Match List-I with List-II. List-I (Transition metal ion) List-II (Spin only magnetic moment (B.M.)) --- --- (A) T i 3+ (I) 3.87 (B) V 2+ (II) 0.00 (C) N i 2+ (III) 1.73 (D) S c 3+ (IV) 2.84 Choose the correct answer from the options given below :

(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

(A)-(III), (B)-(I), (C)-(II), (D)-(IV)

(A)-(IV), (B)-(II), (C)-(III), (D)-(I)

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

Chemistry · d and f Block Elements

JEE Main 2025 — 24 January, Evening Shift — Question 31

Match List-I with List-II.

List-I (Transition metal ion)	List-II (Spin only magnetic moment (B.M.))
(A) $\text{T}{{\text{i}}^{3+}}$	(I) 3.87
(B) ${{\text{V}}^{2+}}$	(II) 0.00
(C) $\text{N}{{\text{i}}^{2+}}$	(III) 1.73
(D) $\text{S}{{\text{c}}^{3+}}$	(IV) 2.84

Choose the correct answer from the options given below :

$\quad \mathrm{Sc}^{+3}=3 \mathrm{~d}^{\circ}$ $\therefore \mu_{\text {spin }}=0$

$\mathrm{V}^{+2}=3 \mathrm{~d}^{3}$ $\therefore \mu_{\text {spin }}=3.87$ B.M.

$\mathrm{Ni}^{+2}=3 \mathrm{~d}^{8}$ $\therefore \mu_{\text {spin }}=2.84$ B.M.

$\mathrm{Ti}^{+3}=3 \mathrm{~d}^{1} \quad \therefore \mu_{\text {spin }}=1.73$ B.M.

Answer key and solution verified before publishing.

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.