{th}, 6^{th} and 7th7^{th} terms in the binomial expansion of (1+x)n+4(1+x)^{n+4} be in A.P. Then the largest coefficient in the expansion of (1+x)n+4(1+x)^{n+4} is:

    1. Option A:

      70

    2. Option B:

      35

    3. Option C:

      20

    4. Option D:

      10

  17. Question 17Mathematics· Quadratic Equations

    The product of all the rational roots of the equation (x2−9x+11)2−(x−4)(x−5)=3,(x^2 - 9x + 11)^2 - (x-4)(x-5) = 3, is equal to:

    1. Option A:

      14

    2. Option B:

      7

    3. Option C:

      28

    4. Option D:

      21

  18. Question 18Mathematics· 3D Geometry

    Let the line passing through the points (−1,2,1)(-1,2,1) and parallel to the line x−12=y+13=z4\frac{\mathrm{x}-1}{2}=\frac{\mathrm{y}+1}{3}=\frac{\mathrm{z}}{4}

    intersect the line x+23=y−32=z−41\frac{x+2}{3}=\frac{y-3}{2}=\frac{z-4}{1} at the point PP. Then the distance of P from the point Q(4,−5,1)\mathrm{Q}(4,-5,1) is :

    1. Option A:

      55

    2. Option B:

      1010

    3. Option C:

      565 \sqrt{6}

    4. Option D:

      555 \sqrt{5}

  19. Question 19Mathematics· Straight lines

    Let the lines 3x−4y−α=0,8x−11y−33=03 x-4 y-\alpha=0,8 x-11 y-33=0, and 2x−3y+λ=02 x-3 y+\lambda=0 be concurrent. If the image of the point (1,2)(1,2) in the line 2x−3y+λ=02 x-3 y+\lambda=0 is (5713,−4013)\left(\frac{57}{13}, \frac{-40}{13}\right), then ∣αλ∣|\alpha \lambda| is equal to :

    1. Option A:

      84

    2. Option B:

      91

    3. Option C:

      113

    4. Option D:

      101

  20. Question 20Mathematics· Matrices

    If the system of equations

    2x−y+z=42 \mathrm{x}-\mathrm{y}+\mathrm{z}=4

    5x+λy+3z=125 x+\lambda y+3 z=12

    100x−47y+μz=212100 x-47 y+\mu z=212,

    has infinitely many solutions, then μ−2λ\mu-2 \lambda is equal to

    1. Option A:

      56

    2. Option B:

      59

    3. Option C:

      55

    4. Option D:

      57

  21. Question 21Mathematics· Definite Integration

    Let f be a differentiable function such that 2(x+2)2f(x)−3(x+2)2=10∫0x(t+2)f(t)dt2(x+2)^{2} f(x)-3(x+2)^{2}=10 \int_{0}^{x}(t+2) f(t) d t,

    x≥0x \geq 0. Then f(2)f(2) is equal to _____\_\_\_\_\_ .

  22. Question 22Mathematics· Inverse Trigonometric Functions

    If for some α,β;α≤β,α+β=8\alpha, \beta ; \alpha \leq \beta, \alpha+\beta=8 and sec⁡2(tan⁡−1α)+cosec⁡2(cot⁡−1β)=36\sec ^{2}\left(\tan ^{-1} \alpha\right)+\operatorname{cosec}^{2}\left(\cot ^{-1} \beta\right)=36, then α2+β\alpha^{2}+\beta

    is _____\_\_\_\_\_ .

  23. Question 23Mathematics· Permutations and Combinations

    The number of 3-digit numbers, that are divisible by 2 and 3 , but not divisible by 4 and 9 , is

  24. Question 24Mathematics· Matrices

    Let be a 3×33 \times 3 matrix such that XTAX=OX^T A X = O for all nonzero 3×13 \times 1 matrices X=[xyz].X = \begin{bmatrix} x \\ y \\ z \end{bmatrix} .

    If A[111]=[14−5],A[121]=[04−8], and\text{If } A \begin{bmatrix} 1 \\ 1 \\ 1 \end{bmatrix} = \begin{bmatrix} 1 \\ 4 \\ -5 \end{bmatrix}, A \begin{bmatrix} 1 \\ 2 \\ 1 \end{bmatrix} = \begin{bmatrix} 0 \\ 4 \\ -8 \end{bmatrix}, \text{ and} det (adj(2(A+I)))=2α3β5γ,α,β,γ∈N, then\text{det } (\text{adj} (2(A + I))) = 2^\alpha 3^\beta 5^\gamma , \alpha, \beta, \gamma \in N, \text{ then} α2+β2+γ2 is\alpha^2 + \beta^2 + \gamma^2 \text{ is}
  25. Question 25Mathematics· Sets and Relations

    Let S={p1,p2……,p10}S=\left\{p_{1}, p_{2} \ldots \ldots, p_{10}\right\} be the set of first ten prime numbers. Let A=S∪PA=S \cup P, where PP is the set

    of all possible products of distinct element of SS. Then the number of all ordered pairs ( x,yx, y ), x∈Sx \in S, y∈Ay \in A,

    such that xx divides yy, is _____\_\_\_\_\_ .

