JEE Main 2025 · previous year paper

JEE Main 2025 — 28 January, Evening Shift

68 questions with the verified answer key. Open any question for its step-by-step solution.

  1. Question 1Mathematics· Probability

    Bag B1B_{1} contains 6 white and 4 blue balls, Bag B2B_{2} contains 4 white and 6 blue balls, and BagB3\mathrm{Bag} \mathrm{B}_{3} contains 5 white and 5 blue balls. One of the bags is selected at random and a ball is drawn from it. If the ball is white, then the probability, that the ball is drawn from Bag⁡B2\operatorname{Bag} \mathrm{B}_{2}, is :

    1. Option A:

      13\frac{1}{3}

    2. Option B:

      415\frac{4}{15}

    3. Option C:

      23\frac{2}{3}

    4. Option D:

      25\frac{2}{5}

  2. Question 2Mathematics· Straight lines

    Let A,B,C\mathrm{A}, \mathrm{B}, \mathrm{C} be three points in xy-plane, whose position vector are given by 3i^+j^,i^+3j^\sqrt{3} \hat{i}+\hat{j}, \hat{i}+\sqrt{3} \hat{j} and ai^+(1−a)j^a \hat{i}+(1-a) \hat{j} respectively with respect to the origin O. If the distance of the point C from the line bisecting the angle between the vectors OA→\overrightarrow{\mathrm{OA}} and OB→\overrightarrow{\mathrm{OB}} is 92\frac{9}{\sqrt{2}}, then the sum of all the possible values of a is :

    1. Option A:

      1

    2. Option B:

      9/29 / 2

    3. Option C:

      0

    4. Option D:

      2

  3. Question 3Mathematics· Vector Algebra

    If the components of a→=αi^+βj^+γk^\overrightarrow{\mathrm{a}}=\alpha \hat{\mathrm{i}}+\beta \hat{\mathrm{j}}+\gamma \hat{\mathrm{k}} along and perpendicular to b→=3i^+j^−k^\overrightarrow{\mathrm{b}}=3 \hat{\mathrm{i}}+\hat{\mathrm{j}}-\hat{\mathrm{k}} respectively, are 1611(3i^+j^−k^)\frac{16}{11}(3 \hat{\mathrm{i}}+\hat{\mathrm{j}}-\hat{\mathrm{k}}) and 111(−4i^−5j^−17k^)\frac{1}{11}(-4 \hat{\mathrm{i}}-5 \hat{\mathrm{j}}-17 \hat{\mathrm{k}}), then α2+β2+γ2\alpha^{2}+\beta^{2}+\gamma^{2} is equal to :

    1. Option A:

      23

    2. Option B:

      18

    3. Option C:

      16

    4. Option D:

      26

  4. Question 4Mathematics· Quadratic Equations

    If α+iβ\alpha+i \beta and γ+iδ\gamma+i \delta are the roots of x2−(3−2i)x−(2i−2)=0,i=−1x^{2}-(3-2 i) x-(2 i-2)=0, i=\sqrt{-1}, then αγ+βδ\alpha \gamma+\beta \delta is

    equal to :

    1. Option A:

      6

    2. Option B:

      2

    3. Option C:

      −2-2

    4. Option D:

      −6-6

  5. Question 5Mathematics· Ellipse

    If the midpoint of a chord of the ellipse x29+y24=1\frac{x^{2}}{9}+\frac{y^{2}}{4}=1 is (2,4/3)(\sqrt{2}, 4 / 3), and the length of the chord is 2α3\frac{2 \sqrt{\alpha}}{3}, then α\alpha is :

    1. Option A:

      18

    2. Option B:

      22

    3. Option C:

      26

    4. Option D:

      20

  6. Question 6Mathematics· Probability

    Let SS be the set of all the words that can be formed by arranging all the letters of the word GARDEN. From the set S , one word is selected at random. The probability that the selected word will NOT have vowels in alphabetical order is :

    1. Option A:

      14\frac{1}{4}

    2. Option B:

      23\frac{2}{3}

    3. Option C:

      13\frac{1}{3}

    4. Option D:

      12\frac{1}{2}

  7. Question 7Mathematics· Definite Integration

    Let ff be a real valued continuous function defined on the positive real axis such that g(x)=∫0xtf(t)dt\mathrm{g}(\mathrm{x})=\int_{0}^{\mathrm{x}} \mathrm{t} f(\mathrm{t}) \mathrm{dt}. If g(x3)=x6+x7g\left(x^{3}\right)=x^{6}+x^{7}, then value of ∑r=115f(r3)\sum_{r=1}^{15} f\left(r^{3}\right) is :

    1. Option A:

      320

    2. Option B:

      340

    3. Option C:

      270

    4. Option D:

      310

  8. Question 8Mathematics· 3D Geometry

    The square of the distance of the point (157,327,7)\left(\frac{15}{7}, \frac{32}{7}, 7\right) from the line x+13=y+35=z+57\frac{x+1}{3}=\frac{y+3}{5}=\frac{z+5}{7} in the direction of the vector i^+4j^+7k^\hat{i}+4 \hat{j}+7 \hat{k} is :

    1. Option A:

      54

    2. Option B:

      41

    3. Option C:

      66

    4. Option D:

      44

  9. Question 9Mathematics· Area under the Curves

    The area of the region bounded by the curves x(1+y2)=1\mathrm{x}\left(1+\mathrm{y}^{2}\right)=1 and y2=2x\mathrm{y}^{2}=2 \mathrm{x} is :

