Mathematics · Functions

JEE Advanced 2024 — Paper 2 — Question 37

If the value of $n(Y)+n(Z)$ is $k^{2}$ , then $|k|$ is $\qquad$

Answer: 36

Numerical answer — enter this value.

Step-by-step solution

$\quad n(Y)=0$ , as no relation $R$ have only one element as its range $n(Z)=4 \times 3 \times 3 \times 3 \times 3 \times 4=1296$ as $\mathrm{n}(\mathrm{Y})+\mathrm{n}(\mathrm{Z})=\mathrm{k}^{2}=1296$ $\therefore \mathrm{k}=36$

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Exam: JEE Advanced 2024
Paper: Paper 2
Subject: Mathematics
Chapter: Functions
Topic: One-One, many-one, onto, into, bijective functions

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Answer: 36

Step-by-step solution

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