  26. Question 26Chemistry· Electrochemistry

    For the given cell

    Fe2+(eq)+Ag+(aq)→Fe3+(aq)+Ag(s)\mathrm{Fe}^{2+}(\mathrm{eq})+\mathrm{Ag}^{+}(\mathrm{aq}) \rightarrow \mathrm{Fe}^{3+}(\mathrm{aq})+\mathrm{Ag}(\mathrm{s})

    The standard cell potential of the above reaction is Given :

    Ag++e−→Ag\mathrm{Ag}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Ag}

    E0=xV\mathrm{E}^{0}=\mathrm{xV}

    Fe2++2e−→Fe\mathrm{Fe}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Fe}

    E0=yVE^{0}=y V

    Fe3++3e−→Fe\mathrm{Fe}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Fe}

    E0=zV\mathrm{E}^{0}=\mathrm{zV}

    1. Option A:

      x+y−zx+y-z

    2. Option B:

      x+2y−3zx+2 y-3 z

    3. Option C:

      y−2xy-2 x

    4. Option D:

      x+2yx+2 y

  27. Question 27Chemistry· Aromatic Compounds

    Following are the four molecules "P", "Q", "R" and "S".

    Which one among the four molecules will react with H−Br(aq)\mathrm{H}-\mathrm{Br}(\mathrm{aq}) at the fastest rate ?

    figure

    1. Option A:

      SS

    2. Option B:

      qq

    3. Option C:

      rr

    4. Option D:

      pp

  28. Question 28Chemistry· Coordination Compounds

    One mole of the octahedral complex compound Co(NH3)5Cl3\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}_{3} gives 3 moles of ions on dissolution in water. One mole of the same complex reacts with excess of AgNO3\mathrm{AgNO}_{3} solution to yield two moles of AgCl(s)\mathrm{AgCl}_{(\mathrm{s})}. The structure of the complex is :

    1. Option A:

      [Co(NH3)5Cl]Cl2\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{2}

    2. Option B:

      [Co(NH3)4Cl]⋅Cl2⋅NH3\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}\right] \cdot \mathrm{Cl}_{2} \cdot \mathrm{NH}_{3}

    3. Option C:

      [Co(NH3)4Cl2]Cl⋅NH3\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right] \mathrm{Cl} \cdot \mathrm{NH}_{3}

    4. Option D:

      [Co(NH3)3Cl3].2NH3\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}_{3}\right] .2 \mathrm{NH}_{3}

  29. Question 29Chemistry· Chemical Bonding

    Which of the following linear combination of atomic orbitals will lead to formation of molecular orbitals in homonuclear diatomic molecules [internuclear axis in z-direction] ?

    A. 2pz2 p_{z} and 2px2 p_{x}

    B. 2 s and 2px2 \mathrm{p}_{\mathrm{x}}

    C. 3dxy3 d_{x y} and 3dx2−y23 d_{x^{2}-y^{2}}

    D. 2 s and 2pz2 \mathrm{p}_{\mathrm{z}}

    E. 2pz2 p_{z} and 3dx2−y23 d_{x^{2}-y^{2}}

    1. Option A:

      E Only

    2. Option B:

      A and B Only

    3. Option C:

      D Only

    4. Option D:

      C and D Only

  30. Question 30Chemistry· d and f Block Elements

    Which of the following ions is the strongest oxidizing agent?

    (Atomic Number of Ce=58,Eu=63, Tb=65,Lu=71\mathrm{Ce}=58, \mathrm{Eu}=63, \mathrm{~Tb}=65, \mathrm{Lu}=71 ]

    1. Option A:

      Lu3+\mathrm{Lu}^{3+}

    2. Option B:

      Eu2+\mathrm{Eu}^{2+}

    3. Option C:

      Tb4+\mathrm{Tb}^{4+}

    4. Option D:

      Ce3+\mathrm{Ce}^{3+}

  31. Question 31Chemistry· Ionic Equilibrium

    Ksp for Cr(OH)3\mathrm{Cr}(\mathrm{OH})_{3} is 1.6×10−301.6 \times 10^{-30}. What is the molar solubility of this salt in water?

