Xg of benzoic acid on reaction with aq. NaHCO 3 release CO 2 that occupied 11.2 L volume at STP. X is g.

Chemistry · Aromatic Compounds

JEE Main 2025 — 24 January, Morning Shift — Question 44

Xg of benzoic acid on reaction with aq. $\mathrm{NaHCO}_{3}$ release $\mathrm{CO}_{2}$ that occupied 11.2 L volume

at STP. X is $\qquad$ g.

Answer: 61

Numerical answer — enter this value.

Step-by-step solution

The reaction is: $\ce{C6H5COOH + NaHCO3 -> C6H5COONa + H2O + CO2}$ At STP, 1 mole of gas occupies 22.4 L. Moles of $\ce{CO2}$ produced = $\frac{11.2}{22.4} = 0.5$ mol. From stoichiometry, 1 mole of benzoic acid produces 1 mole of $\ce{CO2}$ . Moles of benzoic acid = 0.5 mol. Molar mass of benzoic acid ( $\ce{C6H5COOH}$ ) = $7\times12 + 6\times1 + 2\times16 = 122$ g/mol. Mass of benzoic acid = $0.5 \times 122 = 61$ g. Thus, $X = 61$ g.

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Exam: JEE Main 2025
Paper: 24 January, Morning Shift
Subject: Chemistry
Chapter: Aromatic Compounds
Topic: Chemical Properties of Arenes - Non-EAS Reactions

Following are the four molecules "P", "Q", "R" and "S". Which one among the four molecules will react with H- Br( aq) at the fastest rate ?

Answer: 61

Step-by-step solution

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