JEE Advanced 2024 · previous year paper

JEE Advanced 2024 — Paper 2

43 questions with the verified answer key. Open any question for its step-by-step solution.

  1. Question 1Mathematics· Inverse Trigonometric Functions

    Considering only the principal values of the inverse trigonometric functions, the value of tan⁡(sin⁡−1(35)−2cos⁡−1(25))\tan \left(\sin ^{-1}\left(\frac{3}{5}\right)-2 \cos ^{-1}\left(\frac{2}{\sqrt{5}}\right)\right) is

    1. Option A:

      724\frac{7}{24}

    2. Option B:

      −724\frac{-7}{24}

    3. Option C:

      −524\frac{-5}{24}

    4. Option D:

      524\frac{5}{24}

  2. Question 2Mathematics· Area under the Curves

    Let S={(x,y)∈R×R:x≥0,y≥0,y2≤4x,y2≤12−2xS=\left\{(x, y) \in \mathbb{R} \times \mathbb{R}: x \geq 0, y \geq 0, y^{2} \leq 4 x, y^{2} \leq 12-2 x\right. and 3y+8x≤58}\left.3 y+\sqrt{8} x \leq 5 \sqrt{8}\right\}. If the area of the region SS is α2\alpha \sqrt{2}, then α\alpha is equal to

    1. Option A:

      172\frac{17}{2}

    2. Option B:

      173\frac{17}{3}

    3. Option C:

      174\frac{17}{4}

    4. Option D:

      175\frac{17}{5}

  3. Question 3Mathematics· Limits, Continuity and Differentiability

    Let k∈Rk \in \mathbb{R}. If lim⁡x→0+(sin⁡(sin⁡kx)+cos⁡x+x)2x=e6\lim _{x \rightarrow 0^{+}}(\sin (\sin k x)+\cos x+x)^{\frac{2}{x}}=e^{6}, then the value of kk is

    1. Option A:

      1

    2. Option B:

      2

    3. Option C:

      3

    4. Option D:

      4

  4. Question 4Mathematics· Functions

    Let f:R→Rf: \mathbb{R} \rightarrow \mathbb{R} be a function defined by

    f(x)={x2sin⁡(πx2); if x≠00; if x=0f(x)=\left\{\begin{array}{cl} x^{2} \sin \left(\frac{\pi}{x^{2}}\right) & ; \text { if } x \neq 0 \\ 0 & ; \text { if } x=0 \end{array}\right.

    Then which of the following statements is TRUE?

    1. Option A:

      f(x)=0f(x)=0 has infinitely many solutions in the interval [11010,∞)\left[\frac{1}{10^{10}}, \infty\right)

    2. Option B:

      f(x)=0f(x)=0 has no solutions in the interval [1π,∞)\left[\frac{1}{\pi}, \infty\right)

    3. Option C:

      The set of solutions of f(x)=0f(x)=0 in the interval (0,11010)\left(0, \frac{1}{10^{10}}\right) is finite

    4. Option D:

      f(x)=0f(x)=0 has more than 25 solutions in the interval (1π2,1π)\left(\frac{1}{\pi^{2}}, \frac{1}{\pi}\right)

  5. Question 5Mathematics· Limits, Continuity and Differentiability

    Let SS be the set of all (α,β)∈R×R(\alpha, \beta) \in \mathbb{R} \times \mathbb{R} such that lim⁡x→∞sin⁡(x2)(log⁡ex)αsin⁡(1x2)xαβ(log⁡e(1+x))β=0.\lim _{x \rightarrow \infty} \frac{\sin \left(x^{2}\right)\left(\log _{e} x\right)^{\alpha} \sin \left(\frac{1}{x^{2}}\right)}{x^{\alpha \beta}\left(\log _{e}(1+x)\right)^{\beta}}=0 . Then which of the following is(are) correct ?