    1. Option A:

      1.6×10−30274\sqrt[4]{\frac{1.6 \times 10^{-30}}{27}}

    2. Option B:

      1.8×10−3027\frac{1.8 \times 10^{-30}}{27}

    3. Option C:

      1.8×10−305\sqrt[5]{1.8 \times 10^{-30}}

    4. Option D:

      1.6×10−302\sqrt[2]{1.6 \times 10^{-30}}

  32. Question 32Chemistry· Thermodynamics & Thermochemistry

    Let us consider an endothermic reaction which is non-spontaneous at the freezing point of water. However, the reaction is spontaneous at boiling point of water. Choose the correct option.

    1. Option A:

      Both ΔH\Delta \mathrm{H} and ΔS\Delta \mathrm{S} are ( +ve )

    2. Option B:

      ΔH\Delta \mathrm{H} is (−ve)(-\mathrm{ve}) but ΔS\Delta \mathrm{S} is (+ve)(+\mathrm{ve})

    3. Option C:

      ΔH\Delta \mathrm{H} is (+ve)(+\mathrm{ve}) but ΔS\Delta \mathrm{S} is (−ve)(-\mathrm{ve})

    4. Option D:

      Both ΔH\Delta \mathrm{H} and ΔS\Delta \mathrm{S} are (-ve)

  33. Question 33Chemistry· Practical Organic Chemistry

    Given below are two statements : one is labelled as Statement I and the other is labelled as Statement II :

    Statement I : Dumas method is used for estimation of "Nitrogen" in an organic compound.

    Statement II : Dumas method involves the formation of ammonium sulphate by heating the organic compound with conc H2SO4\mathrm{H}_{2} \mathrm{SO}_{4}.

    In the light of the above statements, choose the correct answer from the options given below

    1. Option A:

      Both Statement I and Statement II are true

    2. Option B:

      Statement I is false but Statement II is true

    3. Option C:

      Both Statement I and Statement II are false

    4. Option D:

      Statement I is true but Statement II is false

  34. Question 34Chemistry· Periodicity of Elements and Periodic Properties

    Which of the following statements are NOT true about the periodic table?

    A. The properties of elements are function of atomic weights.

    B. The properties of elements are function of atomic numbers.

    C. Elements having similar outer electronic configuration are arranged in same period.

    D. An element's location reflects the quantum numbers of the last filled orbital.

    E. The number of elements in a period is same as the number of atomic orbitals available in energy level that is being filled.

    In the light of the above statements, choose the correct answer from the options given below :

    1. Option A:

      A, C and E only

    2. Option B:

      D and E only

    3. Option C:

      A and E only

    4. Option D:

      B, C and E only

  35. Question 35Chemistry· Biomolecules

    The carbohydrates "Ribose" present in DNA, is A.

    A pentose sugar

    B. present in pyranose from

    C. in "D" configuration

    D. a reducing sugar, when free

    E. in α\alpha-anomeric form

    Choose the correct answer from the options given below:

    1. Option A:

      A, C and D Only

    2. Option B:

      A, B and E Only

    3. Option C:

      B, D and E Only

    4. Option D:

      A, D and E Only

  36. Question 36Chemistry· d and f Block Elements

    Preparation of potassium permanganate from MnO2\mathrm{MnO}_{2} involves two step process in which the 1st 1^{\text {st }} step is a reaction with KOH and KNO3\mathrm{KNO}_{3} to produce

    1. Option A:

      K4[Mn(OH)6]\mathrm{K}_{4}\left[\mathrm{Mn}(\mathrm{OH})_{6}\right]

    2. Option B:

      K3MnO4\mathrm{K}_{3} \mathrm{MnO}_{4}

    3. Option C:

      KMnO4\mathrm{KMnO}_{4}

    4. Option D:

      K2MnO4\mathrm{K}_{2} \mathrm{MnO}_{4}

  37. Question 37Chemistry· Periodicity of Elements and Periodic Properties

    The large difference between the melting and boiling points of oxygen and sulphur may be explained on the basis of:

    1. Option A:

      Atomic size

    2. Option B:

      Atomicity

    3. Option C:

      Electronegativity

    4. Option D:

      Electron gain enthalpy

  38. Question 38Chemistry· Chemical Equilibrium

    For a reaction, N2O5( g)→2NO2( g)+12O2( g)\mathrm{N}_{2} \mathrm{O}_{5(\mathrm{~g})} \rightarrow 2 \mathrm{NO}_{2(\mathrm{~g})}+\frac{1}{2} \mathrm{O}_{2(\mathrm{~g})} in a constant volume container, no

    products were present initially. The final pressure of the system when 50%50 \% of reaction gets

    completed is

    1. Option A:

      7/27 / 2 times of initial pressure

    2. Option B:

      5 times of initial pressure

    3. Option C:

      5/25 / 2 times of initial pressure

    4. Option D:

      7/47 / 4 times of initial pressure

  39. Question 39Chemistry· General Organic Chemistry

    Which of the following arrangements with respect to their reactivity in nucleophilic addition reaction is correct?

