In Carius method of estimation of halogen, 0.25 g of an organic compound gave 0.15 g of silver bromide ( AgBr ) . The percentage of Bromine in the organic compound is × 10 -1 \% (Nearest integer). (Given : Molar mass of Ag is 108 and Br is 80 g mol -1 )

Chemistry · Practical Organic Chemistry

JEE Main 2025 — 24 January, Evening Shift — Question 46

In Carius method of estimation of halogen, 0.25 g of an organic compound gave 0.15 g of silver bromide $(\mathrm{AgBr})$ . The percentage of Bromine in the organic compound is____ $\times 10^{-1} \%$ (Nearest integer).

(Given : Molar mass of Ag is 108 and Br is $80 \mathrm{~g} \mathrm{~mol}^{-1}$ )

Answer: 255

Numerical answer — enter this value.

Step-by-step solution

% Bromine $=\frac{\text { Molar Mass of Bromine }}{\text { Molar Mass of Silver bromide }}$

$\quad \times \frac{\text { Weight of AgBr }}{\text { Weight of sample }} \times 100$

$=\frac{80}{188} \times \frac{0.165}{0.25} \times 100$

$=\frac{4800}{188}=25.53=255 \times 10^{-1}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 24 January, Evening Shift
Subject: Chemistry
Chapter: Practical Organic Chemistry
Topic: Quantitative organic analysis