Chemistry · Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

JEE Main 2025 — 24 January, Evening Shift — Question 42

The observed molar mass and normal molar mass of the compound MX2\mathrm{MX_2} are 65.665.6 and 164164 respectively.

Find the percent degree of ionisation of MX2\mathrm{MX_2}. (Nearest   integer)\quad (\text{Nearest \;integer})

Answer: 75

Numerical answer — enter this value.

Step-by-step solution

MX2→M2++2X−\mathrm{MX_2 \rightarrow M^{2+} + 2X^-} Total  particles   after   ionisation=3\text{Total\;particles \;after \;ionisation} = 3

Let degree of ionisation =α= \alpha

Mobserved=Mnormal1+2αM_{\text{observed}} = \frac{M_{\text{normal}}}{1 + 2\alpha} 65.6=1641+2α65.6 = \frac{164}{1 + 2\alpha} 1+2α=16465.6=2.51 + 2\alpha = \frac{164}{65.6} = 2.5 2α=1.52\alpha = 1.5 α=0.75\alpha = 0.75 Percent   degree   of   ionisation=75%\text{Percent\; degree \;of\; ionisation} = 75\%

Thus, the correct value is 75.

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry
Topic
Introduction to Mole Concept
The observed molar mass and normal molar mass of the compound MX 2… | JEE Main 2025 PYQ with Solution · DhiX AI