    1. Option A:

      benzaldehyde < acetophenone<< p-nitrobenzaldehyde << p-tolualdehyde

    2. Option B:

      acetophenone << benzaldehyde< p-tolualdehyde < p-nitrobenzaldehyde

    3. Option C:

      acetophenone << p-tolualdehyde < benzaldehyde < p-nitrobenzaldehyde

    4. Option D:

      p-nitrobenzaldehyde << benzaldehyde << p-tolualdehyde < acetophenone

  40. Question 40Chemistry· Aldehydes and Ketones

    Aman has been asked to synthesise the molecule

    figure

    He thought of preparing the molecule using an aldol condensation reaction. He found a few cyclic alkenes in his laboratory. He thought of performing ozonolysis reaction on alkene to produce a dicarbonyl compound followed by aldol reaction to prepare "x". Predict the suitable alkene that can lead to the formation of "x".

    1. Option A:

      image

      Option A figure
    2. Option B:

      image

      Option B figure
    3. Option C:

      image

      Option C figure
    4. Option D:

      image

      Option D figure
  41. Question 41Chemistry· Chemical Bonding

    Which of the following statement is true with respect to H2O,NH3\mathrm{H}_{2} \mathrm{O}, \mathrm{NH}_{3} and CH4\mathrm{CH}_{4} ?

    A. The central atoms of all the molecules are sp3\mathrm{sp}^{3} hybridized.

    B. The H−O−H,H−N−H\mathrm{H}-\mathrm{O}-\mathrm{H}, \mathrm{H}-\mathrm{N}-\mathrm{H} and H−C−H\mathrm{H}-\mathrm{C}-\mathrm{H} angles in the above molecules are 104.5∘,107.5∘104.5^{\circ}, 107.5^{\circ} and 109.5∘109.5^{\circ} respectively.

    C. The increasing order of dipole moment is CH4<NH3<H2O\mathrm{CH}_{4}<\mathrm{NH}_{3}<\mathrm{H}_{2} \mathrm{O}.

    D. Both H2O\mathrm{H}_{2} \mathrm{O} and NH3\mathrm{NH}_{3} are Lewis acids and CH4\mathrm{CH}_{4} is a Lewis base

    E. A solution of NH3\mathrm{NH}_{3} in H2O\mathrm{H}_{2} \mathrm{O} is basic. In this solution NH3\mathrm{NH}_{3} and H2O\mathrm{H}_{2} \mathrm{O} act as Lowry-Bronsted acid and base respectively.

    Choose the correct answer from the options given below :

    1. Option A:

      A, B and C only

    2. Option B:

      C, D and E only

    3. Option C:

      A, D and E only

    4. Option D:

      A, B, C and E only

  42. Question 42Chemistry· Chemical Equilibrium

    37.8 g N2O5\quad 37.8 \mathrm{~g} \mathrm{~N}_{2} \mathrm{O}_{5} was taken in a 1 L reaction vessel and allowed to undergo the following reaction

    at 500 K 2 N2O5( g)→2 N2O4( g)+O2( g)2 \mathrm{~N}_{2} \mathrm{O}_{5(\mathrm{~g})} \rightarrow 2 \mathrm{~N}_{2} \mathrm{O}_{4(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})}

    The total pressure at equilibrium was found to be 18.65 bar.

    Then, Kp=\mathrm{Kp}=___×10−2\times 10^{-2} [nearest integer] Assume N2O5\mathrm{N}_{2} \mathrm{O}_{5} to behave ideally under these

    conditions

    Given : R=0.082\mathrm{R}=0.082 bar Lmol−1 K−1\mathrm{L} \mathrm{mol}^{-1} \mathrm{~K}^{-1}

  43. Question 43Chemistry· Thermodynamics & Thermochemistry

    Standard entropies of X2,Y2X_{2}, Y_{2} and XY5X Y_{5} are 70, 50 and 110 J K−1 mol−1110 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1} respectively. The

    temperature in Kelvin at which the reaction

    12X2+52Y2→XY5ΔH−=−35 kJ mol−1\frac{1}{2} \mathrm{X}_{2}+\frac{5}{2} \mathrm{Y}_{2} \rightarrow \mathrm{XY}_{5} \Delta \mathrm{H}^{-}=-35 \mathrm{~kJ} \mathrm{~mol}^{-1}

    Will be at equilibrium is____(Nearest integer)

  44. Question 44Chemistry· Aromatic Compounds

    Xg of benzoic acid on reaction with aq. NaHCO3\mathrm{NaHCO}_{3} release CO2\mathrm{CO}_{2} that occupied 11.2 L volume

    at STP. X is \qquad g.