    1. Option A:

      (−1,3)∈S(-1,3) \in S

    2. Option B:

      (−1,1)∈S(-1,1) \in S

    3. Option C:

      (1,−1)∈S(1,-1) \in S

    4. Option D:

      (1,−2)∈S(1,-2) \in S

  6. Question 6Mathematics· 3D Geometry

    A straight line drawn from the point P(1,3,2)P(1,3,2), parallel to the line x−21=y−42=z−61\frac{x-2}{1}=\frac{y-4}{2}=\frac{z-6}{1} intersects the plane L1:x−y+3z=6L_{1}: x-y+3 z=6 at the point QQ. Another straight line which passesthrough QQ and is perpendicular to the plane L1L_{1} intersects the plane L2:2x−y+z=−4L_{2}: 2 x-y+z=-4 at the point RR. then which of the following statements is(are) TRUE?

    1. Option A:

      The length of the line segment PQP Q is 6\sqrt{6}

    2. Option B:

      The coordinates of R are (1,6,3)(1,6,3)

    3. Option C:

      The centroid of the triangle PQR is (43,143,53)\left(\frac{4}{3}, \frac{14}{3}, \frac{5}{3}\right)

    4. Option D:

      The perimeter of the triangle PQR is 2+6+11\sqrt{2}+\sqrt{6}+\sqrt{11}

  7. Question 7Mathematics· Parabola

    Let A1,B1,C1A_{1}, B_{1}, C_{1} be three points in the xyx y-plane. Suppose that the lines A1C1A_{1} C_{1} and B1C1B_{1} C_{1} are tangents to the curve y2=8xy^{2}=8 x at A1A_{1} and B1B_{1}, respectively. If O=(0,0)O=(0,0) and C1=(−4,0)C_{1}=(-4,0), then which of the following statements is(are) TRUE?

    1. Option A:

      The length of the line segment OA1\mathrm{OA}_{1} is 434 \sqrt{3}

    2. Option B:

      The length of the line segment A1B1A_{1} B_{1} is 16

    3. Option C:

      The orthocenter of the triangle A1 B1C1\mathrm{A}_{1} \mathrm{~B}_{1} \mathrm{C}_{1} is (0,0)(0,0)

    4. Option D:

      The orthocenter of the triangle A1B1C1A_{1} B_{1} C_{1} is (1,0)(1,0)

  8. Question 8Mathematics· Functions

    Let f:R→Rf: \mathbb{R} \rightarrow \mathbb{R} be a function such that f(x+y)=f(x)+f(y)f(x+y)=f(x)+f(y) for all x,y∈Rx, y \in \mathbb{R}, and g:R→(0,∞)g: \mathbb{R} \rightarrow(0, \infty) be a function such that g(x+y)=g(x)g(y)g(x+y)=g(x) g(y) for all x,y∈Rx, y \in \mathbb{R}. If f(−35)=12f\left(\frac{-3}{5}\right)=12 and g(−13)=2g\left(\frac{-1}{3}\right)=2, then the value of (f(14)+g(−2)−8)g(0)\left(f\left(\frac{1}{4}\right)+g(-2)-8\right) g(0) is \qquad

  9. Question 9Mathematics· Probability

    A bag contains NN balls out of which 3 balls are white, 6 balls are green, and the remaining balls are blue. Assume that the balls are identical otherwise. Three balls are drawn randomly one after the other without replacement. For i=1,2,3i=1,2,3, let Wi,GiW_{i}, G_{i}, and BiB_{i} denote the events that the ball drawn in the ith \mathrm{i}^{\text {th }} draw is a white ball, green ball, and blue ball, respectively. If the probability P(W1∩G2∩B3)=25NP\left(W_{1} \cap G_{2} \cap B_{3}\right)=\frac{2}{5 N} and the conditional probability P(B3∣W1∩G2)=29P\left(B_{3} \mid W_{1} \cap G_{2}\right)=\frac{2}{9}, then NN equals \qquad

  10. Question 10Mathematics· Functions

    Let the function f:R→Rf: \mathbb{R} \rightarrow \mathbb{R} be defined by f(x)=sin⁡xeπx(x2024+2024x+2025)(x2−x+3)+2eπx(x2024+2024x+2025)(x2−x+3).f(x)=\frac{\sin x}{e^{\pi x}} \frac{\left(x^{2024}+2024 x+2025\right)}{\left(x^{2}-x+3\right)}+\frac{2}{e^{\pi x}} \frac{\left(x^{2024}+2024 x+2025\right)}{\left(x^{2}-x+3\right)} .

