JEE Main 2025 · previous year paper

JEE Main 2025 — 24 January, Evening Shift

68 questions with the verified answer key. Open any question for its step-by-step solution.

  1. Question 1Mathematics· Ellipse

    The equation of the chord, of the ellipse x225+y216=1\frac{x^{2}}{25}+\frac{y^{2}}{16}=1, whose mid-point is (3,1)(3,1) is :

    1. Option A:

      48x+25y=16948 x+25 y=169

    2. Option B:

      4x+122y=1344 x+122 y=134

    3. Option C:

      25x+101y=17625 x+101 y=176

    4. Option D:

      5x+16y=315 x+16 y=31

  2. Question 2Mathematics· Functions

    The function f:(−∞,∞)→(−∞,1)f:(-\infty, \infty) \rightarrow(-\infty, 1), defined by f(x)=2x−2−x2x+2−xf(x)=\frac{2^{x}-2^{-x}}{2^{x}+2^{-x}} is :

    1. Option A:

      One-one but not onto

    2. Option B:

      Onto but not one-one

    3. Option C:

      Both one-one and onto

    4. Option D:

      Neither one-one nor onto

  3. Question 3Mathematics· Inverse Trigonometric Functions

    If α>β>γ>0\alpha>\beta>\gamma>0, then the expression cot⁡−1{β+(1+β2)(α−β)}+cot⁡−1{γ+(1+γ2)(β−γ)}+cot⁡−1{α+(1+α2)(γ−α)}\cot ^{-1}\left\{\beta+\frac{\left(1+\beta^{2}\right)}{(\alpha-\beta)}\right\}+\cot ^{-1}\left\{\gamma+\frac{\left(1+\gamma^{2}\right)}{(\beta-\gamma)}\right\}+\cot ^{-1}\left\{\alpha+\frac{\left(1+\alpha^{2}\right)}{(\gamma-\alpha)}\right\} is equal to:

    1. Option A:

      π2−(α+β+γ)\frac{\pi}{2}-(\alpha+\beta+\gamma)

    2. Option B:

      3π3 \pi

    3. Option C:

      0

    4. Option D:

      π\pi

  4. Question 4Mathematics· Limits, Continuity and Differentiability

    Let f:(0,∞)→R\mathrm{f}:(0, \infty) \rightarrow \mathbf{R} be a function which is differentiable at all points of its domain and satisfies the condition

    x2f′(x)=2xf(x)+3x^{2} f^{\prime}(x)=2 x f(x)+3, with f(1)=4f(1)=4. Then 2f(2)2 f(2) is equal to:

    1. Option A:

      29

    2. Option B:

      19

    3. Option C:

      39

    4. Option D:

      23

  5. Question 5Mathematics· Basic Maths

    Let A={x∈(0,π)−{π2}:log⁡(2/π)∣sin⁡x∣+log⁡(2/π)∣cos⁡x∣=2}A=\left\{x \in(0, \pi)-\left\{\frac{\pi}{2}\right\}: \log _{(2 / \pi)}|\sin x|+\log _{(2 / \pi)}|\cos x|=2\right\}

    and B={x≥0:x(x−4)−3∣x−2∣+6=0}B=\{x \geq 0: \sqrt{x}(\sqrt{x}-4)-3|\sqrt{x}-2|+6=0\}. Then n(A∪B)\mathrm{n}(\mathrm{A} \cup \mathrm{B}) is equal to:

    1. Option A:

      4

    2. Option B:

      2

    3. Option C:

      8

    4. Option D:

      6

  6. Question 6Mathematics· Vector Algebra

    Let the position vectors of three vertices of a triangle be 4p→+q→−3r→,−5p→+q→+2r→4 \overrightarrow{\mathrm{p}}+\overrightarrow{\mathrm{q}}-3 \overrightarrow{\mathrm{r}},-5 \overrightarrow{\mathrm{p}}+\overrightarrow{\mathrm{q}}+2 \overrightarrow{\mathrm{r}} and 2p→−q→+2r→2 \overrightarrow{\mathrm{p}}-\overrightarrow{\mathrm{q}}+2 \overrightarrow{\mathrm{r}}.

    If the position vectors of the orthocenter and the circumcenter of the triangle are p→+q→+r→4\frac{\overrightarrow{\mathrm{p}}+\overrightarrow{\mathrm{q}}+\overrightarrow{\mathrm{r}}}{4} and αp→+βq→+γr→\alpha \overrightarrow{\mathrm{p}}+\beta \overrightarrow{\mathrm{q}}+\gamma \overrightarrow{\mathrm{r}}

    respectively, then α+2β+5γ\alpha+2 \beta+5 \gamma is equal to:

    1. Option A:

      3

    2. Option B:

      1

    3. Option C:

      6

    4. Option D:

      4

  7. Question 7Mathematics· Sequence and Series

    In an arithmetic progression, if S40=1030S_{40}=1030 and S12=57S_{12}=57, then S30−S10S_{30}-S_{10} is equal to:

    1. Option A:

      510

    2. Option B:

      515

    3. Option C:

      525

    4. Option D:

      505

  8. Question 8Mathematics· Sequence and Series

    If 7=5+17(5+α)+172(5+2α)+173(5+3α)+7=5+\frac{1}{7}(5+\alpha)+\frac{1}{7^{2}}(5+2 \alpha)+\frac{1}{7^{3}}(5+3 \alpha)+ _____\_\_\_\_\_ ∞\infty, then the value of α\alpha is :

