Start free

Physics · Wave Optics

JEE Main 2025 — 24 January, Morning Shift — Question 55

The Young's double slit interference experiment is performed using light consisting of 480 nm and 600 nm wavelengths to form interference patterns. The least number of the bright fringes of 480 nm light that are required for the first coincidence with the bright fringes formed by 600 nm light is :-

  1. Option A:

    4

  2. Option B:

    8

  3. Option C:

    6

  4. Option D:

    5

    Correct

Answer: D

Step-by-step solution

n1λ1Dd=n2λ2Dd\frac{n_{1} \lambda_{1} D}{d}=\frac{n_{2} \lambda_{2} D}{d}

n 480=m600480=m 600

nmin =5\mathrm{n}_{\text {min }}=5

Answer key and solution verified before publishing.

Practise Wave Optics

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free
Exam
JEE Main 2025
Paper
24 January, Morning Shift
Subject
Physics
Chapter
Wave Optics
Topic
Young's Double Slit Experiment and Its Modifications
The Young's double slit interference experiment is performed using… | JEE Main 2025 PYQ with Solution · DhiX AI