    Then the number of solutions of f(x)=0f(x)=0 in R\mathbb{R} is \qquad

  11. Question 11Mathematics· Vector Algebra

    Let p⃗=2i^+j^+3k^\vec{p}=2 \hat{i}+\hat{j}+3 \hat{k} and q⃗=i^−j^+k^\vec{q}=\hat{i}-\hat{j}+\hat{k}. If for some real numbers α,β\alpha, \beta, and γ\gamma, we have

    15i^+10j^+6k^=α(2p⃗+q⃗)+β(p⃗−2q⃗)+γ(p⃗×q⃗),15 \hat{i}+10 \hat{j}+6 \hat{k}=\alpha(2 \vec{p}+\vec{q})+\beta(\vec{p}-2 \vec{q})+\gamma(\vec{p} \times \vec{q}),

    then the value of γ\gamma is _____\_\_\_\_\_

  12. Question 12Mathematics· Parabola

    A normal with slope 16\frac{1}{\sqrt{6}} is drawn from the point (0,−α)(0,-\alpha) to the parabola x2=−4x^{2}=-4 ay, where a>0\mathrm{a}>0. Let LL be the line passing through (0,−α)(0,-\alpha) and parallel to the directrix of the parabola. Suppose that LL intersects the parabola at two points AA and BB. Let rr denote the length of the latus rectum and ss denote the square of the length of the line segment ABA B. If r:s=1:16r: s=1: 16, then the value of 24α24 \alpha is

  13. Question 13Mathematics· Definite Integration

    A continuous function f:[0,34]→Rf:\left[0, \frac{3}{4}\right] \rightarrow R satisfies the equation f(x)=(1+x2)(1+∫0xf2(t)1+t2dt)f(x)=\left(1+x^{2}\right)\left(1+\int_{0}^{x} \frac{f^{2}(t)}{1+t^{2}} d t\right), then [f(12)]\left[\mathrm{f}\left(\frac{1}{2}\right)\right] is: [Note : [K] denotes greatest integer less than or equal to K.]

  14. Question 14Physics· Gravitation

    A particle of mass mm is under the influence of the gravitational field of a body of mass M(≫m)M(\gg m). The particle is moving in a circular orbit of radius ro with time period T0\mathrm{T}_{0} around the mass M . Then, the particle is subjected to an additional central force, corresponding to the potential energy Vc(r)=ma/r3V_{c}(r)=m a / r^{3}, where α\alpha is a positive constant of suitable dimensions and rr is the distance from the center of the orbit. If the particle moves in the same circular orbit of radius ro in the combined gravitational potential due to MM and Vc(r)V_{c}(r), but with a new time period T1T_{1}, then (T12−T02/T12\left(T_{1}^{2}-T_{0}^{2} / T_{1}^{2}\right. is given by [0pt] [ G is the gravitational constant.]

    1. Option A:

      3αGMr02\frac{3 \alpha}{\mathrm{GMr}_{0}^{2}}

    2. Option B:

      α2GMr02\frac{\alpha}{2 G M r_{0}^{2}}

    3. Option C:

      αGMr02\frac{\alpha}{\mathrm{GMr}_{0}^{2}}

    4. Option D:

      2αGMr02\frac{2 \alpha}{\mathrm{GMr}_{0}^{2}}

  15. Question 15Physics· Atomic Physics

    A metal target with atomic number Z=46Z=46 is bombarded with a high energy electron beam. The emission of XX-rays from the target is analyzed. The ratio rr of the wavelengths of the KαK_{\alpha}-line and the cut-off is found to be r=2r=2. If the same electron beam bombards another metal target with Z=41Z=41, the value of rr will be

    1. Option A:

      2.53

    2. Option B:

      1.27

    3. Option C:

      2.24

    4. Option D:

      1.58

  16. Question 16Physics· Moving Charges and Magnetic Field

    A thin stiff insulated metal wire is bent into a circular loop with its two ends extending tangentially from the same point of the loop. The wire loop has mass mm and radius rr and it is in a uniform vertical magnetic field B0B_{0}, as shown in the figure. Initially, it hangs vertically downwards, because of acceleration due to gravity gg, on two conducting supports at PP and QQ. When a current II is passed through the loop, the loop turns about the

    line PQ by an angle θ\theta given by

    Question 16 figure
    1. Option A:

      tan⁡θ=πrlBo/(mg)\tan \theta=\pi \mathrm{rlBo} /(\mathrm{mg})