    1. Option A:

      1

    2. Option B:

      67\frac{6}{7}

    3. Option C:

      6

    4. Option D:

      17\frac{1}{7}

  9. Question 9Mathematics· Matrices

    If the system of equations

    x+2y−3z=2x+2 y-3 z=2

    2x+λy+5z=52 x+\lambda y+5 z=5

    14x+3y+μz=3314 x+3 y+\mu z=33

    has infinitely many solutions, then λ+μ\lambda+\mu is equal to:

    1. Option A:

      13

    2. Option B:

      10

    3. Option C:

      11

    4. Option D:

      12

  10. Question 10Mathematics· Application of Derivatives

    Let (2,3)(2,3) be the largest open interval in which the function f(x)=2log⁡e(x−2)−x2+ax+1f(x)=2 \log _{e}(x-2)-x^{2}+a x+1

    is strictly increasing and (b, c) be the largest open interval, in which the function

    g(x)=(x−1)3(x+2−a)2g(x)=(x-1)^{3}(x+2-a)^{2} is strictly decreasing. Then 100(a+b−c)100(a+b-c) is equal to:

    1. Option A:

      280

    2. Option B:

      360

    3. Option C:

      420

    4. Option D:

      160

  11. Question 11Mathematics· Binomial Theorem

    Suppose AA and BB are the coefficients of 30th 30^{\text {th }} and 12th 12^{\text {th }} terms respectively in the binomial expansion of (1+x)2n−1(1+x)^{2 n-1}. If 2A=5B2 A=5 B, then nn is equal to:

    1. Option A:

      22

    2. Option B:

      21

    3. Option C:

      20

    4. Option D:

      19

  12. Question 12Mathematics· Vector Algebra

    Let a→=3i^−j^+2k^,b→=a→×(i^−2k^)\overrightarrow{\mathrm{a}}=3 \hat{\mathrm{i}}-\hat{\mathrm{j}}+2 \hat{\mathrm{k}}, \overrightarrow{\mathrm{b}}=\overrightarrow{\mathrm{a}} \times(\hat{\mathrm{i}}-2 \hat{\mathrm{k}}) and c→=b→×k^\overrightarrow{\mathrm{c}}=\overrightarrow{\mathrm{b}} \times \hat{\mathrm{k}}. Then the projection of c⃗−2j^\vec{c}-2 \hat{j} on a⃗\vec{a} is:

    1. Option A:

      373 \sqrt{7}

    2. Option B:

      14\sqrt{14}

    3. Option C:

      2142 \sqrt{14}

    4. Option D:

      272 \sqrt{7}

  13. Question 13Mathematics· Determinants

    For some a,ba, b, let

    f(x)=∣a+sin⁡xx1ba1+sin⁡xxba1b+sin⁡xx∣,x≠0,f(x)=\left|\begin{array}{ccc} a+\frac{\sin x}{x} & 1 & b \\a & 1+\frac{\sin x}{x} & b\\ a & 1 & b+\frac{\sin x}{x} \end{array}\right|, \quad x \neq 0,

    lim⁡x→0f(x)=λ+μa+vb\lim _{x \rightarrow 0} f(x)=\lambda+\mu a+v b. Then (λ+μ+v)2(\lambda+\mu+v)^{2} is equal to:

    1. Option A:

      25

    2. Option B:

      9

    3. Option C:

      36

    4. Option D:

      16

  14. Question 14Mathematics· Permutations and Combinations

    Group AA consists of 7 boys and 3 girls, while group BB consists of 6 boys and 5 girls. The number of ways, 4 boys and 4 girls can be invited for a picnic if 5 of them must be from group A and the remaining 3 from group BB, is equal to:

    1. Option A:

      8575

    2. Option B:

      9100

    3. Option C:

      8925

    4. Option D:

      8750

  15. Question 15Mathematics· Area under the Curves

    The area of the region enclosed by the curves y=ex,y=∣ex−1∣y=e^{x}, y=\left|e^{x}-1\right| and yy-axis is :

    1. Option A:

      1+log⁡e21+\log _{e} 2

    2. Option B:

      log⁡e2\log _{e} 2

    3. Option C:

      2log⁡e2−12 \log _{\mathrm{e}} 2-1

    4. Option D:

      1−log⁡e21-\log _{e} 2

  16. Question 16Mathematics· Basic Maths

    The number of real solution(s) of the equation x2+3x+2=min⁡{∣x−3∣,∣x+2∣}x^{2}+3 x+2=\min \{|x-3|,|x+2|\} is :

    1. Option A:

      2

    2. Option B:

      0

    3. Option C:

      3

    4. Option D:

      1

  17. Question 17Mathematics· Matrices

    Let A=[aij]\mathrm{A}=\left[\mathrm{a}_{\mathrm{ij}}\right] be a square matrix of order 2 with entries either 0 or 1 . Let E be the event that A is an invertible matrix. Then the probability P(E)\mathrm{P}(\mathrm{E}) is :