  45. Question 45Chemistry· Practical Inorganic chemistry (Qualitative Analysis)

    Among the following cations, the number of cations which will give characteristic precipitate in

    their identification tests with K4[Fe(CN)6]\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right] is :

    Cu2+,Fe3+,Ba2+,Ca2+,NH4+,Mg2+,Zn2+\mathrm{Cu}^{2+}, \mathrm{Fe}^{3+}, \mathrm{Ba}^{2+}, \mathrm{Ca}^{2+}, \mathrm{NH}_{4}^{+}, \mathrm{Mg}^{2+}, \mathrm{Zn}^{2+}

  46. Question 46Chemistry· Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

    Consider the following reaction occurring in the blast furnace.

    Fe3O4(s)+4CO(g)→3Fe(l)+4CO2(g)\mathrm{Fe_3O_4(s) + 4CO(g) \xrightarrow{} 3Fe(l) + 4CO_2(g)}

    xx kg of iron is produced when 2.32×103 kg2.32\times10^3\,\mathrm{kg} Fe3O4\mathrm{Fe_3O_4} and 2.8×102 kg2.8\times10^2\,\mathrm{kg} CO\mathrm{CO} are brought together in the furnace.

    The value of xx is ______\_\_\_\_\_\_ (nearest integer).

    Given: Molar mass of Fe3O4=232 g mol−1\mathrm{Fe_3O_4} = 232\,\mathrm{g\,mol^{-1}} Molar mass of CO=28 g mol−1\mathrm{CO} = 28\,\mathrm{g\,mol^{-1}} Molar mass of Fe=56 g mol−1\mathrm{Fe} = 56\,\mathrm{g\,mol^{-1}}

  47. Question 47Physics· Capacitors and R-C Circuits

    Consider a parallel plate capacitor of area A (of each plate) and separation 'd' between the plates. If E is the electric field and ε0\varepsilon_{0} is the permittivity of free space between the plates, then potential energy stored in the capacitor is :-

    1. Option A:

      12ε0E2Ad\frac{1}{2} \varepsilon_{0} E^{2} \mathrm{Ad}

    2. Option B:

      34ε0E2Ad\frac{3}{4} \varepsilon_{0} \mathrm{E}^{2} \mathrm{Ad}

    3. Option C:

      14ε0E2Ad\frac{1}{4} \varepsilon_{0} E^{2} \mathrm{Ad}

    4. Option D:

      ε0E2Ad\varepsilon_{0} E^{2} A d

  48. Question 48Physics· Geometrical Optics

    What is the relative decrease in focal length of a lens for an increase in optical power by 0.1 D from 2.5 D? ['D' stands for dioptre]

    1. Option A:

      0.04

    2. Option B:

      0.4

    3. Option C:

      0.1

    4. Option D:

      0.01

  49. Question 49Physics· Mechanical Properties of Matter

    An air bubble of radius 0.1 cm lies at a depth of 20 cm below the free surface of a liquid of density 1000 kg/m31000 \mathrm{~kg} / \mathrm{m}^{3}. If the pressure inside the bubble is 2100 N/m22100 \mathrm{~N} / \mathrm{m}^{2} greater than the atmospheric pressure, then the surface tension of the liquid in SI unit is (use g=10 m/s2g=10 \mathrm{~m} / \mathrm{s}^{2} )

    1. Option A:

      0.02

    2. Option B:

      0.1

    3. Option C:

      0.25

    4. Option D:

      0.05

  50. Question 50Physics· Units, Dimensions & Error Analysis

    For an experimental expression y=32.3×112527.4\mathrm{y}=\frac{32.3 \times 1125}{27.4}, where all the digits are significant. Then to report the value of yy we should write :-