    2. Option B:

      tan⁡θ=2πrlBo/(mg)\tan \theta=2 \pi \mathrm{rlBo} /(\mathrm{mg})

    3. Option C:

      tan⁡θ=πrlBo/(2mg)\tan \theta=\pi \mathrm{rlBo} /(2 \mathrm{mg})

    4. Option D:

      tan⁡θ=mg/(πrlBB0)\tan \theta=\mathrm{mg} /\left(\pi \mathrm{rlB} \mathrm{B}_{0}\right)

  17. Question 17Physics· Fluid Mechanics

    A table tennis ball has radius (3/2)×10−2 m(3 / 2) \times 10^{-2} \mathrm{~m} and mass (22/7)×10−3 kg(22 / 7) \times 10^{-3} \mathrm{~kg}. It is slowly pushed down into a swimming pool to a depth of d=0.7 m\mathrm{d}=0.7 \mathrm{~m} below the water surface and then released from rest. It emerges from the water surface at speed v, without getting wet, and rises up to a height H. Which of the following option(s) is(are) correct? [Given: m=22/7, g=10 ms−2\mathrm{m}=22 / 7, \mathrm{~g}=10 \mathrm{~ms}^{-2}, density of water =1×103kgm−3=1 \times 10^{3} \mathrm{kgm}^{-3}, viscosity of water =1×10−3 Pa=1 \times 10^{-3} \mathrm{~Pa}-s.]

    1. Option A:

      The work done in pushing the ball to the depth d is 0.077 J

    2. Option B:

      If we neglect the viscous force in water, then the speed v=7 m/sv=7 \mathrm{~m} / \mathrm{s}.

    3. Option C:

      If we neglect the viscous force in water, then the height H=1.4 m\mathrm{H}=1.4 \mathrm{~m}.

    4. Option D:

      The ratio of the magnitudes of the net force excluding the viscous force to the maximum viscous force in water is 500/9500 / 9.

  18. Question 18Physics· Moving Charges and Magnetic Field

    A positive, singly ionized atom of mass number AMA_{M} is accelerated from rest by the voltage 192 V . Thereafter, it enters a rectangular region of width ww with magnetic field B→0=0.1k^\overrightarrow{\mathrm{B}}_{0}=0.1 \hat{\mathrm{k}} Tesla, as shown in the figure. The ion finally hits a detector at the distance x below its starting trajectory. [Given: Mass of neutron/proton =(5/3)×10−27 kg=(5 / 3) \times 10^{-27} \mathrm{~kg}, charge of the electron =1.6×10−19C=1.6 \times 10^{-19} \mathrm{C}.] Which of the following option(s) is(are) correct?

    Question 18 figure
    1. Option A:

      The value of xx for H+\mathrm{H}^{+}ion is 4 cm

    2. Option B:

      The value of xx for an ion with Am=144A_{m}=144 is 48 cm

    3. Option C:

      For detecting ions with 1≤AM≤1961 \leq A_{M} \leq 196, the minimum height ( x1−x0x_{1}-x_{0} ) of the detector is 55 cm

    4. Option D:

      The minimum width ww of the region of the magnetic field for detecting ions with Am=196A_{m}=196 is 56 cm

  19. Question 19Physics· Units, Dimensions & Error Analysis

    The dimensions of a cone are measured using a scale with a least count of 2 mm . The diameter of the base and the height are both measured to be 20.0 cm . The maximum percentage error in the determination of the volume is

  20. Question 20Physics· Motion in Plane

    A ball is thrown from the location (x0,y0)=(0,0)\left(\mathrm{x}_{0}, \mathrm{y}_{0}\right)=(0,0) of a horizontal playground with an initial speed v0v_{0} at an angle θ0\theta_{0} from the +x+x-direction. The ball is to be hit by a stone, which is thrown at the same time from the location (x1,y1)=(L,0)\left(x_{1}, y_{1}\right)=(L, 0). The stone is thrown at an angle ( 180−θ1180-\theta_{1} ) from the +x+x-direction with a suitable initial speed. For a fixed v0v_{0}, when (θ0,θ1)=(45∘,45∘)\left(\theta_{0}, \theta_{1}\right)=\left(45^{\circ}, 45^{\circ}\right), the stone hits the ball after time T1\mathrm{T}_{1}, and when (θ0,θ1)=(60∘,30∘)\left(\theta_{0}, \theta_{1}\right)=\left(60^{\circ}, 30^{\circ}\right), it hits the ball after time T2\mathrm{T}_{2}. In such a case, (T1/T2)2\left(T_{1} / T_{2}\right)^{2} is _____\_\_\_\_\_

