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Physics · Units, Dimensions & Error Analysis

JEE Main 2025 — 24 January, Morning Shift — Question 50

For an experimental expression y=32.3×112527.4\mathrm{y}=\frac{32.3 \times 1125}{27.4}, where all the digits are significant. Then to report the value of yy we should write :-

  1. Option A:

    y=1326.2y=1326.2

  2. Option B:

    y=1326.19y=1326.19

  3. Option C:

    y=1326.186y=1326.186

  4. Option D:

    y=1330y=1330

    Correct

Answer: D

Step-by-step solution

y=32.3×112527.4=1326.186\mathrm{y}=\frac{32.3 \times 1125}{27.4}=1326.186

Last significant digits are 3 in operands so results should rounded off to 3 digits.

∴y=1330\therefore \mathrm{y}=1330

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
24 January, Morning Shift
Subject
Physics
Chapter
Units, Dimensions & Error Analysis
Topic
Significant Figures and Error Analysis

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