Chemistry · Chemical Bonding
JEE Main 2025 — 24 January, Evening Shift — Question 28
In the given structure, number of sp and hybridized carbon atoms present respectively are :
- Option A:
3 and 6
- Option B:Correct
3 and 5
- Option C:
4 and 6
- Option D:
4 and 5
Answer: B
Step-by-step solution
Number of sp and hybridised carbon atom are 3 and 5.
Answer key and solution verified before publishing.
Practise Chemical Bonding
Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.
- Exam
- JEE Main 2025
- Subject
- Chemistry
- Chapter
- Chemical Bonding
- Topic
- Hybridization and VSEPR