  21. Question 21Physics· Electrostatics

    A charge is kept at the central point PP of a cylindrical region. The two edges subtend a half-angle θ\theta at PP, as shown in the figure. When θ=30∘\theta=30^{\circ}, then the electric flux through the curved surface of the cylinder is Φ\Phi. If θ=60∘\theta=60^{\circ}, then the electric flux through the curved surface becomes ϕn\frac{\phi}{\sqrt{n}}, where the value of nn is _____\_\_\_\_\_

    Question 21 figure
  22. Question 22Physics· Geometrical Optics

    Two equilateral-triangular prisms P1P_{1} and P2P_{2} are kept with their sides parallel to each other, in vacuum, as shown in the figure. A light ray enters prism P1P_{1} at an angle of incidence θ\theta such that the outgoing ray undergoes minimum deviation in prism P2P_{2}. If the respective refractive indices of P1P_{1} and P2P_{2} are 32\sqrt{\frac{3}{2}} and 3\sqrt{3}, then θ=sin⁡−1[32sin⁡(πβ)]\theta=\sin ^{-1}\left[\sqrt{\frac{3}{2}} \sin \left(\frac{\pi}{\beta}\right)\right], where the value of β\beta is

    Question 22 figure
  23. Question 23Physics· Electrostatics

    An infinitely long thin wire, having a uniform charge density per unit length of 5nC/m5 \mathrm{nC} / \mathrm{m}, is passing through a spherical shell of radius 1 m , as shown in the figure. A 10 nC charge is distributed uniformly over the spherical shell. If the configuration of the charges remains static, the magnitude of the potential difference between points PP and RR, in Volt, is [Given: In SI units 14πε0=9×109,ln⁡2=0.7\frac{1}{4 \pi \varepsilon_{0}}=9 \times 10^{9}, \ln 2=0.7. Ignore the area pierced by the wire.]

    Question 23 figure
  24. Question 24Physics· Mechanical Properties of Matter

    A spherical soap bubble inside an air chamber at pressure P0=105 PaP_{0}=10^{5} \mathrm{~Pa} has a certain radius so that the excess pressure inside the bubble is ΔP=144 Pa\Delta \mathrm{P}=144 \mathrm{~Pa}. Now, the chamber pressure is reduced to 8P0/278 \mathrm{P}_{0} / 27 so that the bubble radius and its excess pressure change. In this process, all the temperatures remain unchanged. Assume air to be an ideal gas and the excess pressure ΔP\Delta P in both the cases to be much smaller than the chamber pressure. The new excess pressure ΔP\Delta P in Pa is

  25. Question 25Chemistry· Structure of Atom

    According to Bohr's model, the highest kinetic energy is associated with the electron in the

    1. Option A:

      first orbit of H atom

    2. Option B:

      first orbit of He+\mathrm{He}^{+}

    3. Option C:

      second orbit of He+\mathrm{He}^{+}

    4. Option D:

      second orbit of Li2+\mathrm{Li}^{2+}

  26. Question 26Chemistry· Periodicity of Elements and Periodic Properties

    In a metal deficient oxide sample, (M and Y are metals), M is present in both +2 and +3 oxidation states and Y\mathbf{Y} is in +3 oxidation state. If the fraction of M2+\mathbf{M}^{2+} ions present in M\mathbf{M} is 13\frac{1}{3}, the value of XX is \qquad