    1. Option A:

      2(π2−13)2\left(\frac{\pi}{2}-\frac{1}{3}\right)

    2. Option B:

      π4−13\frac{\pi}{4}-\frac{1}{3}

    3. Option C:

      π2−13\frac{\pi}{2}-\frac{1}{3}

    4. Option D:

      12(π2−13)\frac{1}{2}\left(\frac{\pi}{2}-\frac{1}{3}\right)

  10. Question 10Mathematics· Matrices
    Let   A=[12−201] and   P=[cos⁡θ−sin⁡θsin⁡θcos⁡θ],θ>0.\text{Let\; } A = \begin{bmatrix} \frac{1}{\sqrt{2}} & -2 \\ 0 & 1 \end{bmatrix} \text{ and\; } P = \begin{bmatrix} \cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}, \theta > 0. If   B=PAPT,C=PTB10P   and   the   sum   of   the   diagonal   elements   of   C   is   mn\text{If\; } B = PAP^T, C = P^T B^{10} P\; \text{ and\; the\; sum\; of\; the\; diagonal\; elements\; of\; } C\; \text{ is\; } \frac{m}{n}  where   gcd(m,n)=1, then   m+n   is:\text{ where\; } \text{gcd}(m, n) = 1, \text{ then\; } m + n\; \text{ is:}
    1. Option A:

      65

    2. Option B:

      127

    3. Option C:

      258

    4. Option D:

      2049

  11. Question 11Mathematics· Indefinite Integration

    If f(x)=∫1x1/4(1+x1/4)dx,f(0)=−6f(\mathrm{x})=\int \frac{1}{\mathrm{x}^{1 / 4}\left(1+\mathrm{x}^{1 / 4}\right)} \mathrm{dx}, f(0)=-6, then f(1)f(1) is equal to :

    1. Option A:

      log⁡e2+2\log _{e} 2+2

    2. Option B:

      4(log⁡e2−2)4\left(\log _{\mathrm{e}} 2-2\right)

    3. Option C:

      2−log⁡e22-\log _{\mathrm{e}} 2

    4. Option D:

      4(log⁡e2+2)4\left(\log _{e} 2+2\right)

  12. Question 12Mathematics· Definite Integration

    Let f:R→R\mathrm{f}: \mathrm{R} \rightarrow \mathrm{R} be a twice differentiable function such that f(2)=1f(2)=1. If F(x)=xf(x)\mathrm{F}(\mathrm{x})=\mathrm{x} f(\mathrm{x}) for all x∈R\mathrm{x} \in \mathrm{R}, ∫02xF′(x)dx=6\int_{0}^{2} x F^{\prime}(x) d x=6 and ∫02x2F′′(x)dx=40\int_{0}^{2} x^{2} F^{\prime \prime}(x) d x=40, then F′(2)+∫02F(x)dxF^{\prime}(2)+\int_{0}^{2} F(x) d x is equal to :

    1. Option A:

      11

    2. Option B:

      15

    3. Option C:

      9

    4. Option D:

      13

  13. Question 13Mathematics· Sequence and Series

    For positive integers nn, if 4an=(n2+5n+6)4 a_{n}=\left(n^{2}+5 n+6\right) and Sn=∑k=1n(1ak)\mathrm{S}_{\mathrm{n}}=\sum_{\mathrm{k}=1}^{\mathrm{n}}\left(\frac{1}{\mathrm{a}_{\mathrm{k}}}\right), then the value of 507 S2025507 \mathrm{~S}_{2025} is :

    1. Option A:

      540

    2. Option B:

      1350

    3. Option C:

      675

    4. Option D:

      135

  14. Question 14Mathematics· Functions

    Let f:[0,3]→f:[0,3] \rightarrow A be defined by f(x)=2x3−15x2+36x+7f(x)=2 x^{3}-15 x^{2}+36 x+7 and g:[0,∞)→Bg:[0, \infty) \rightarrow B be defined by g(x)=x2025x2025+1g(x)=\frac{x^{2025}}{x^{2025}+1}. If both the functions are onto and S={x∈Z:x∈AS=\{x \in \mathbf{Z}: x \in A or x∈B}x \in B\}, then n(S)n(S) is equal to :

    1. Option A:

      30

    2. Option B:

      36

    3. Option C:

      29

    4. Option D:

      31

  15. Question 15Mathematics· Functions

    Let [x][x] denote the greatest integer less than or equal to xx. Then domain of f(x)=sec⁡−1(2[x]+1)f(x)=\sec ^{-1}(2[x]+1) is :

    1. Option A:

      (−∞,−1]∪[0,∞)(-\infty,-1] \cup[0, \infty)

    2. Option B:

      (−∞,∞)(-\infty,\infty)

    3. Option C:

      (−∞,−1]∪[1,∞)(-\infty,-1] \cup[1, \infty)

    4. Option D:

      (−∞,∞]−{0}(-\infty, \infty]-\{0\}

  16. Question 16Mathematics· Trigonometry Ratios and Identities

    If ∑r=113{1sin⁡(π4+(r−1)π6)sin⁡(π4+rπ6)}=a3+b\sum_{r=1}^{13}\left\{\frac{1}{\sin \left(\frac{\pi}{4}+(r-1) \frac{\pi}{6}\right) \sin \left(\frac{\pi}{4}+\frac{r \pi}{6}\right)}\right\}=a \sqrt{3}+b, a,b∈Z\mathrm{a}, \mathrm{b} \in \mathbf{Z}, then a2+b2\mathrm{a}^{2}+\mathrm{b}^{2} is equal to :

