Physics · Capacitors and R-C Circuits

JEE Main 2025 — 24 January, Morning Shift — Question 64

A parallel plate capacitor was made with two rectangular plates, each with a length of

l=3 cml=3 \mathrm{~cm} and breath of b=1 cm\mathrm{b}=1 \mathrm{~cm}. The distance

between the plates is 3μ m3 \mu \mathrm{~m}. Out of the following, which are the ways

to increase the capacitance by a factor of 10 ?

A. l=30 cm, b=1 cm, d=1μ ml=30 \mathrm{~cm}, \mathrm{~b}=1 \mathrm{~cm}, \mathrm{~d}=1 \mu \mathrm{~m}

B. l=3 cm, b=1 cm, d=30μ ml=3 \mathrm{~cm}, \mathrm{~b}=1 \mathrm{~cm}, \mathrm{~d}=30 \mu \mathrm{~m}

C. l=6 cm, b=5 cm, d=3μ ml=6 \mathrm{~cm}, \mathrm{~b}=5 \mathrm{~cm}, \mathrm{~d}=3 \mu \mathrm{~m}

D. l=1 cm, b=1 cm, d=10μ ml=1 \mathrm{~cm}, \mathrm{~b}=1 \mathrm{~cm}, \mathrm{~d}=10 \mu \mathrm{~m}

E. l=5 cm, b=2 cm, d=1μ ml=5 \mathrm{~cm}, \mathrm{~b}=2 \mathrm{~cm}, \mathrm{~d}=1 \mu \mathrm{~m}

  1. Option A:

    C and E only

    Correct
  2. Option B:

    B and D only

  3. Option C:

    A only

  4. Option D:

    C only

Answer: A

Step-by-step solution

C=Aϵ0dC=\frac{A \epsilon_{0}}{d}

A : plate area

d : distance between the plates.

Capacitance initial

=ϵ0ℓbd=ϵ0=\frac{\epsilon_{0} \ell b}{d}=\epsilon_{0} units

Option ' C′ℓ=6 cm\mathrm{C}^{\prime} \quad \ell=6 \mathrm{~cm}

b=5 cm\mathrm{b}=5 \mathrm{~cm}

 d=3 cm \mathrm{~d}=3 \mathrm{~cm}

Capacitance =10ϵ0=10 \epsilon_{0} units

Option 'E' ℓ=5 cm\quad \ell=5 \mathrm{~cm}

b=2 cm\mathrm{b}=2 \mathrm{~cm}

 d=1 cm\mathrm{~d}=1 \mathrm{~cm}

Capacitance =10ϵ0=10 \epsilon_{0} units

∴\therefore Ans is option (1)

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Physics
Chapter
Capacitors and R-C Circuits
Topic
Capacitance and Different types of Capacitors
A parallel plate capacitor was made with two rectangular plates, each… | JEE Main 2025 PYQ with Solution · DhiX AI