    1. Option A:

      0.25

    2. Option B:

      0.33

    3. Option C:

      0.67

    4. Option D:

      0.75

  27. Question 27Chemistry· Biomolecules

    In the following reaction sequence, the major product Q\mathbf{Q} is

    L-Glucose→ii) CuO, 775 K, 10–20 atmi) H, ΔP→UVCl2 (excess)Q\text{L-Glucose} \xrightarrow[\text{ii) CuO, }775\,\text{K},\ 10\text{--}20\,\text{atm}] {\text{i) H, }\Delta} P \xrightarrow[\mathrm{UV}] {\mathrm{Cl_2\ (excess)}} Q
    1. Option A:

      structure

    2. Option B:

      structure

    3. Option C:

      structure

    4. Option D:

      structure

  28. Question 28Chemistry· p-Block Elements (Group 15-18)

    The species formed on fluorination of phosphorus pentachloride in a polar organic solvent are

    1. Option A:

      [PF4]+[PF6]−\left[\mathrm{PF}_{4}\right]^{+}\left[\mathrm{PF}_{6}\right]^{-}and [PCl4]+[PF6]\left[\mathrm{PCl}_{4}\right]^{+}\left[\mathrm{PF}_{6}\right]

    2. Option B:

      [PCl4]+[PCl4 F2]−\left[\mathrm{PCl}_{4}\right]^{+}\left[\mathrm{PCl}_{4} \mathrm{~F}_{2}\right]^{-}and [PCl4]+[PF6]−\left[\mathrm{PCl}_{4}\right]^{+}\left[\mathrm{PF}_{6}\right]^{-}

    3. Option C:

      PF3\mathrm{PF}_{3} and PCl3\mathrm{PCl}_{3}

    4. Option D:

      PF5\mathrm{PF}_{5} and PCl3\mathrm{PCl}_{3}

  29. Question 29Chemistry· p-Block Elements (Group 15-18)

    The compound(s) having peroxide linkage is(are)

    1. Option A:

      H2 S2O7\mathrm{H}_{2} \mathrm{~S}_{2} \mathrm{O}_{7}

    2. Option B:

      H2 S2O8\mathrm{H}_{2} \mathrm{~S}_{2} \mathrm{O}_{8}

    3. Option C:

      H2 S2O5\mathrm{H}_{2} \mathrm{~S}_{2} \mathrm{O}_{5}

    4. Option D:

      H2SO5\mathrm{H}_{2} \mathrm{SO}_{5}

  30. Question 30Chemistry· Surface Chemistry

    To form a complete monolayer of acetic acid on 1 g of charcoal, 100 mL of 0.5 M acetic acid was used. Some of the acetic acid remained unadsorbed. To neutralize the unadsorbed acetic acid, 40 mL of 1 M NaOH solution was required. If each molecule of acetic acid occupies P×10−23 m2\mathbf{P} \times 10^{-23} \mathrm{~m}^{2} surface area on charcoal, the value of P\mathbf{P} is _____\_\_\_\_\_ _. [Use given data : Surface area of charcoal =1.5×102 m2 g−1=1.5 \times 10^{2} \mathrm{~m}^{2} \mathrm{~g}^{-1}; Avogadro's number (NA)=6.0×1023 mol−1\left(N_{A}\right)=6.0 \times 10^{23} \mathrm{~mol}^{-1} ]

  31. Question 31Chemistry· Solutions and Colligative Properties

    Vessel-1 contains w2g\mathbf{w}_{\mathbf{2}} \mathrm{g} of a non-volatile solute X\mathbf{X} dissolved in w1g\mathbf{w}_{\mathbf{1}} \mathrm{g} of water. Vessel-2 contains w2\mathbf{w}_{\mathbf{2}} gg of another non-volatile solute Y\mathbf{Y} dissolved in w1 g\mathbf{w}_{1} \mathrm{~g} of water. Both the vessels are at the same temperature and pressure. The molar mass of X\mathbf{X} is 80%80 \% of that of Y\mathbf{Y}. The van't Hoff factor for X\mathbf{X} is 1.2 times of that of Y\mathbf{Y} for their respective concentrations.

    The elevation of boiling point for solution in Vessel-1 is _____\_\_\_\_\_ % of the solution in Vessel-2.

  32. Question 32Chemistry· Biomolecules

    For a double strand DNA, one strand is given below: The amount of energy required to split the double strand DNA into two single strands is _____\_\_\_\_\_ kcalmol−1\mathrm{kcal} \mathrm{mol}^{-1}. [Given: Average energy per H-bond for A-T base pair =1.0kcalmol−1=1.0 \mathrm{kcal} \mathrm{mol}^{-1}, G-C base pair =1.5kcal=1.5 \mathrm{kcal} mol−1\mathrm{mol}^{-1}, and A-U base pair =1.25kcalmol−1=1.25 \mathrm{kcal} \mathrm{mol}^{-1}. Ignore electrostatic repulsion between the phosphate groups.]