    1. Option A:

      10

    2. Option B:

      2

    3. Option C:

      8

    4. Option D:

      4

  17. Question 17Mathematics· Straight lines

    Two equal sides of an isosceles triangle are along −x+2y=4-x+2 y=4 and x+y=4x+y=4. If mm is the slope of its third side, then the sum of all possible distinct values of m , is :

    1. Option A:

      −6-6

    2. Option B:

      12

    3. Option C:

      6

    4. Option D:

      −210-2 \sqrt{10}

  18. Question 18Mathematics· Binomial Theorem

    Let the coefficients of three consecutive terms TrT_{r}, Tr+1T_{r+1} and Tr+2T_{r+2} in the binomial expansion of (a+b)12(a+b)^{12} be in a G.P. and let pp be the number of all possible values of rr. Let qq be the sum of all rational terms in the binomial expansion of (34+43)12(\sqrt[4]{3}+\sqrt[3]{4})^{12}. Then p+q\mathrm{p}+\mathrm{q} is equal to :

    1. Option A:

      283

    2. Option B:

      295

    3. Option C:

      287

    4. Option D:

      299

  19. Question 19Mathematics· Hyperbola

    If AA and BB are the points of intersection of the circle x2+y2−8x=0\mathrm{x}^{2}+\mathrm{y}^{2}-8 \mathrm{x}=0 and the hyperbola x29−y24=1\frac{x^{2}}{9}-\frac{y^{2}}{4}=1 and a point PP moves on the line 2x−3y+4=02 x-3 y+4=0, then the centroid of △PAB\triangle P A B lies on the line :

    1. Option A:

      4x−9y=124 x-9 y=12

    2. Option B:

      x+9y=36x+9 y=36

    3. Option C:

      9x−9y=329 x-9 y=32

    4. Option D:

      6x−9y=206 x-9 y=20

  20. Question 20Mathematics· Functions

    Let f:R−{0}→(−∞,1)f: \mathbf{R}-\{0\} \rightarrow(-\infty, 1) be a polynomial of degree 2, satisfying f(x)f(1x)=f(x)+f(1x)f(\mathrm{x}) f\left(\frac{1}{\mathrm{x}}\right)=f(\mathrm{x})+f\left(\frac{1}{\mathrm{x}}\right).

    If f( K)=−2 Kf(\mathrm{~K})=-2 \mathrm{~K}, then the sum of squares of all possible values of K is :

    1. Option A:

      1

    2. Option B:

      6

    3. Option C:

      7

    4. Option D:

      9

  21. Question 21Mathematics· Permutations and Combinations

    The number of natural numbers, between 212 and 999 , such that the sum of their digits is 15 , is

  22. Question 22Mathematics· Limits, Continuity and Differentiability

    Let f(x)=lim⁡n→∞∑r=0n(tan⁡(x/2r+1)+tan⁡3(x/2r+1)1−tan⁡2(x/2r+1))f(\mathrm{x})=\lim _{\mathrm{n} \rightarrow \infty} \sum_{\mathrm{r}=0}^{\mathrm{n}}\left(\frac{\tan \left(\mathrm{x} / 2^{\mathrm{r}+1}\right)+\tan ^{3}\left(\mathrm{x} / 2^{\mathrm{r}+1}\right)}{1-\tan ^{2}\left(\mathrm{x} / 2^{\mathrm{r}+1}\right)}\right). Then lim⁡x→0ex−ef(x)(x−f(x))\lim _{x \rightarrow 0} \frac{\mathrm{e}^{\mathrm{x}}-\mathrm{e}^{f(\mathrm{x})}}{(\mathrm{x}-f(\mathrm{x}))} is equal to

  23. Question 23Mathematics· Sequence and Series

    The interior angles of a polygon with n sides, are in an A.P. with common difference 6∘6^{\circ}. If the largest interior angle of the polygon is 219∘219^{\circ}, then nn is equal to -.

  24. Question 24Mathematics· Parabola

    Let AA and BB be the two points of intersection of the line y+5=0y+5=0 and the mirror image of the parabola y2=4xy^{2}=4 x with respect to the line x+y+4=0x+y+4=0. If dd denotes the distance between A and B , and a denotes the area of △SAB\triangle \mathrm{SAB}, where S is the focus of the parabola y2=4xy^{2}=4 x, then the value of (a+d)(a+d) is

  25. Question 25Mathematics· Differential Equations

    If y=y(x)y=y(x) is the solution of the differential equation, 4−x2dydx=((sin⁡−1(x2))2−y)sin⁡−1(x2)\sqrt{4-x^{2}} \frac{d y}{d x}=\left(\left(\sin ^{-1}\left(\frac{x}{2}\right)\right)^{2}-y\right) \sin ^{-1}\left(\frac{x}{2}\right), −2≤x≤2,y(2)=(π2−84)-2 \leq x \leq 2, y(2)=\left(\frac{\pi^{2}-8}{4}\right), then y2(0)y^{2}(0) is equal to

  26. Question 26Chemistry· Chemical Kinetics

    consider the elementary reaction

    A(g)+B(g)→C(g)+D(g)\mathrm{A}(\mathrm{g})+\mathrm{B}(\mathrm{g}) \rightarrow \mathrm{C}(\mathrm{g})+\mathrm{D}(\mathrm{g})

    If the volume of reaction mixture is suddenly reduced to 13\frac{1}{3} of its initial volume, the reaction rate

    will become ' xx ' times of the original reaction rate. The value of xx is :