    1. Option A:

      58\frac{5}{8}

    2. Option B:

      316\frac{3}{16}

    3. Option C:

      18\frac{1}{8}

    4. Option D:

      38\frac{3}{8}

  18. Question 18Mathematics· Parabola

    If the equation of the parabola with vertex V(32,3)V\left(\frac{3}{2}, 3\right) and the directrix x+2y=0x+2 y=0 is

    αx2+βy2−γxy−30x−60y+225=0\alpha x^{2}+\beta y^{2}-\gamma x y-30 x-60 y+225=0, then α+β+γ\alpha+\beta+\gamma is equal to:

    1. Option A:

      6

    2. Option B:

      8

    3. Option C:

      7

    4. Option D:

      9

  19. Question 19Mathematics· Permutations and Combinations

    Number of functions f:{1,2,...,100}→{0,1},f : \{1, 2, ..., 100\} \rightarrow \{0, 1\}, that assign 1 to exactly one of the positive integers less than or equal to 98, is equal to _____\_\_\_\_\_.

  20. Question 20Mathematics· 3D Geometry

    Let P be the image of the point Q(7, -2, 5) in the line L:x−12=y+13=z4L: \frac{x-1}{2} = \frac{y+1}{3} = \frac{z}{4} and R(5, p, q) be a point on L. Then the square of the area of △\triangle PQR is_____\_\_\_\_\_.

  21. Question 21Mathematics· Differential Equations

    Let y=y(x)y=y(x) be the solution of the differential equation 2cos⁡xdydx=sin⁡2x−4ysin⁡x,x∈(0,π2)2 \cos x \frac{d y}{d x}=\sin 2 x-4 y \sin x, x \in\left(0, \frac{\pi}{2}\right).

    If y(π3)=0y\left(\frac{\pi}{3}\right)=0, then y′(π4)+y(π4)y^{\prime}\left(\frac{\pi}{4}\right)+y\left(\frac{\pi}{4}\right) is equal to _____\_\_\_\_\_ .

  22. Question 22Mathematics· Hyperbola

    Let H1:x2a2−y2b2=1H_{1}: \frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1 and H2:−x2A2+y2B2=1H_{2}:-\frac{x^{2}}{A^{2}}+\frac{y^{2}}{B^{2}}=1 be two hyperbolas having length of latus rectums 15215 \sqrt{2} and 12512 \sqrt{5} respectively. Let their eccentricities be e1=52e_{1}=\sqrt{\frac{5}{2}} and e2e_{2} respectively. If the product of the lengths of their transverse axes is 10010100 \sqrt{10}, then 25e2225 \mathrm{e}_{2}^{2} is equal to _____\_\_\_\_\_

  23. Question 23Mathematics· Indefinite Integration

    If ∫2x2+5x+9x2+x+1dx=xx2+x+1+αx2+x+1+\int \frac{2 x^{2}+5 x+9}{\sqrt{x^{2}+x+1}} d x=x \sqrt{x^{2}+x+1}+\alpha \sqrt{x^{2}+x+1}+ βlog⁡e∣x+12+x2+x+1∣+C\beta \log _{e}\left|x+\frac{1}{2}+\sqrt{x^{2}+x+1}\right|+C,

    where CC is the constant of integration, then α+2β\alpha+2 \beta is equal to _____\_\_\_\_\_

  24. Question 24Chemistry· Electrochemistry

    Based on the following data:

    ECr2O72−/Cr3+∘=+1.33 V,ECl2/Cl−∘=+1.36 VE^\circ_{\mathrm{Cr_2O_7^{2-}/Cr^{3+}}} = +1.33\,\mathrm{V}, \qquad E^\circ_{\mathrm{Cl_2/Cl^-}} = +1.36\,\mathrm{V}

    the strongest reducing agent among the following is:

    1. Option A:

      Mn2+\mathrm{Mn}^{2+}

    2. Option B:

      Cr\mathrm{Cr}

    3. Option C:

      MnO4−\mathrm{MnO}_{4}^{-}

    4. Option D:

      Cl−\mathrm{Cl}^{-}

  25. Question 25Chemistry· Chemical Kinetics

    Given below are two statements:

    figure

    figure

    In the light of the above statements, choose the correct answer from the options given below :

    1. Option A:

      Both Statement I and Statement II are false

    2. Option B:

      Statement I is false but Statement II is true

    3. Option C:

      Both Statement I and Statement II are true

    4. Option D:

      Statement I is true but Statement II is false

  26. Question 26Chemistry· Nitrogen Containing Organic Compounds

    For reaction

    figure

    The correct order of set of reagents for the above conversion is:

    1. Option A:

      Br2∣FeBr3,H2O(Δ),NaOH\mathrm{Br}_{2} \mid \mathrm{FeBr}_{3}, \mathrm{H}_{2} \mathrm{O}(\Delta), \mathrm{NaOH}

    2. Option B:

      H2SO4,Ac2O,Br2,H2O(Δ),NaOH\mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{Ac}_{2} \mathrm{O}, \mathrm{Br}_{2}, \mathrm{H}_{2} \mathrm{O}(\Delta), \mathrm{NaOH}

    3. Option C:

      Ac2O,Br2,H2O(Δ),NaOH\mathrm{Ac}_{2} \mathrm{O}, \mathrm{Br}_{2}, \mathrm{H}_{2} \mathrm{O}(\Delta), \mathrm{NaOH}