    1. Option A:

      y=1326.2y=1326.2

    2. Option B:

      y=1326.19y=1326.19

    3. Option C:

      y=1326.186y=1326.186

    4. Option D:

      y=1330y=1330

  51. Question 51Physics· Atomic Physics

    During the transition of electron from state A to state C of a Bohr atom, the wavelength of emitted radiation is 2000A2000 A and it becomes 6000A6000 A when the electron jumps from state B to state C. Then the wavelength of the radiation emitted during the transition of electrons from state A to state B is :-

    Question 51 figure
    1. Option A:

      3000A3000 A

    2. Option B:

      6000A6000 A

    3. Option C:

      4000A4000 A

    4. Option D:

      2000A2000 A

  52. Question 52Physics· Semiconductor and Electronic Devices

    Consider the following statements : A. The junction area of solar cell is made very narrow compared to a photo diode. B. Solar cells are not connected with any external bias. C. LED is made of lightly doped p-n junction. D. Increase of forward current results in continuous increase of LED light intensity. E. LEDs have to be connected in forward bias for emission of light.

    1. Option A:

      B, D, E Only

    2. Option B:

      A, C Only

    3. Option C:

      A, C, E Only

    4. Option D:

      B, E Only

  53. Question 53Physics· Mechanical Properties of Matter

    The amount of work done to break a big water drop of radius ' R ' into 27 small drops of equal

    radius is 10 J . The work done required to break the same big drop into 64 small drops of equal

    radius will be :-

    1. Option A:

      15J

    2. Option B:

      10J

    3. Option C:

      20J

    4. Option D:

      5J

  54. Question 54Physics· Motion in Plane

    An object of mass ' mm ' is projected from origin in a vertical xy plane at an angle 45∘45^{\circ} with the x -axis with an initial velocity v0\mathrm{v}_{0}. The magnitude and direction of the angular momentum of the object with respect to origin, when it reaches at the maximum height, will be [ g is acceleration due to gravity]

    1. Option A:

      mv0322g\frac{\mathrm{mv}_{0}^{3}}{2 \sqrt{2} g} along negative zz-axis

    2. Option B:

      mv0322g\frac{m v_{0}^{3}}{2 \sqrt{2} g} along positive zz-axis

    3. Option C:

      mv0342g\frac{\mathrm{mv}_{0}^{3}}{4 \sqrt{2} g} along positive z -axis

    4. Option D:

      mv0342g\frac{m v_{0}^{3}}{4 \sqrt{2} g} along negative zz-axis

  55. Question 55Physics· Wave Optics

    The Young's double slit interference experiment is performed using light consisting of 480 nm and 600 nm wavelengths to form interference patterns. The least number of the bright fringes of 480 nm light that are required for the first coincidence with the bright fringes formed by 600 nm light is :-

    1. Option A:

      4

    2. Option B:

      8

    3. Option C:

      6

    4. Option D:

      5

  56. Question 56Physics· Horizontal Circular Motion

    A car of mass ' mm ' moves on a banked road having radius ' r ' and banking angle θ\theta. To avoid slipping from banked road, the maximum permissible speed of the car is v0\mathrm{v}_{0}. The coefficient of friction μ\mu between the wheels of the car and the banked road is :-

    1. Option A:

      μ=v02+rgtan⁡θrg−v02tan⁡θ\mu=\frac{v_{0}^{2}+r g \tan \theta}{r g-v_{0}^{2} \tan \theta}

    2. Option B:

      μ=v02+rgtan⁡θrg+v02tan⁡θ\mu=\frac{\mathrm{v}_{0}^{2}+\mathrm{rg} \tan \theta}{\mathrm{rg}+\mathrm{v}_{0}^{2} \tan \theta}

    3. Option C:

      μ=v02−rgtan⁡θrg+v02tan⁡θ\mu=\frac{v_{0}^{2}-r g \tan \theta}{r g+v_{0}^{2} \tan \theta}

    4. Option D:

      μ=v02−rgtan⁡θrg⁡−v02tan⁡θ\mu=\frac{v_{0}^{2}-r g \tan \theta}{\operatorname{rg}-v_{0}^{2} \tan \theta}

  57. Question 57Physics· Rotational Dynamics

    A uniform solid cylinder of mass ' m ' and radius ' r ' rolls along an inclined rough plane of inclination 45∘45^{\circ}. If it starts to roll from rest from the top of the plane then the linear acceleration of the cylinder axis will be:-

    1. Option A:

      12g\frac{1}{\sqrt{2}} g

    2. Option B:

      132g\frac{1}{3 \sqrt{2}} g

    3. Option C:

      2g3\frac{\sqrt{2} g}{3}

    4. Option D:

      2g\sqrt{2} g

  58. Question 58Physics· Geometrical Optics

    A thin plano convex lens made of glass of refractive index 1.5 is immersed in a liquid of refractive index 1.2 . When the plane side of the lens is silver coated for complete reflection, the lens immersed in the liquid behaves like a concave mirror of focal length 0.2 m . The radius of curvature of the curved surface of the lens is :-

