Physics · Fluid Mechanics

JEE Main 2025 — 28 January, Evening Shift — Question 66

The volume contraction of a solid copper cube of edge length 10 cm , when subjected to a hydraulic pressure of $7 \times 10^{6} \mathrm{~Pa}$ , would be $\qquad$ $\mathrm{mm}^{3}$ .

(Given bulk modulus of copper $=1.4 \times 10^{11} \mathrm{Nm}^{-2}$ )

Answer: 50

Numerical answer — enter this value.

Step-by-step solution

$B=\frac{\Delta P}{\frac{\Delta V}{V}}$

$\Delta \mathrm{V}=\frac{7 \times 10^{6}}{1.4 \times 10^{11}} \times\left(10 \times 10^{-2}\right)^{3}$

$\Delta \mathrm{V}=50 \mathrm{~mm}^{3}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 28 January, Evening Shift
Subject: Physics
Chapter: Fluid Mechanics
Topic: Properties of Fluids & Hydrostatic Pressure

a 400 g id cube having an edge of length 10 cm floats in water. How much volume of the cube is outside the water? (Given : density of water…

Answer: 50

Step-by-step solution

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