Chemistry · d and f Block Elements

JEE Main 2025 — 24 January, Morning Shift — Question 30

Which of the following ions is the strongest oxidizing agent?

(Atomic Number of Ce=58,Eu=63, Tb=65,Lu=71\mathrm{Ce}=58, \mathrm{Eu}=63, \mathrm{~Tb}=65, \mathrm{Lu}=71 ]

  1. Option A:

    Lu3+\mathrm{Lu}^{3+}

  2. Option B:

    Eu2+\mathrm{Eu}^{2+}

  3. Option C:

    Tb4+\mathrm{Tb}^{4+}

    Correct
  4. Option D:

    Ce3+\mathrm{Ce}^{3+}

Answer: C

Step-by-step solution

Tb4+\mathrm{Tb}^{4+} is strongest oxidising agent

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Chemistry
Chapter
d and f Block Elements
Topic
Inner transition elements (f-Block elements)
Which of the following ions is the strongest oxidizing agent? (Atomic… | JEE Main 2025 PYQ with Solution · DhiX AI