Mathematics · Inverse Trigonometric Functions

JEE Main 2025 — 24 January, Morning Shift — Question 22

If for some α,β;α≤β,α+β=8\alpha, \beta ; \alpha \leq \beta, \alpha+\beta=8 and sec⁡2(tan⁡−1α)+cosec⁡2(cot⁡−1β)=36\sec ^{2}\left(\tan ^{-1} \alpha\right)+\operatorname{cosec}^{2}\left(\cot ^{-1} \beta\right)=36, then α2+β\alpha^{2}+\beta

is _____\_\_\_\_\_ .

Answer: 14

Numerical answer — enter this value.

Step-by-step solution

1+(tan⁡(tan⁡−1(α))2+1+(cot⁡(cot⁡−1β))2=361 +\left(\tan \left(\tan ^{-1}(\alpha)\right)^{2}+1 +\left(\cot \left(\cot ^{-1} \beta\right)\right)^{2}=36\right.

α2+β2=34\alpha^{2}+\beta^{2}=34

αβ=15\alpha \beta=15

α=3,β=5\alpha=3, \beta=5

∴α2+β=9+5=14\therefore \alpha^{2}+\beta=9+5=14

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Mathematics
Chapter
Inverse Trigonometric Functions
Topic
Equations, Inequations and Identitites involving ITFs
If for some α, β ; α leq β, α+β=8 and sec 2 (tan -1 α )+ cosec 2 (cot… | JEE Main 2025 PYQ with Solution · DhiX AI