Physics · Units, Dimensions & Error Analysis

JEE Advanced 2024 — Paper 2 — Question 19

The dimensions of a cone are measured using a scale with a least count of 2 mm . The diameter of the base and the height are both measured to be 20.0 cm . The maximum percentage error in the determination of the volume is

Answer: 3

Numerical answer — enter this value.

Step-by-step solution

Percentage error in Volume $\frac{\Delta \mathrm{V}}{\mathrm{V}} \times 100=2 \frac{\Delta \mathrm{~d}}{\mathrm{~d}} \times 100+\frac{\Delta \mathrm{h}}{\mathrm{h}} \times 100 \quad\left(\frac{\Delta \mathrm{~d}}{\mathrm{~d}}=\frac{\Delta \mathrm{h}}{\mathrm{h}}=\frac{1}{100}\right)$ $\Rightarrow \frac{\Delta \mathrm{V}}{\mathrm{V}} \times 100=3 \%$

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Exam: JEE Advanced 2024
Paper: Paper 2
Subject: Physics
Chapter: Units, Dimensions & Error Analysis
Topic: Significant Figures and Error Analysis