Chemistry · Chemical Bonding

JEE Main 2025 — 24 January, Evening Shift — Question 27

For hydrogen atom, the orbital/s with lowest energy is/are :

(A) 4 s

(B) 3px3 p_{x}

(C) 3dx2−y23 d_{x^{2}-y^{2}}

(D) 3 dz23 \mathrm{~d}_{\mathrm{z}^{2}}

(E) 4pz4 p_{z}

Choose the correct answer from the options given below :

  1. Option A:

    (A) and (E) only

  2. Option B:

    (B) only

  3. Option C:

    (A) only

  4. Option D:

    (B), (C) and (D) only

    Correct

Answer: D

Step-by-step solution

In hydrogen atom the orbitals in a shell are degenerate means energy depends only on ' nn '

∴E3px=E3 dx2−y2=E3 dz2\therefore \mathrm{E}_{3 \mathrm{p}_{x}}=\mathrm{E}_{3 \mathrm{~d}_{x^{2}-y^{2}}}=\mathrm{E}_{3 \mathrm{~d}_{z^{2}}}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Chemistry
Chapter
Chemical Bonding
Topic
Molecular Orbital Theory
For hydrogen atom, the orbital/s with lowest energy is/are : (A) 4 s… | JEE Main 2025 PYQ with Solution · DhiX AI