    1. Option A:

      19\frac{1}{9}

    2. Option B:

      9

    3. Option C:

      13\frac{1}{3}

    4. Option D:

      3

  27. Question 27Chemistry· d and f Block Elements

    The amphoteric oxide among V2O3, V2O4\mathrm{V}_{2} \mathrm{O}_{3}, \mathrm{~V}_{2} \mathrm{O}_{4} and V2O5\mathrm{V}_{2} \mathrm{O}_{5} upon reaction with alkali leads to formation of an oxide anion. The oxidation state of V in the oxide anion is :

    1. Option A:

      3

    2. Option B:

      7

    3. Option C:

      5

    4. Option D:

      4

  28. Question 28Chemistry· Biomolecules

    Match List-I with List-II

    List-I (Saccharides)List_II (Glycosidic-linkages found)
    (A) Sucroseα\alpha 1-4
    (B) Maltose(II) α1−4\alpha 1-4 and α1−6\alpha 1-6
    (C) Lactose(III) α1−β2\alpha 1-\beta 2
    (D) Amylopectin(IV) β1−4\beta 1-4

    Choose the correct answer from the options given below :

    1. Option A:

      (A)-(III), (B)-(I), (C)-(IV), (D)-(II)

    2. Option B:

      (A)-(IV), (B)-(II), (C)-(I), (D)-(III)

    3. Option C:

      (A)-(II), (B)-(IV), (C)-(III), (D)-(I)

    4. Option D:

      (A)-(I), (B)-(II), (C)-(III), (D)-(IV)

  29. Question 29Chemistry· Hydrocarbons

    Identify product [A],[B][\mathrm{A}],[\mathrm{B}] and [C][\mathrm{C}] in the following reaction sequence :

    figure

    1. Option A:

      [A]:CH3−CH=CH2,[ B]:CH3CHO,[\mathrm{A}]: \mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2,[\mathrm{~B}]: \mathrm{CH}_3 \mathrm{CHO}, [C]:HCHO[\mathrm{C}]: \mathrm{HCHO}

    2. Option B:
      Option B figure
    3. Option C:

      [A]:CH3−CH=CH2,[ B]:CH3CHO,[C]:CH3CH2OH\begin{aligned} & {[\mathrm{A}]: \mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2,[\mathrm{~B}]: \mathrm{CH}_3 \mathrm{CHO},} \\ & {[\mathrm{C}]: \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}}\end{aligned}

    4. Option D:

      [A]:CH3CH2CH3,[ B]:CH3CHO,[C]:HCHO[\mathrm{A}]: \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_3,[\mathrm{~B}]: \mathrm{CH}_3 \mathrm{CHO},[\mathrm{C}]: \mathrm{HCHO}

  30. Question 30Chemistry· Ionic Equilibrium

    Arrange the following in increasing order of solubility product : Ca(OH)2,AgBr,PbS,HgS\mathrm{Ca}(\mathrm{OH})_{2}, \mathrm{AgBr}, \mathrm{PbS}, \mathrm{HgS}

    1. Option A:

      PbS<HgS<Ca(OH)2<AgBr\mathrm{PbS}<\mathrm{HgS}<\mathrm{Ca}(\mathrm{OH})_{2}<\mathrm{AgBr}

    2. Option B:

      HgS<PbS<AgBr<Ca(OH)2\mathrm{HgS}<\mathrm{PbS}<\mathrm{AgBr}<\mathrm{Ca}(\mathrm{OH})_{2}

    3. Option C:

      Ca(OH)2<AgBr<HgS<PbS\mathrm{Ca}(\mathrm{OH})_{2}<\mathrm{AgBr}<\mathrm{HgS}<\mathrm{PbS}

    4. Option D:

      HgS<AgBr<PbS<Ca(OH)2\mathrm{HgS}<\mathrm{AgBr}<\mathrm{PbS}<\mathrm{Ca}(\mathrm{OH})_{2}

  31. Question 31Chemistry· Practical Inorganic chemistry (Qualitative Analysis)

    The purification method based on the following physical transformation is :

    Solid(X)→ Heat  Vapour (X)→ Cool \underset{(\mathrm{X})}{\mathrm{Solid}} \xrightarrow{\text { Heat }} \underset{(\mathrm{X})}{\text { Vapour }} \xrightarrow{\text { Cool }} Solid

    1. Option A:

      Sublimation

    2. Option B:

      Distillation

    3. Option C:

      Crystallization

    4. Option D:

      Extraction

  32. Question 32Chemistry· Biomolecules

    Identify correct conversion during acidic hydrolysis from the following :

    (A) starch gives galactose.

    (B) cane sugar gives equal amount of glucose and fructose.

    (C) milk sugar gives glucose and galactose.

    (D) amylopectin gives glucose and fructose.

    (E) amylose gives only glucose.

    Choose the correct answer from the options given below :

    1. Option A:

      (C), (D) and (E) only

    2. Option B:

      (A), (B) and (C) only

    3. Option C:

      (B), (C) and (E) only

    4. Option D:

      (B), (C) and (D) only

  33. Question 33Chemistry· Thermodynamics & Thermochemistry

    figure

    An ideal gas undergoes a cyclic transformation starting from the point A and coming back to the same point by tracing the path A→B→C→D→A\mathrm{A} \rightarrow \mathrm{B} \rightarrow \mathrm{C} \rightarrow \mathrm{D} \rightarrow \mathrm{A} as shown in the three cases above. Choose the correct option regarding ΔU\Delta \mathrm{U}.

