Mathematics · Probability

JEE Main 2025 — 28 January, Evening Shift — Question 6

Let SS be the set of all the words that can be formed by arranging all the letters of the word GARDEN. From the set S , one word is selected at random. The probability that the selected word will NOT have vowels in alphabetical order is :

  1. Option A:

    14\frac{1}{4}

  2. Option B:

    23\frac{2}{3}

  3. Option C:

    13\frac{1}{3}

  4. Option D:

    12\frac{1}{2}

    Correct

Answer: D

Step-by-step solution

A, E,G R D N

Probabllity (P)= favourable case  Total case (P)=\frac{\text { favourable case }}{\text { Total case }}

(when A & E are in order)

Total case =6!=6!

Favourable case =6C2.4={ }^{6} \mathrm{C}_{2} .4 !

P=(15)4!(30)4!P=\frac{(15) 4!}{(30) 4!}

Probablity when not in order =1−12=12=1-\frac{1}{2}=\frac{1}{2}

Answer key and solution verified before publishing.

Practise Probability

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Exam
JEE Main 2025
Subject
Mathematics
Chapter
Probability
Topic
Problems based on P & C
Let S be the set of all the words that can be formed by arranging all… | JEE Main 2025 PYQ with Solution · DhiX AI