    1. Option A:

      0.15m

    2. Option B:

      0.10m

    3. Option C:

      0.20m

    4. Option D:

      0.25m

  59. Question 59Physics· Simple Harmonic Motion

    A particle is executing simple harmonic motion with time period 2 s and amplitude 1 cm . If D and d are the total distance and displacement covered by the particle in 12.5 s , then D/d is :-

    1. Option A:

      15/4

    2. Option B:

      25

    3. Option C:

      10

    4. Option D:

      16/5

  60. Question 60Physics· Gravitation

    A satellite is launched into a circular orbit of radius ' R ' around the earth. A second statellite is launched into an orbit of radius 1.03 R . The time period of revolution of the second satellite is larger than the first one approximately by :-

    1. Option A:

      3%3 \%

    2. Option B:

      4.5%4.5 \%

    3. Option C:

      9%9 \%

    4. Option D:

      2.5%2.5 \%

  61. Question 61Physics· Geometrical Optics

    A plano-convex lens having radius of curvature of first surface 2 cm exhibits focal length of f1f_{1} in air. Another plano-convex lens with first surface radius of curvature 3 cm has focal length of f2\mathrm{f}_{2} when it is immersed in a liquid of refractive index 1.2. If both the lenses are made of same glass of refractive index 1.5, the ratio of f1\mathrm{f}_{1} and f2\mathrm{f}_{2} will be :-

    1. Option A:

      3:53: 5

    2. Option B:

      1:31: 3

    3. Option C:

      1:21: 2

    4. Option D:

      2:32: 3

  62. Question 62Physics· Alternating Current

    An alternating current is given by

    I=IAsin⁡ωt+IBcos⁡ωt\mathrm{I}=\mathrm{I}_{\mathrm{A}} \sin \omega \mathrm{t}+\mathrm{I}_{\mathrm{B}} \cos \omega \mathrm{t}.

    The r.m.s. current will be :-

    1. Option A:

      IA2+IB2\sqrt{\mathrm{I}_{\mathrm{A}}^{2}+\mathrm{I}_{\mathrm{B}}^{2}}

    2. Option B:

      IA2+IB22\frac{\sqrt{\mathrm{I}_{\mathrm{A}}^{2}+\mathrm{I}_{\mathrm{B}}^{2}}}{2}

    3. Option C:

      IA2+IB22\sqrt{\frac{\mathrm{I}_{\mathrm{A}}^{2}+\mathrm{I}_{\mathrm{B}}^{2}}{2}}

    4. Option D:

      ∣IA+IB∣2\frac{\left|I_{A}+I_{B}\right|}{\sqrt{2}}

  63. Question 63Physics· Atomic Physics

    An electron of mass ' mm ' with an initial velocity v→=v0i^(v0>0)\overrightarrow{\mathrm{v}}=\mathrm{v}_{0} \hat{\mathrm{i}}\left(\mathrm{v}_{0}>0\right) \quad enters an electric field E→=−E0k^\overrightarrow{\mathrm{E}}=-\mathrm{E}_{0} \hat{\mathrm{k}}. If the initial de Broglie wavelength is λ0\lambda_{0}, the value after time tt would be :-

    1. Option A:

      λ01+e2E02t2 m2v02\frac{\lambda_{0}}{\sqrt{1+\frac{\mathrm{e}^{2} \mathrm{E}_{0}^{2} \mathrm{t}^{2}}{\mathrm{~m}^{2} \mathrm{v}_{0}^{2}}}}

    2. Option B:

      λ01−e2E02t2m2v02\frac{\lambda_{0}}{\sqrt{1-\frac{e^{2} E_{0}^{2} t^{2}}{m^{2} v_{0}^{2}}}}

    3. Option C:

      λ0\lambda_{0}

    4. Option D:

      λ01+e2E02t2m2v02\lambda_{0} \sqrt{1+\frac{e^{2} E_{0}^{2} t^{2}}{m^{2} v_{0}^{2}}}

  64. Question 64Physics· Capacitors and R-C Circuits

    A parallel plate capacitor was made with two rectangular plates, each with a length of

    l=3 cml=3 \mathrm{~cm} and breath of b=1 cm\mathrm{b}=1 \mathrm{~cm}. The distance

    between the plates is 3μ m3 \mu \mathrm{~m}. Out of the following, which are the ways

    to increase the capacitance by a factor of 10 ?

