Mathematics · Functions

JEE Main 2025 — 28 January, Evening Shift — Question 15

Let $[x]$ denote the greatest integer less than or equal to $x$ . Then domain of $f(x)=\sec ^{-1}(2[x]+1)$ is :

Answer: B

$2[\mathrm{x}]+1 \leq-1$ or $2[\mathrm{x}]+1 \geq 1$

$\Rightarrow[\mathrm{x}] \leq-1 \cup[\mathrm{x}] \geq 0$

$\Rightarrow \mathrm{x} \in(-\infty, 0) \cup \mathrm{x} \in[0, \infty)$

$\Rightarrow \mathrm{x} \in(-\infty, \infty)$

Answer key and solution verified before publishing.

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.