    4. Option D:

      Ac2O,H2SO4,Br2,NaOH\mathrm{Ac}_{2} \mathrm{O}_{,} \mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{Br}_{2}, \mathrm{NaOH}

  27. Question 27Chemistry· Chemical Bonding

    For hydrogen atom, the orbital/s with lowest energy is/are :

    (A) 4 s

    (B) 3px3 p_{x}

    (C) 3dx2−y23 d_{x^{2}-y^{2}}

    (D) 3 dz23 \mathrm{~d}_{\mathrm{z}^{2}}

    (E) 4pz4 p_{z}

    Choose the correct answer from the options given below :

    1. Option A:

      (A) and (E) only

    2. Option B:

      (B) only

    3. Option C:

      (A) only

    4. Option D:

      (B), (C) and (D) only

  28. Question 28Chemistry· Chemical Bonding

    In the given structure, number of sp and sp2\mathrm{sp}^{2} hybridized carbon atoms present respectively are :

    figure

    1. Option A:

      3 and 6

    2. Option B:

      3 and 5

    3. Option C:

      4 and 6

    4. Option D:

      4 and 5

  29. Question 29Chemistry· Chemical Bonding

    Given below are two statements :

    Statement(I) : Experimentally determined oxygen-oxygen bond lengths in the O3\mathrm{O}_{3} are found to be same and the bond length is greater than that of a O=O\mathrm{O}=\mathrm{O} (double bond) but less than that of a single ( O−O\mathrm{O}-\mathrm{O} ) bond.

    Statement (II) : The strong lone pair-lone pair repulsion between oxygen atoms is solely responsible for the fact that the bond length in ozone is smaller than that of a double bond (O=O)(\mathrm{O}=\mathrm{O}) but more than that of a single bond (O−O)(\mathrm{O}-\mathrm{O}).

    In the light of the above statements, choose the correct answer from the options given below:

    1. Option A:

      Statement I is true but Statement II is false

    2. Option B:

      Both Statement I and Statement II are true

    3. Option C:

      Both Statement I and Statement II are false

    4. Option D:

      Statement I is false but Statement II is true

  30. Question 30Chemistry· Practical Inorganic chemistry (Qualitative Analysis)

    Find the compound 'A' from the following reaction sequences.

    A→ aqua-regia B→(2)AcOH(1)KNO2/NH4OH\mathrm{A} \xrightarrow{\text { aqua-regia }} \mathrm{B} \xrightarrow[(2) \mathrm{AcOH}]{(1) \mathrm{KNO}_{2} / \mathrm{NH}_{4} \mathrm{OH}} yellow ppt

    1. Option A:

      ZnS

    2. Option B:

      CoS

    3. Option C:

      MnS

    4. Option D:

      NiS

  31. Question 31Chemistry· d and f Block Elements

    Match List-I with List-II.

    List-I (Transition metal ion)List-II (Spin only magnetic moment (B.M.))
    (A) Ti3+\text{T}{{\text{i}}^{3+}}(I) 3.87
    (B) V2+{{\text{V}}^{2+}}(II) 0.00
    (C) Ni2+\text{N}{{\text{i}}^{2+}}(III) 1.73
    (D) Sc3+\text{S}{{\text{c}}^{3+}}(IV) 2.84

    Choose the correct answer from the options given below :

    1. Option A:

      (A)-(III), (B)-(I), (C)-(II), (D)-(IV)

    2. Option B:

      (A)-(III), (B)-(I), (C)-(IV), (D)-(II)

    3. Option C:

      (A)-(IV), (B)-(II), (C)-(III), (D)-(I)

    4. Option D:

      (A)-(II), (B)-(IV), (C)-(I), (D)-(III)

  32. Question 32Chemistry· Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

    The elemental composition of a compound is 54.2%54.2\% C, 9.2%9.2\% H and 36.6%36.6\% O. If the molar mass of the compound is 132 g mol−1132\,\text{g mol}^{-1}, the molecular formula of the compound is _____\_\_\_\_\_.

    (Given: Relative atomic masses of C : H : O = 12 : 1 : 16)

    1. Option A:

      C4H9O3\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{O}_{3}

    2. Option B:

      C6H12O6\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}

    3. Option C:

      C6H12O3\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{3}

    4. Option D:

      C4H8O2\mathrm{C}_{4} \mathrm{H}_{8} \mathrm{O}_{2}

  33. Question 33Chemistry· Coordination Compounds

    When Ethane-1,2-diamine is added progressively to an aqueous solution of Nickel (II) chloride, the sequence of colour change observed will be :

    1. Option A:

      Pale Blue →\rightarrow Blue →\rightarrow Green →\rightarrow Violet

    2. Option B:

      Pale Blue →\rightarrow Blue →\rightarrow Violet →\rightarrow Green

    3. Option C:

      Green →\rightarrow Pale Blue →\rightarrow Blue →\rightarrow Violet

    4. Option D:

      Violet →\rightarrow Blue →\rightarrow Pale Blue →\rightarrow Green

  34. Question 34Chemistry· Coordination Compounds

    The conditions and consequence that favours the t2 g3,eg1\mathrm{t}_{2 \mathrm{~g}}{ }^{3}, \mathrm{e}_{\mathrm{g}}{ }^{1} configuration in a metal complex are :