    A. l=30 cm, b=1 cm, d=1μ ml=30 \mathrm{~cm}, \mathrm{~b}=1 \mathrm{~cm}, \mathrm{~d}=1 \mu \mathrm{~m}

    B. l=3 cm, b=1 cm, d=30μ ml=3 \mathrm{~cm}, \mathrm{~b}=1 \mathrm{~cm}, \mathrm{~d}=30 \mu \mathrm{~m}

    C. l=6 cm, b=5 cm, d=3μ ml=6 \mathrm{~cm}, \mathrm{~b}=5 \mathrm{~cm}, \mathrm{~d}=3 \mu \mathrm{~m}

    D. l=1 cm, b=1 cm, d=10μ ml=1 \mathrm{~cm}, \mathrm{~b}=1 \mathrm{~cm}, \mathrm{~d}=10 \mu \mathrm{~m}

    E. l=5 cm, b=2 cm, d=1μ ml=5 \mathrm{~cm}, \mathrm{~b}=2 \mathrm{~cm}, \mathrm{~d}=1 \mu \mathrm{~m}

    1. Option A:

      C and E only

    2. Option B:

      B and D only

    3. Option C:

      A only

    4. Option D:

      C only

  65. Question 65Physics· Work, Power & Energy

    A force F=α+βx2F=\alpha+\beta x^{2} acts on an object in the x -direction. The work done by the force is 5 J when the object is displaced by 1 m . If the constant α=1 N\alpha=1 \mathrm{~N} then β\beta will be

    1. Option A:

      15 N/m215 \mathrm{~N} / \mathrm{m}^{2}

    2. Option B:

      10 N/m210 \mathrm{~N} / \mathrm{m}^{2}

    3. Option C:

      12 N/m212 \mathrm{~N} / \mathrm{m}^{2}

    4. Option D:

      8 N/m28 \mathrm{~N} / \mathrm{m}^{2}

  66. Question 66Physics· Thermodynamics

    An ideal gas goes from an initial state to final state. During the process, the pressure of gas increases linearly with temperature.

    A. The work done by gas during the process is zero.

    B. The heat added to gas is different from change in its internal energy.

    C. The volume of the gas is increased.

    D. The internal energy of the gas is increased.

    E. The process is isochoric (constant volume process)

    1. Option A:

      A, B, C, D Only

    2. Option B:

      A, D, E Only

    3. Option C:

      E Only

    4. Option D:

      A, C Only

  67. Question 67Physics· Electrostatics

    A square loop of sides a=1 m\mathrm{a}=1 \mathrm{~m} is held normally in front of a point charge q=1C\mathrm{q}=1 \mathrm{C}. The flux of the electric field through the shaded region is 5p×1ε0Nm2C\frac{5}{\mathrm{p}} \times \frac{1}{\varepsilon_{0}} \frac{\mathrm{Nm}^{2}}{\mathrm{C}}, where the value of p is \qquad

    images

    Question 67 figure
  68. Question 68Physics· Units, Dimensions & Error Analysis

    The least count of a screw guage is 0.01 mm . If the pitch is increased by 75%75 \% and number of divisions on the circular scale is reduced by 50%50 \%, the new least count will be \qquad ×10−3 mm\times 10^{-3} \mathrm{~mm}.

  69. Question 69Physics· Current Electricity

    A wire of resistance 9Ω9 \Omega is bent to form an equilateral triangle. Then the equivalent resistance across any two vertices will be \qquad ohm.

  70. Question 70Physics· Moving Charges and Magnetic Field

    A current of 5 A exists in a square loop of side 12 m\frac{1}{\sqrt{2}} \mathrm{~m}.

    Then the magnitude of the magnetic field BB at the centre of the square loop will be

    p×10−6 T\mathrm{p} \times 10^{-6} \mathrm{~T}. where, value of p is \qquad .[0pt]

    [Take μ0=4π×10−7 T mA−1\mu_{0}=4 \pi \times 10^{-7} \mathrm{~T} \mathrm{~mA}^{-1} ].

  71. Question 71Physics· Kinetic Theory of Gases

    The temperature of 1 mole of an ideal monoatomic gas is increased by 50∘C50^{\circ} \mathrm{C} at constant pressure. The total heat added and change in internal energy are E1E_{1} and E2E_{2}, respectively. If E1E2=x9\frac{E_{1}}{E_{2}}=\frac{x}{9} then the value of xx is \qquad .

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JEE Main 2025 — 24 January, Morning Shift — Questions with Answer Key & Solutions · DhiX AI