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Chemistry · d and f Block Elements

JEE Main 2025 — 24 January, Morning Shift — Question 36

Preparation of potassium permanganate from MnO2\mathrm{MnO}_{2} involves two step process in which the 1st 1^{\text {st }} step is a reaction with KOH and KNO3\mathrm{KNO}_{3} to produce

  1. Option A:

    K4[Mn(OH)6]\mathrm{K}_{4}\left[\mathrm{Mn}(\mathrm{OH})_{6}\right]

  2. Option B:

    K3MnO4\mathrm{K}_{3} \mathrm{MnO}_{4}

  3. Option C:

    KMnO4\mathrm{KMnO}_{4}

  4. Option D:

    K2MnO4\mathrm{K}_{2} \mathrm{MnO}_{4}

    Correct

Answer: D

Step-by-step solution

MnO2→KNO3,ΔKOHK2MnO4\mathrm{MnO}_{2} \xrightarrow[\mathrm{KNO}_{3}, \Delta]{\mathrm{KOH}} \mathrm{K}_{2} \mathrm{MnO}_{4}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
24 January, Morning Shift
Subject
Chemistry
Chapter
d and f Block Elements
Topic
Compounds of Manganese

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