    1. Option A:

      weak field ligand, high spin complex

    2. Option B:

      strong field ligand, high spin complex

    3. Option C:

      strong field ligand, low spin complex

    4. Option D:

      weak field ligand, low spin complex

  35. Question 35Chemistry· Aromatic Compounds

    Identify correct statement/s :

    (A) −OCH3-\mathrm{OCH}_{3} and −NHCOCH3-\mathrm{NHCOCH}_{3} are activating group

    (B) -CN and -OH are meta directing group

    (C) -CN and −SO3H-\mathrm{SO}_{3} \mathrm{H} are meta directing group

    (D) Activating groups act as ortho - and para directing groups

    (E) Halides are activating groups

    Choose the correct answer from the options given below:

    1. Option A:

      (A), (C) and (D) only

    2. Option B:

      (A) , (B) and (E) only

    3. Option C:

      (A) only

    4. Option D:

      (A) and (C) only

  36. Question 36Chemistry· Periodicity of Elements and Periodic Properties

    Given below are two statements, one is labelled as Statement I and the other is labelled as Statement II.

    Statement I : The first ionization energy of Pb is greater than that of Sn.

    Statement II : The first ionization energy of Ge is greater than that of Si.

    In the light of the above statements, choose the correct answer from the options given below :

    1. Option A:

      Statement I is true but Statement II is false

    2. Option B:

      Both Statement I and Statement II are false

    3. Option C:

      Statement I is false but Statement II is true

    4. Option D:

      Both Statement I and Statement II are true

  37. Question 37Chemistry· Thermodynamics & Thermochemistry

    S(g)+32O2( g)→SO3( g)+2xkcal\mathrm{S}(\mathrm{g})+\frac{3}{2} \mathrm{O}_{2}(\mathrm{~g}) \rightarrow \mathrm{SO}_{3}(\mathrm{~g})+2 \mathrm{xkcal}

    SO2( g)+12O2( g)→SO3( g)+ykcal\mathrm{SO}_{2}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g}) \rightarrow \mathrm{SO}_{3}(\mathrm{~g})+\mathrm{y} \mathrm{kcal}

    The heat of formation of SO2( g)\mathrm{SO}_{2}(\mathrm{~g}) is given by :

    1. Option A:

      2xykcal\frac{2 x}{y} \mathrm{kcal}

    2. Option B:

      y−2xy-2 x kcal

    3. Option C:

      2x+y2 x+y kcal

    4. Option D:

      x+yx+y kcal

  38. Question 38Chemistry· Aromatic Compounds

    Match List-I with List-II

    figure

    Choose the correct answer from the options given below :

    1. Option A:

      (A)-(IV), (B)-(III), (C)-(I), (D)-(II)

    2. Option B:

      (A)-(III), (B)-(IV), (C)-(II), (D)-(I)

    3. Option C:

      (A)-(I), (B)-(III), (C)-(II), (D)-(IV)

    4. Option D:

      (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

  39. Question 39Chemistry· Aromatic Compounds

    The structure of the major product formed in the following reaction is :

    figure

    1. Option A:
      Option A figure
    2. Option B:
      Option B figure
    3. Option C:
      Option C figure
    4. Option D:
      Option D figure
  40. Question 40Chemistry· Biomolecules

    Match List-I with List-II.

    figure

    Choose the correct answer from the options given below :

    1. Option A:

      (A)-(III), (B)-(IV), (C)-(II), (D)-(I)

    2. Option B:

      (A)-(III), (B)-(I), (C)-(IV), (D)-(II)

    3. Option C:

      (A)-(IV), (B)-(III), (C)-(II), (D)-(I)

    4. Option D:

      (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

  41. Question 41Chemistry· Periodicity of Elements and Periodic Properties

    The successive 5 ionisation energies of an element are 800,2427,3658,25024800,2427,3658,25024 and 32824  kJ mol−132824\; \mathrm{kJ\,mol^{-1}}, respectively. By using the above values predict the group in which the above element is present :

    1. Option A:

      Group 2

    2. Option B:

      Group 13

    3. Option C:

      Group 4

    4. Option D:

      Group 14

  42. Question 42Chemistry· Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

    The observed molar mass and normal molar mass of the compound MX2\mathrm{MX_2} are 65.665.6 and 164164 respectively.

    Find the percent degree of ionisation of MX2\mathrm{MX_2}. (Nearest   integer)\quad (\text{Nearest \;integer})

  43. Question 43Chemistry· Isomerism

    The possible number of stereoisomers for 5 -phenylpent-4-en-2-ol is___.

  44. Question 44Chemistry· Chemical Kinetics

    Consider a complex reaction taking place in three steps with rate constants k1,k2\mathrm{k}_{1}, \mathrm{k}_{2} and k3\mathrm{k}_{3} respectively. The overall rate constant kk is given by the expression k=k1k3k2k=\sqrt{\frac{k_{1} k_{3}}{k_{2}}}. If the activation energies of the three steps are 60,30 and 10 kJ mol−110 \mathrm{~kJ} \mathrm{~mol}^{-1} respectively, then the overall energy of activation in kJmol−1\mathrm{kJ} \mathrm{mol}^{-1} is___ . (Nearest integer)

  45. Question 45Chemistry· Hydrocarbons

    The hydrocarbon (X) with molar mass 80 g mol−180 \mathrm{~g} \mathrm{~mol}^{-1} and 90%90 \% carbon has ___degree of unsaturation.

