JEE Main 2025 — 24 January, Evening Shift — Question 58

$\mathrm{H}=18 \mathrm{~km}$

Size of camera film $=2 \mathrm{~cm} \times 2 \mathrm{~cm}$

$\mathrm{A}_{\text {image }}=400 \mathrm{~km}^{2}$

$\mathrm{x}=20 \times 10^{3} \mathrm{~m}=2 \times 10^{4} \mathrm{~m}$

$y=2 \times 10^{-2} \mathrm{~m}$

$\frac{\mathrm{x}}{\mathrm{y}}=10^{6}=\frac{18 \mathrm{Km}}{\mathrm{f}}$

$\mathrm{f}=18 \times 10^{-3} \mathrm{~m}=18 \mathrm{~mm}$

$\mathrm{f}=1.8 \mathrm{~cm}$

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