    1. Option A:

      ΔU(\Delta \mathrm{U}( Case-III) >ΔU(>\Delta \mathrm{U}( Case-II )>ΔU()>\Delta \mathrm{U}( Case-I)

    2. Option B:

      ΔU(\Delta \mathrm{U}( Case-I) >ΔU(>\Delta \mathrm{U}( Case-II )>ΔU()>\Delta \mathrm{U}( Case-III ))

    3. Option C:

      ΔU(\Delta \mathrm{U}( Case-I )>ΔU()>\Delta \mathrm{U}( Case-III )>ΔU()>\Delta \mathrm{U}( Case-II ))

    4. Option D:

      ΔU(\Delta \mathrm{U}( Case-I )=ΔU()=\Delta \mathrm{U}( Case-II )=ΔU()=\Delta \mathrm{U}( Case-III ))

  34. Question 34Chemistry· Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

    Concentrated nitric acid is labelled as 75%75 \% by mass. The volume in mL of the solution which contains 30 g of nitric acid is___.

    Given : Density of nitric acid solution is 1.25 g/mL1.25 \mathrm{~g} / \mathrm{mL}

    1. Option A:

      45

    2. Option B:

      55

    3. Option C:

      32

    4. Option D:

      40

  35. Question 35Chemistry· Coordination Compounds

    Match List-I with List-II.

    List-I (Complex)List-II (Hybridisation of central metal ion)
    (A) [CoF6]3−{{\left[ \text{Co}{{\text{F}}_{6}} \right]}^{3-}}(I) d2sp 3{{\text{d}}^{2}}\text{sp}{{~}^{3}}
    (B) [NiCl4]2−{{\left[ \text{NiC}{{\text{l}}_{4}} \right]}^{2-}}(II) sp3\text{s}{{\text{p}}^{3}}
    (C) [Co(NH3)6]3+{{\left[ \text{Co}{{\left( \text{N}{{\text{H}}_{3}} \right)}_{6}} \right]}^{3+}}(III) sp3  ⁣ ⁣  ⁣ ⁣ d2\text{s}{{\text{p}}^{3}}\text{ }\!\!~\!\!\text{ }{{\text{d}}^{2}}
    (D) [Ni(CN)4]2−{{\left[ \text{Ni}{{(\text{CN})}_{4}} \right]}^{2-}}(IV) dsp2\text{ds}{{\text{p}}^{2}}

    Choose the correct answer from the options given below :

    1. Option A:

      (A)-(I), (B)-(IV), (C)-(III), (D)-(II)

    2. Option B:

      (A)-(III), (B)-(II), (C)-(I), (D)-(IV)

    3. Option C:

      (A)-(I), (B)-(II), (C)-(III), (D)-(IV)

    4. Option D:

      (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

  36. Question 36Chemistry· Carboxylic Acids and Derivatives

    The total number of compounds from below when treated with hot KMnO4\mathrm{KMnO}_{4} giving benzoic acid is :

    figure

    1. Option A:

      3

    2. Option B:

      4

    3. Option C:

      6

    4. Option D:

      5

  37. Question 37Chemistry· Alkyl and Aryl Halides

    The major product of the following reaction is :

    figure

    1. Option A:

      6-Phenylhepta-2,4-diene

    2. Option B:

      2-Phenylhepta-2,5-diene

    3. Option C:

      6-Phenylhepta-3,5-diene

    4. Option D:

      2-Phenylhepta-2,4-diene

  38. Question 38Chemistry· Periodicity of Elements and Periodic Properties

    Given below are two statements, one is labelled as Statement I and the other is labelled as Statement II.

    Statement I : According to the Law of Octaves, the elements were arranged in the increasing order of their atomic number.

    Statement II : Meyer observed a periodically repeated pattern upon plotting physical properties of certain elements against their respective atomic numbers.

    In the light of the above statements, choose the correct answer from the options given below :

    1. Option A:

      Statement I is false but Statement II is true

    2. Option B:

      Both Statement I and Statement II are true

    3. Option C:

      Statement I is true but Statement II is false

    4. Option D:

      Both Statement I and Statement II are false

  39. Question 39Chemistry· Nitrogen Containing Organic Compounds

    Identify correct statements :

    (A) Primary amines do not give diazonium salts when treated with NaNO2\mathrm{NaNO}_{2} in acidc condition.

    (B) Aliphatic and aromatic primary amines on heating wth CHCl3\mathrm{CHCl}_{3} and ethanolic KOH form carbylamines.

    (C) Secondary and tertiary amines also give carbylamine test.

    (D) Benzenesulfonyl chloride is known as Hinsberg's reagent.

    (E) Tertiary amines reacts with benzenesulfonyl chloride very easily.

    Choose the correct answer from the options given below :

    1. Option A:

      (B) and (D) only

    2. Option B:

      (A) and (B) only

    3. Option C:

      (D) and (E) only

    4. Option D:

      (B) and (C) only

  40. Question 40Chemistry· Isomerism

    Given below are two statements : one is labelled as Statement I and the other is labelled as Statement II :

    Statement (I) :

    structure

    are isomeric compounds.

    Statement (II) :

    structure

    and

    structure

    are functional group isomers.