  46. Question 46Chemistry· Practical Organic Chemistry

    In Carius method of estimation of halogen, 0.25 g of an organic compound gave 0.15 g of silver bromide (AgBr)(\mathrm{AgBr}). The percentage of Bromine in the organic compound is____ ×10−1%\times 10^{-1} \% (Nearest integer).

    (Given : Molar mass of Ag is 108 and Br is 80 g mol−180 \mathrm{~g} \mathrm{~mol}^{-1} )

  47. Question 47Physics· Wave Optics

    Young's double slit interference apparatus is immersed in a liquid of refractive index 1.44. It has slit separation of 1.5 mm . The slits are illuminated by a parallel beam of light whose wavelength in air is 690 nm . The fringe-width on a screen placed behind the plane of slits at a distance of 0.72 m , will be :

    1. Option A:

      0.23 mm

    2. Option B:

      0.33 mm

    3. Option C:

      0.63 mm

    4. Option D:

      0.46 mm

  48. Question 48Physics· Electromagnetic Waves

    Arrange the following in the ascending order of wavelength ( λ\lambda ) : (A) Microwaves (λ1)\left(\lambda_{1}\right) (B) Ultraviolet rays ( λ2\lambda_{2} ) (C) Infrared rays (λ3)\left(\lambda_{3}\right) (D) X-rays (λ4)\left(\lambda_{4}\right) Choose the most appropriate answer from the options

    1. Option A:

      λ4<λ3<λ2<λ1\lambda_{4}<\lambda_{3}<\lambda_{2}<\lambda_{1}

    2. Option B:

      λ3<λ4<λ2<λ1\lambda_{3}<\lambda_{4}<\lambda_{2}<\lambda_{1}

    3. Option C:

      λ4<λ2<λ3<λ1\lambda_{4}<\lambda_{2}<\lambda_{3}<\lambda_{1}

    4. Option D:

      λ4<λ3<λ1<λ2\lambda_{4}<\lambda_{3}<\lambda_{1}<\lambda_{2}

  49. Question 49Physics· Moving Charges and Magnetic Field

    Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason(R). Assertion (A) : A electron in a certain region of uniform magnetic field is moving with constant velocity in a straight line path.

    Reason (A) : The magnetic field in that region is along the direction of velocity of the electron.

    In the light of the above statements, choose the correct answer from the options given below :

    1. Option A:

      (A) is false but ( R ) is true

    2. Option B:

      Both (A) and (R) are true and (R) is the correct explanation of (A)

    3. Option C:

      Both (A) and (R) are true but ( R ) is NOT the correct explanation of (A)

    4. Option D:

      (A) is true but ( R ) is false

  50. Question 50Physics· Rotational Dynamics

    A solid sphere is rolling without slipping on a horizontal plane. The ratio of the linear kinetic energy of the centre of mass of the sphere and rotational kinetic energy is :

    1. Option A:

      2/5

    2. Option B:

      5/2

    3. Option C:

      3/4

    4. Option D:

      4/3

  51. Question 51Physics· Moving Charges and Magnetic Field

    . A long straight wire of a circular cross-section with radius 'a' carries a steady current I. The current I is a uniformly distributed across this cross-section. The plot of magnitude of magnetic field B with distance r from the centre of the wire is given by (1)

    1. Option A:
      Option A figure
    2. Option B:
      Option B figure
    3. Option C:
      Option C figure
    4. Option D:
      Option D figure
  52. Question 52Physics· Thermodynamics

    Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason(R). Assertion (A) : In an insulated container, a gas is adiabatically shrunk to half of its initial volume. The temperature of the gas decreases.

    Reason (R): Free expansion of an ideal gas is an irreversible and an adiabatic process.

    In the light of the above statement, choose the correct answer from the options given below :

    1. Option A:

      Both (A) and (R) are true and ( R ) is the correct explanation of (A)

    2. Option B:

      (A) is true but (R) is false

    3. Option C:

      (A) is false but ( R ) is true

    4. Option D:

      Both (A) and (R) are true but (R) is NOT the correct explanation of (A)

  53. Question 53Physics· Electrostatics

    In the first configuration (1) as shown in the figure, four identical charges (q0)\left(q_{0}\right) are kept at the corners A,B,CA, B, C and DD of square of side length ' aa '. In the second configuration (2), the same charges are shifted to mid points G,E,H\mathrm{G}, \mathrm{E}, \mathrm{H} and F , of the square, If K=14πε0\mathrm{K}=\frac{1}{4 \pi \varepsilon_{0}}, the difference between the potential energies of configuration (2) and (1) is given by :

    Question 53 figure
    1. Option A:

      Kq02a(42−2)\frac{K q_{0}^{2}}{a}(4 \sqrt{2}-2)

    2. Option B:

      Kq02a(3−2)\frac{\mathrm{Kq}_{0}^{2}}{\mathrm{a}}(3-\sqrt{2})

    3. Option C:

      Kq02a(4−22)\frac{\mathrm{Kq}_{0}^{2}}{\mathrm{a}}(4-2 \sqrt{2})

