Mathematics · Permutations and Combinations

JEE Main 2025 — 24 January, Morning Shift — Question 23

The number of 3-digit numbers, that are divisible by 2 and 3 , but not divisible by 4 and 9 , is

Answer: 125

Numerical answer — enter this value.

Step-by-step solution

No, of 3 digits =999−99=900=999-99=900

No. of 3 digit numbers divisible by 2&32 \& 3 i.e. by 6

9006=150\frac{900}{6}=150

No. of 3 digit numbers divisible by 4&94 \& 9 i.e. by 36

90036=25\frac{900}{36}=25

∴\therefore No of 3 digit numbers divisible by 2&32 \& 3 but not by 4&94 \& 9

150−25=125150-25=125

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Mathematics
Chapter
Permutations and Combinations
Topic
Applications of Permuations and Combination
The number of 3-digit numbers, that are divisible by 2 and 3 , but… | JEE Main 2025 PYQ with Solution · DhiX AI