    Question 32 figure
  33. Question 33Chemistry· Coordination Compounds

    Among [Co(CN)4]4−,[Co(CO)3(NO)],XeF4,[PCl4]+,[PdCl4]2−,[ICl]−,[Cu(CN)4]3−\left[\mathrm{Co}(\mathrm{CN})_{4}\right]^{4-},\left[\mathrm{Co}(\mathrm{CO})_{3}(\mathrm{NO})\right], \mathrm{XeF}_{4},\left[\mathrm{PCl}_{4}\right]^{+},\left[\mathrm{PdCl}_{4}\right]^{2-},[\mathrm{ICl}]^{-},\left[\mathrm{Cu}(\mathrm{CN})_{4}\right]^{3-} and P4\mathrm{P}_{4} the total number of species with tetrahedral geometry is _____\_\_\_\_\_ -.

  34. Question 34Chemistry· Aldehydes and Ketones

    An organic compound PP having molecular formula C6H6O3\mathrm{C}_{6} \mathrm{H}_{6} \mathrm{O}_{3} gives ferric chloride test and does not have intramolecular hydrogen bond. The compound P\mathbf{P} reacts with 3 equivalents of NH2OH\mathrm{NH}_{2} \mathrm{OH} to produce oxime Q\mathbf{Q}. Treatment of P\mathbf{P} with excess methyl iodide in the presence of KOH produces compound R\mathbf{R} as the major product. Reaction of R\mathbf{R} with excess iso-butylmagnesium bromide followed by treatment with H3O+\mathrm{H}_{3} \mathrm{O}^{+}gives compound S\mathbf{S} as the major product. The total number of methyl (−CH3)\left(-\mathrm{CH}_{3}\right)

    group(s) in compound S\mathbf{S} is \qquad

  35. Question 35Chemistry· Chemical Kinetics

    A sample initially contains only U-238 isotope of uranium. With time, some of the U-238 radioactively decays into Pb−206\mathrm{Pb}-206 while the rest of it remains undisintegrated. When the age of the sample is P×108\mathbf{P} \times 10^8 years, the ratio of mass of Pb-206 to that of U-238 in the sample is found to be 7. The value of P\mathbf{P} is \qquad ………. [Given: Half-life of U-238 is 4.5×1094.5 \times 10^9 years; log⁡e2=0.693\log _{\mathrm{e}} 2=0.693 ]

  36. Question 36Mathematics· Functions

    Let S={1,2,3,4,5,6}S=\{1,2,3,4,5,6\} and XX be the set of all relations RR from SS to SS that satisfy both the following properties: i. R\quad \mathrm{R} has exactly 6 elements. ii. For each (a,b)∈R(a, b) \in R,we have ∣a−b∣≥2|a-b| \geq 2. Let Y={R∈XY=\{R \in X : The range of RR has exactly one element }\} and Z={R∈X:RZ=\{R \in X: R is a function from SS to S}S\}. Let n(A)n(A) denote the number of elements in a set AA. (There are two questions based on PARAGRAPH "I", the question given below is one of them)

    If n(X)=mC6n(X)={ }^{m} C_{6}, then the value of mm is \qquad

  37. Question 37Mathematics· Functions

    If the value of n(Y)+n(Z)n(Y)+n(Z) is k2k^{2}, then ∣k∣|k| is \qquad

  38. Question 38Mathematics· Definite Integration

    Let f:[0,π2]→[0,1]f:\left[0, \frac{\pi}{2}\right] \rightarrow[0,1] be the function defined by f(x)=sin⁡2xf(x)=\sin ^{2} x and let g:[0,π2]→[0,∞)g:\left[0, \frac{\pi}{2}\right] \rightarrow[0, \infty) be the function defined by g=πx2−x2g=\sqrt{\frac{\pi x}{2}-x^{2}}.