    4. Option D:

      Kq02a(32−2)\frac{\mathrm{Kq}_{0}^{2}}{\mathrm{a}}(3 \sqrt{2}-2)

  54. Question 54Physics· Motion in one Dimension

    The position vector of a moving body at any instant of time is given as r→=(5t2i^−5tj^)m\overrightarrow{\mathrm{r}}=\left(5 \mathrm{t}^{2} \hat{\mathrm{i}}-5 \mathrm{t} \hat{\mathrm{j}}\right) \mathrm{m}. The magnitude and direction of velocity at t=2 s\mathrm{t}=2 \mathrm{~s} is,

    1. Option A:

      515 m/s5 \sqrt{15} \mathrm{~m} / \mathrm{s}, making an angle of tan⁡−14\tan ^{-1} 4 with -ve Y axis

    2. Option B:

      515 m/s5 \sqrt{15} \mathrm{~m} / \mathrm{s}, making an angle of tan⁡−14\tan ^{-1} 4 with +ve X axis

    3. Option C:

      517 m/s5 \sqrt{17} \mathrm{~m} / \mathrm{s}, making an angle of tan⁡−14\tan ^{-1} 4 with -ve Y axis

    4. Option D:

      517 m/s5 \sqrt{17} \mathrm{~m} / \mathrm{s}, making an angle of tan⁡−14\tan ^{-1} 4 with +ve X axis

  55. Question 55Physics· Rotational Dynamics

    A solid sphere and a hollow sphere of the same mass and of same radius are rolled on an inclined plane. Let the time taken to reach the bottom by the solid sphere and the hollow sphere be t1t_1 and t2t_2, respectively, then

    1. Option A:

      t1<t2\mathrm{t}_{1}<\mathrm{t}_{2}

    2. Option B:

      t1=t2\mathrm{t}_{1}=\mathrm{t}_{2}

    3. Option C:

      t1=2t2t_{1}=2 t_{2}

    4. Option D:

      t1>t2t_{1}>t_{2}

  56. Question 56Physics· Moving Charges and Magnetic Field

    N equally spaced charges each of value q , are placed on a circle of radius R. The circle rotates about its axis with an angular velocity ω\omega as shown in the figure. A bigger Amperian loop B encloses the whole circle where as a smaller Amperian loop A encloses a small segment. The difference between enclosed currents, IA−IBI_{A}-I_{B}, for the given Amperian loops is images

    Question 56 figure
    1. Option A:

      N22πqω\frac{\mathrm{N}^{2}}{2 \pi} \mathrm{q} \omega

    2. Option B:

      2πNqω\frac{2 \pi}{N} q \omega

    3. Option C:

      N2πqω\frac{N}{2 \pi} q \omega

    4. Option D:

      Nπqω\frac{N}{\pi} q \omega

  57. Question 57Physics· Atomic Physics

    In photoelectric effect, the stopping potential (V0)\left(\mathrm{V}_{0}\right) v/s\mathrm{v} / \mathrm{s} frequency ( v ) curve is plotted.

    (h is the Planck's constant and ϕ0\phi_{0} is work function of metal)

    (A) V0v/svV_{0} v / s v is linear

    (B) The slope of V0v/sv\mathrm{V}_{0} \mathrm{v} / \mathrm{s} v curve =ϕ0 h=\frac{\phi_{0}}{\mathrm{~h}}

    (C) h constant is related to the slope of V0v/sv\mathrm{V}_{0} \mathrm{v} / \mathrm{s} \mathrm{v} line

    (D) The value of electric charge of electron is not required to determine hh using the V0v/svV_{0} v / s v curve.

    (E) The work function can be estimated without knowing the value of hh.

    Choose the correct answer from the options given below :

    1. Option A:

      (A),(B) and (C) only

    2. Option B:

      (C) and (D) only

    3. Option C:

      (A),(C) and (E) only

    4. Option D:

      (D) and (E) only

  58. Question 58Physics· Geometrical Optics

    A photograph of a landscape is captured by a drone camera at a height of 18 km . The size of the camera film is 2 cm×2 cm2 \mathrm{~cm} \times 2 \mathrm{~cm} and the area of the landscape photographed is 400 km2400 \mathrm{~km}^{2}. The focal length of the lens in the drone camera is :

    1. Option A:

      1.8cm

    2. Option B:

      2.8cm

    3. Option C:

      2.5cm

    4. Option D:

      0.9cm

  59. Question 59Physics· Semiconductor and Electronic Devices

    The output of the circuit is low (zero) for :

    (A) X=0,Y=0\mathrm{X}=0, \mathrm{Y}=0

    (B) X=0,Y=1\mathrm{X}=0, \mathrm{Y}=1

    (C) X=1,Y=0\mathrm{X}=1, \mathrm{Y}=0

    (D) X=1,Y=1\mathrm{X}=1, \mathrm{Y}=1

    Choose the correct answer from the options given below :

    Question 59 figure
    1. Option A:

      (A), (C) and (D) only

    2. Option B:

      (A), (B) and (C) only

    3. Option C:

      (B), (C) and (D) only

    4. Option D:

      (A), (B) and (D) only

  60. Question 60Physics· Heat Transfer

    The temperature of a body in air falls from 40∘C40^{\circ} \mathrm{C} to 24∘C24^{\circ} \mathrm{C} in 4 minutes. The temperature of the air is 16∘C16^{\circ} \mathrm{C}. The temperature of the body in the next 4 minutes will be :

    1. Option A:

      143∘C\frac{14}{3}{ }^{\circ} \mathrm{C}

    2. Option B:

      283∘C\frac{28}{3}{ }^{\circ} \mathrm{C}

    3. Option C:

      563∘C\frac{56}{3}{ }^{\circ} \mathrm{C}

    4. Option D:

      423∘C\frac{42}{3}{ }^{\circ} \mathrm{C}

  61. Question 61Physics· Units, Dimensions & Error Analysis

    The energy E and momentum p of a moving body of mass mm are related by some equation. Given that c represents the speed of light, identify the correct equation.

