Chemistry · d and f Block Elements

JEE Main 2025 — 28 January, Evening Shift — Question 42

The spin only magnetic moment ( μ\mu ) value (B.M.) of the compound with strongest oxidising power among Mn2O3,TiO\mathrm{Mn}_{2} \mathrm{O}_{3}, \mathrm{TiO} and VO is____B.M. (Nearest integer).

Answer: 5

Numerical answer — enter this value.

Step-by-step solution

Strongest oxidising power among the option is

Mn2O3\mathrm{Mn}_{2} \mathrm{O}_{3} because of E∘\mathrm{E}^{\circ} value

EMn+3/Mn+2∘=+1.57 V\mathrm{E}_{\mathrm{Mn}^{+3} / \mathrm{Mn}^{+2}}^{\circ}=+1.57 \mathrm{~V}

Mn+3→ d4\mathrm{Mn}^{+3} \rightarrow \mathrm{~d}^{4} configuration

μ=24BM\mu=\sqrt{24} \mathrm{BM}

=4.89BM=4.89 \mathrm{BM}

⇒5\Rightarrow 5

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Chemistry
Chapter
d and f Block Elements
Topic
Properties of general compounds of transition elements
The spin only magnetic moment ( μ ) value (B.M.) of the compound with… | JEE Main 2025 PYQ with Solution · DhiX AI