    In the light of the above statements, choose the correct answer from the options given below :

    1. Option A:

      Both Statement I and Statement II are false

    2. Option B:

      Both Statement I and Statement II are true

    3. Option C:

      Statement I is true but Statement II is false

    4. Option D:

      Statement I is false but Statement II is true

  41. Question 41Chemistry· p-Block Elements (Group 15-18)

    Identify the inorganic sulphides that are yellow in colour :

    (A) (NH4)2 S\left(\mathrm{NH}_{4}\right)_{2} \mathrm{~S}

    (B) PbS

    (C) CuS

    (D) As2 S3\mathrm{As}_{2} \mathrm{~S}_{3}

    (E) As2 S5\mathrm{As}_{2} \mathrm{~S}_{5}

    Choose the correct answer from the options given below :

    1. Option A:

      (A) and (C) only

    2. Option B:

      (A), (D) and (E) only

    3. Option C:

      (A) and (B) only

    4. Option D:

      (D) and (E) only

  42. Question 42Chemistry· d and f Block Elements

    The spin only magnetic moment ( μ\mu ) value (B.M.) of the compound with strongest oxidising power among Mn2O3,TiO\mathrm{Mn}_{2} \mathrm{O}_{3}, \mathrm{TiO} and VO is____B.M. (Nearest integer).

  43. Question 43Chemistry· Thermodynamics & Thermochemistry

    Consider the following data :

    Heat of formation of CO2( g)=−393.5 kJ mol−1\mathrm{CO}_{2}(\mathrm{~g})=-393.5 \mathrm{~kJ} \mathrm{~mol}^{-1}

    Heat of formation of H2O(l)=−286.0 kJ mol−1\mathrm{H}_{2} \mathrm{O}(\mathrm{l})=-286.0 \mathrm{~kJ} \mathrm{~mol}^{-1}

    Heat of combustion of benzene =−3267.0 kJ mol−1=-3267.0 \mathrm{~kJ} \mathrm{~mol}^{-1}

    The heat of formation of benzene is ____ kJmol−1\mathrm{kJ} \mathrm{mol}^{-1}. (Nearest integer)

  44. Question 44Chemistry· Ionic Equilibrium

    Electrolysis of 600 mL aqueous solution of NaCl for 5 min changes the pH of the solution to 12 . The current in Amperes used for the given electrolysis is____ . (Nearest integer).

  45. Question 45Chemistry· d and f Block Elements

    A group 15 element forms dπ−dπ\mathrm{d} \pi-\mathrm{d} \pi bond with transition metals. It also forms hydride, which is a strongest base among the hydrides of other group members that form dπ−dπ\mathrm{d} \pi-\mathrm{d} \pi bond. The atomic number of the element is___ .

  46. Question 46Chemistry· Chemical Bonding

    Total number of molecules/species from following which will be paramagnetic is___.

    O2,O2+,O2−,NO,NO2,CO,K2[NiCl4]\mathrm{O}_{2}, \mathrm{O}_{2}^{+}, \mathrm{O}_{2}^{-}, \mathrm{NO}, \mathrm{NO}_{2}, \mathrm{CO}, \mathrm{K}_{2}\left[\mathrm{NiCl}_{4}\right],

    [Co(NH3)6]Cl3, K2[Ni(CN)4]\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}, \mathrm{~K}_{2}\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]

  47. Question 47Physics· Electromagnetic Induction

    A uniform magnetic field of 0.4 T acts perpendicular to a circular copper disc 20 cm in radius. The disc is having a uniform angular velocity of 10πrads−110 \pi \mathrm{rad} \mathrm{s}^{-1} about an axis through its centre and perpendicular to the disc. What is the protential difference developed between the axis of the disc and the rim ? (π=3.14)(\pi=3.14)

    1. Option A:

      0.0628 V

    2. Option B:

      0.5024 V

    3. Option C:

      0.2512 V

    4. Option D:

      0.1256 V

  48. Question 48Physics· Capacitors and R-C Circuits

    A parallel plate capacitor of capacitance 1μ F1 \mu \mathrm{~F} is charged to a potential difference of 20 V . The distance between plates is 1μ m1 \mu \mathrm{~m}. The energy density between plates of capacitor is :

    1. Option A:

      1.8×103 J/m31.8 \times 10^{3} \mathrm{~J} / \mathrm{m}^{3}

    2. Option B:

      2×10−4 J/m32 \times 10^{-4} \mathrm{~J} / \mathrm{m}^{3}

    3. Option C:

      2×102 J/m32 \times 10^{2} \mathrm{~J} / \mathrm{m}^{3}

    4. Option D:

      1.8×105 J/m31.8 \times 10^{5} \mathrm{~J} / \mathrm{m}^{3}

  49. Question 49Physics· Units, Dimensions & Error Analysis

    Match List-I with List-II

    List-IList-II
    (A) Angular Impulse(I) [M0 L2 T−2]\quad\left[\mathrm{M}^{0} \mathrm{~L}^{2} \mathrm{~T}^{-2}\right]
    (B) Latent Heat(II)[ML2 T−3 A−1]\quad\left[\mathrm{M}\mathrm{L}^{2}\mathrm{~T}^{-3}\mathrm{~A}^{-1}\right]
    (C) Electrical resistivity(III) [ML2 T−1]\left[\mathrm{M} \mathrm{L}^{2} \mathrm{~T}^{-1}\right]
    (D) Electromotive force(IV) [ML3 T−3 A−2]\left[\mathrm{M} \mathrm{L}^{3} \mathrm{~T}^{-3} \mathrm{~A}^{-2}\right]

    Choose the correct one from the options given below:

    1. Option A:

      (A)-(III), (B)-(I), (C)-(IV), (D)-(II)

    2. Option B:

      (A)-(I), (B)-(III), (C)-(IV), (D)-(II)