    1. Option A:

      E2=pc2+m2c4\mathrm{E}^{2}=\mathrm{pc}^{2}+\mathrm{m}^{2} \mathrm{c}^{4}

    2. Option B:

      E2=pc2+m2c2\mathrm{E}^{2}=\mathrm{pc}^{2}+\mathrm{m}^{2} \mathrm{c}^{2}

    3. Option C:

      E2=p2c2+m2c2E^{2}=p^{2} c^{2}+m^{2} c^{2}

    4. Option D:

      E2=p2c2+m2c4E^{2}=p^{2} c^{2}+m^{2} c^{4}

  62. Question 62Physics· Electrostatics

    A small uncharged conducting sphere is placed in contact with an identical sphere but having 4×10−84 \times 10^{-8} C charge and then removed to a distance such that the force of repulsion between them is 9×10−3 N9 \times 10^{-3} \mathrm{~N}. The distance between them is (Take 14πε0\frac{1}{4 \pi \varepsilon_{0}} as 9×1099 \times 10^{9} in SI units)

    1. Option A:

      2cm

    2. Option B:

      3cm

    3. Option C:

      4cm

    4. Option D:

      1cm

  63. Question 63Physics· Wave Optics

    In a Young's double slit experiment, three polarizers are kept as shown in the figure. The transmission axes of P1P_{1} and P2P_{2} are orthogonal to each other. The polarizer P3P_{3} covers both the slits with its transmission axis at 45∘45^{\circ} to those of P1\mathrm{P}_{1} and P2P_{2}. An unpolarized light of wavelength λ\lambda and intensity I0\mathrm{I}_{0} is incident on P1\mathrm{P}_{1} and P2\mathrm{P}_{2}. The intensity at a point after P3P_{3} where the path difference between the light waves from s1\mathrm{s}_{1} and s2\mathrm{s}_{2} is λ3\frac{\lambda}{3}, is

    Question 63 figure
    1. Option A:

      I02\frac{I_{0}}{2}

    2. Option B:

      I04\frac{I_{0}}{4}

    3. Option C:

      I0I_{0}

    4. Option D:

      I03\frac{I_{0}}{3}

  64. Question 64Physics· Moving Charges and Magnetic Field

    A tightly wound long solenoid carries a current of 1.5 A. An electron is executing

    uniform circular motion inside the solenoid with a time period of 75 ns . The number

    of turns per metre in the solenoid is \qquad .[0pt]

    [Take mass of electron me=9×10−31 kgm_{e}=9 \times 10^{-31} \mathrm{~kg}, charge of electron ∣qe∣=1.6×10−19C\left|\mathrm{q}_{\mathrm{e}}\right|=1.6 \times 10^{-19} \mathrm{C},

    μ0=4π×10−7 N A2,1 ns=10−9 s]\left.\mu_{0}=4 \pi \times 10^{-7} \frac{\mathrm{~N}}{\mathrm{~A}^{2}}, 1 \mathrm{~ns}=10^{-9} \mathrm{~s}\right]

  65. Question 65Physics· Horizontal Circular Motion

    A string of length LL is fixed at one end and carries a mass of M at the other end. The mass makes (3π)\left(\frac{3}{\pi}\right) rotations per second about the vertical axis passing through end of the string as shown. The tension in the string is \qquad ML.A string of length LL is fixed at one end and carries a mass of M at the other end. The mass makes (3π)\left(\frac{3}{\pi}\right) rotations per second about the vertical axis passing through end of the string as shown. The tension in the string is \qquad ML.. images

    Question 65 figure
  66. Question 66Physics· Atomic Physics

    The ratio of the power of a light source S1S_{1} to that the light source S2S_{2} is 2.S12 . S_{1} is emitting 2×10152 \times 10^{15} photons per second at 600 nm . If the wavelength of the source S2S_{2} is 300 nm , then the number of photons per second emitted by S2S_{2} is \qquad ×1014\times 10^{14}.

  67. Question 67Physics· Fluid Mechanics

    The increase in pressure required to decrease the volume of a water sample by 0.2%0.2 \% is P×105Nm−2\mathrm{P} \times 10^{5} \mathrm{Nm}^{-2}. Bulk modulus of water is 2.15×109Nm−22.15 \times 10^{9} \mathrm{Nm}^{-2}. The value of P is \qquad —.

  68. Question 68Physics· Gravitation

    Acceleration due to gravity on the surface of earth is ' g '. If the diameter of earth is reduced to one third of its original value and mass remains unchanged, then the acceleration due to gravity on the surface of the earth is \qquad g.

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