    The value of 2∫0π2f(x)g(x)dx−∫0π2g(x)dx2 \int_{0}^{\frac{\pi}{2}} f(x) g(x) d x-\int_{0}^{\frac{\pi}{2}} g(x) d x is \qquad

  39. Question 39Mathematics· Definite Integration

    Let f:[0,π2]→[0,1]f:\left[0, \frac{\pi}{2}\right] \rightarrow[0,1] be the function defined by f(x)=sin⁡2xf(x)=\sin ^{2} x and let g:[0,π2]→[0,∞)g:\left[0, \frac{\pi}{2}\right] \rightarrow[0, \infty) be the function defined by g=πx2−x2g=\sqrt{\frac{\pi x}{2}-x^{2}}.

    The value of 16π3∫0π2f(x)g(x)dx\frac{16}{\pi^{3}} \int_{0}^{\frac{\pi}{2}} f(x) g(x) d x is \qquad

  40. Question 40Physics· Wave Optics

    In a Young's double slit experiment, each of the two slits A and B, as shown in the figure, are oscillating about their fixed center and with a mean separation of 0.8 mm . The distance between the slits at time tt is given by d=(0.8+0.04sin⁡ωt)mm\mathrm{d}=(0.8+0.04 \sin \omega \mathrm{t}) \mathrm{mm}, where ω=0.08rads−1\omega=0.08 \mathrm{rads}^{-1}. The distance of the screen from the slits is 1 m and the wavelength of the light used to illuminate the slits is 6000AA6000 AA. The interference pattern on the screen changes with time,while the central bright fringe (zeroth fringe) remains fixed at point O

    The 8th 8^{\text {th }} bright fringe above the point O oscillates with time between two extreme positions. The separation between these two extreme positions, in micrometer ( μm\mu \mathrm{m} ), is

    Question 40 figure
  41. Question 41Physics· Wave Optics

    The maximum speed in μm/s\mu \mathrm{m} / \mathrm{s} at which the 8th 8^{\text {th }} bright fringe will move is

    Question 41 figure
  42. Question 42Physics· System Of Particles

    Two particles, 1 and 2 , each of mass mm, are connected by a massless spring, and are on a horizontal frictionless plane, as shown in the figure. Initially, the two particles, with their center of mass at x0x_{0}, are oscillating with amplitude a and angular frequency ω\omega. Thus, their positions at time tt are given by x1(t)=(x0+d)+asin⁡ωtx_{1}(t)=\left(x_{0}+d\right)+a \sin \omega t and x2(t)=(x0−d)−asin⁡ωtx_{2}(t)=\left(x_{0}-d\right)-a \sin \omega t, respectively, where d>2ad>2 a. Particle 3 of mass mm moves towards this system with speed u0=aω/2u_{0}=a \omega / 2, and undergoes instantaneous elastic collision with particle 2, at time t0t_{0}. Finally, particles 1 and 2 acquire a center of mass speed vcm\mathrm{v}_{\mathrm{cm}} and oscillate with amplitude b and the same angular frequency ω\omega.

    If the collision occurs at time t0=π/(2ω)t_{0}=\pi /(2 \omega), then the value of 4b2/a24 b^{2} / a^{2} will be

  43. Question 43Chemistry· Aldehydes and Ketones

    An organic compound P\mathbf{P} with molecular formula C9H18O2\mathrm{C}_{9} \mathrm{H}_{18} \mathrm{O}_{2} decolorizes bromine water and also shows positive iodoform test. P\mathbf{P} on ozonolysis followed by treatment with H2O2\mathrm{H}_{2} \mathrm{O}_{2} gives Q\mathbf{Q} and R\mathbf{R}. While compound Q\mathbf{Q} shows positive iodoform test, compound R\mathbf{R} does not give positive iodoform test. Q\mathbf{Q} and R\mathbf{R} on oxidation with pyridinium chlorochromate (PCC) followed by heating give S\mathbf{S} and T\mathbf{T}, respectively. Both S\mathbf{S} and T\mathbf{T} show positive iodoform test. Complete copolymerization of 500 moles of Q\mathbf{Q} and 500 moles of R\mathbf{R} gives one mole of a single acyclic copolymer U. [Given, atomic mass: H=1,C=12,O=16\mathrm{H}=1, \mathrm{C}=12, \mathrm{O}=16 ]

    The molecular weight of U\mathbf{U} is

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