    3. Option C:

      (A)-(III), (B)-(I), (C)-(II), (D)-(IV)

    4. Option D:

      (A)-(II), (B)-(I), (C)-(IV), (D)-(III)

  50. Question 50Physics· Kinetic Theory of Gases

    The ratio of vapour densities of two gases at the same temperature is 4/25, then the ratio of r.m.s. velocities will be :

    1. Option A:

      25/4

    2. Option B:

      2/5

    3. Option C:

      5/2

    4. Option D:

      4/25

  51. Question 51Physics· Kinetic Theory of Gases

    The kinetic energy of translation of the molecules in 50 g of CO2\mathrm{CO}_{2} gas at 17∘C17^{\circ} \mathrm{C} is :

    1. Option A:

      3986.3 J

    2. Option B:

      4102.8 J

    3. Option C:

      4205.5 J

    4. Option D:

      3582.7 J

  52. Question 52Physics· Geometrical Optics

    In a long glass tube, mixture of two liquids A and B with refractive indices 1.3 and 1.4 respectively, forms a convex refractive meniscus towards A. If an object placed at 13 cm from the vertex of the meniscus in A forms an image with a magnification of '–2' then the radius of curvature of meniscus is :

    1. Option A:

      1 cm

    2. Option B:

      1/3 cm

    3. Option C:

      2/3 cm

    4. Option D:

      4/3 cm

  53. Question 53Physics· Atomic Physics

    The frequency of revolution of the electron in Bohr's orbit varies with n , the principal quantum number as

    1. Option A:

      1n\frac{1}{\mathrm{n}}

    2. Option B:

      1n3\frac{1}{n^{3}}

    3. Option C:

      1n4\frac{1}{\mathrm{n}^{4}}

    4. Option D:

      1n2\frac{1}{\mathrm{n}^{2}}

  54. Question 54Physics· Atomic Physics

    Which of the following phenomena can not be explained by wave theory of light?

    1. Option A:

      Reflection of light

    2. Option B:

      Diffraction of light

    3. Option C:

      Refraction of light

    4. Option D:

      Compton effect

  55. Question 55Physics· Gravitation

    Earth has mass 8 times and radius 2 times that of a planet. If the escape velocity from the earth is 11.2 km/s\mathrm{km} / \mathrm{s}, the escape velocity in km/s\mathrm{km} / \mathrm{s} from the planet will be :

    1. Option A:

      11.2

    2. Option B:

      5.6

    3. Option C:

      2.8

    4. Option D:

      8.4

  56. Question 56Physics· Simple Harmonic Motion

    Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R).

    Assertion (A) : Knowing initial position x0\mathrm{x}_{0} and initial momentum p0p_{0} is enough to determine the position and momentum at any time t for a simple harmonic motion with a given angular frequency ω\omega.

    Reason (R) : The amplitude and phase can be expressed in terms of x0\mathrm{x}_{0} an p0\mathrm{p}_{0}.

    In the light of the above statements, choose the correct answer from the options given below :

    1. Option A:

      Both (A) and (R) are true but (R) is NOT the correct explanation of (A).

    2. Option B:

      (A) is false but (R) is true.

    3. Option C:

      (A) is true but ( R ) is false.

    4. Option D:

      Both (A) and (R) are true and (R) is the correct explanation of (A).

  57. Question 57Physics· Geometrical Optics

    A concave mirror produces an image of an object such that the distance between the object and image is 20 cm . If the magnification of the image is ' -3 ', then the magnitude of the radius of curvature of the mirror is :

    1. Option A:

      3.75cm

    2. Option B:

      3.0cm

    3. Option C:

      7.5cm

    4. Option D:

      15cm

  58. Question 58Physics· Work, Power & Energy

    A body of mass 4 kg is placed on a plane at a point PP having coordinate (3,4)m(3,4) \mathrm{m}. Under the action of force F⃗=(2i^+3j^)N\vec{F}=(2 \hat{i}+3 \hat{j}) N, it moves to a new point QQ having coordinates (6,10)m(6,10) \mathrm{m} in 4 sec . The average power and instantaneous power at the end of 4 sec are in the ratio of :

    1. Option A:

      13:613: 6

    2. Option B:

      6:136: 13

    3. Option C:

      1:21: 2

    4. Option D:

      4:34: 3

  59. Question 59Physics· Moving Charges and Magnetic Field

    An infinite wire has a circular bend of radius a, and carrying a current II as shown in figure. The magnitude of magnetic field at the origin O of the arc is given by :

    Question 59 figure
    1. Option A:

      μ04πIa[π2+1]\frac{\mu_{0}}{4 \pi} \frac{I}{a}\left[\frac{\pi}{2}+1\right]

    2. Option B:

      μ04πIa[3π2+1]\frac{\mu_{0}}{4 \pi} \frac{\mathrm{I}}{\mathrm{a}}\left[\frac{3 \pi}{2}+1\right]

    3. Option C:

      μ02πIa[π2+2]\frac{\mu_{0}}{2 \pi} \frac{I}{a}\left[\frac{\pi}{2}+2\right]

    4. Option D:

      μ04πIa[3π2+2]\frac{\mu_{0}}{4 \pi} \frac{\mathrm{I}}{\mathrm{a}}\left[\frac{3 \pi}{2}+2\right]

  60. Question 60Physics· Rotational Dynamics

    A uniform rod of mass 250 g having length 100 cm is balanced on a sharp edge at 40 cm mark. A mass of 400 g is suspended at 10 cm mark. To maintain the balance of the rod, the mass to be suspended at 90 cm mark, is

    1. Option A:

      300 g

    2. Option B:

      190g

    3. Option C:

      200g

    4. Option D:

      290g

  61. Question 61Physics· Fluid Mechanics

    a 400 g id cube having an edge of length 10 cm floats in water. How much volume of the cube is outside the water? (Given : density of water =1000 kg m−3=1000 \mathrm{~kg} \mathrm{~m}^{-3} )

    1. Option A:

      1400 cm31400 \mathrm{~cm}^{3}

    2. Option B:

      4000 cm34000 \mathrm{~cm}^{3}

    3. Option C:

      400 cm3400 \mathrm{~cm}^{3}

    4. Option D:

      600 cm3600 \mathrm{~cm}^{3}

  62. Question 62Physics· Electromagnetic Waves

    The magnetic field of an E.M. wave is given by B⃗=(32i^+12j^)30sin⁡[ω(t−zc)]\vec{B}=\left(\frac{\sqrt{3}}{2} \hat{i}+\frac{1}{2} \hat{\mathrm{j}}\right) 30 \sin \left[\omega\left(\mathrm{t}-\frac{\mathrm{z}}{\mathrm{c}}\right)\right] (S.I. Units) The corresponding electric field in S.I. units is :

    1. Option A:

      E⃗=(12i^−32j^)30csin⁡[ω(t−zc)]\vec{E}=\left(\frac{1}{2} \hat{i}-\frac{\sqrt{3}}{2} \hat{j}\right) 30 c \sin \left[\omega\left(t-\frac{z}{c}\right)\right]

    2. Option B:

      E→=(34i^+14j^)30cos⁡[ω(t−zc)]\overrightarrow{\mathrm{E}}=\left(\frac{3}{4} \hat{\mathrm{i}}+\frac{1}{4} \hat{\mathrm{j}}\right) 30 \cos \left[\omega\left(\mathrm{t}-\frac{\mathrm{z}}{\mathrm{c}}\right)\right]

    3. Option C:

      E→=(12i^+32j^)30csin⁡[ω(t+zc)]\overrightarrow{\mathrm{E}}=\left(\frac{1}{2} \hat{\mathrm{i}}+\frac{\sqrt{3}}{2} \hat{\mathrm{j}}\right) 30 \mathrm{c} \sin \left[\omega\left(\mathrm{t}+\frac{\mathrm{z}}{\mathrm{c}}\right)\right]

    4. Option D:

      E→=(32i^−12j^)30csin⁡[ω(t+zc)]\overrightarrow{\mathrm{E}}=\left(\frac{\sqrt{3}}{2} \hat{\mathrm{i}}-\frac{1}{2} \hat{\mathrm{j}}\right) 30 \mathrm{c} \sin \left[\omega\left(\mathrm{t}+\frac{\mathrm{z}}{\mathrm{c}}\right)\right]

  63. Question 63Physics· Newton's Laws of Motion

    A balloon and its content having mass MM is moving up with an acceleration ' aa '. The mass that must be released from the content so that the balloon starts moving up with an acceleration ' 3a′3 \mathrm{a}^{\prime} will be : (Take ' g ' as acceleration due to gravity)

    1. Option A:

      3Ma2a−g\frac{3 \mathrm{Ma}}{2 \mathrm{a}-\mathrm{g}}

    2. Option B:

      3Ma2a+g\frac{3 \mathrm{Ma}}{2 \mathrm{a}+\mathrm{g}}

    3. Option C:

      2Ma3a+g\frac{2 \mathrm{Ma}}{3 \mathrm{a}+\mathrm{g}}

    4. Option D:

      2Ma3a−g\frac{2 \mathrm{Ma}}{3 \mathrm{a}-\mathrm{g}}

  64. Question 64Physics· Electromagnetic Induction

    A conducting bar moves on two conducting rails as shown in the figure. A constant magnetic field BB exists into the page. The bar starts to move from the vertex at time t=0t=0 with a constant velocity. If the induced EMF is E∝tnE \propto t^{n}, then value of nn is \qquad ..

    Question 64 figure
  65. Question 65Physics· Electrostatics

    An electric dipole of dipole moment 6×10−6Cm6 \times 10^{-6} \mathrm{Cm} is placed in uniform electric field of magnitude 106 V/m10^{6} \mathrm{~V} / \mathrm{m}. Initially, the dipole moment is parallel to electric field. The work that needs to be done on the dipole to make its dipole moment opposite to the field, will be \qquad J.

  66. Question 66Physics· Fluid Mechanics

    The volume contraction of a solid copper cube of edge length 10 cm , when subjected to a hydraulic pressure of 7×106 Pa7 \times 10^{6} \mathrm{~Pa}, would be \qquad mm3\mathrm{mm}^{3}.

    (Given bulk modulus of copper =1.4×1011Nm−2=1.4 \times 10^{11} \mathrm{Nm}^{-2} )

  67. Question 67Physics· Current Electricity

    The value of current II in the electrical circuit as given below, when potential at A is equal to the potential at B , will be \qquad A.

    Question 67 figure
  68. Question 68Physics· Wave Optics

    A thin transparent film with refractive index 1.4 , is held on circular ring of radius 1.8 cm . The fluid in the film evaporates such that transmission through the film at wavelength 560 nm goes to a minimum every 12 seconds. Assuming that the film is flat on its two sides, the rate of evaporation is \qquad π×10−13 m3/s\pi \times 10^{-13} \mathrm{~m}^{3} / \mathrm{s}.

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