Mathematics · Functions

JEE Advanced 2024 — Paper 2 — Question 36

Let S={1,2,3,4,5,6}S=\{1,2,3,4,5,6\} and XX be the set of all relations RR from SS to SS that satisfy both the following properties: i. R\quad \mathrm{R} has exactly 6 elements. ii. For each (a,b)∈R(a, b) \in R,we have ∣a−b∣≥2|a-b| \geq 2. Let Y={R∈XY=\{R \in X : The range of RR has exactly one element }\} and Z={R∈X:RZ=\{R \in X: R is a function from SS to S}S\}. Let n(A)n(A) denote the number of elements in a set AA. (There are two questions based on PARAGRAPH "I", the question given below is one of them)

If n(X)=mC6n(X)={ }^{m} C_{6}, then the value of mm is \qquad

Answer: 20

Numerical answer — enter this value.

Step-by-step solution

Total elements in relation R0\mathrm{R}_{0} such that ∣a−b∣≥2|\mathrm{a}-\mathrm{b}| \geq 2 are 20 {(1,3),(1,4)(1,5)(1,6)(2,4)(2,5)(2,6),(3,1)(3,5),(3,6)(4,1)(4,2)(4,6),(5,1)(5,2)\{(1,3),(1,4)(1,5)(1,6)(2,4)(2,5)(2,6),(3,1)(3,5),(3,6)(4,1)(4,2)(4,6),(5,1)(5,2) (5,3),(6,1)(6,2)(6,3),(6,4)}(5,3),(6,1)(6,2)(6,3),(6,4)\} But XX is set of all subsets of Ro which have exactly 6 elements n(X)=20C6;20C6=mC6⇒ m=20\mathrm{n}(\mathrm{X})={ }^{20} \mathrm{C}_{6} ;{ }^{20} \mathrm{C}_{6}={ }^{\mathrm{m}} \mathrm{C}_{6} \Rightarrow \mathrm{~m}=20

Answer key and solution verified before publishing.

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Exam
JEE Advanced 2024
Paper
Paper 2
Subject
Mathematics
Chapter
Functions
Topic
One-One, many-one, onto, into, bijective functions
Let S=\ 1,2,3,4,5,6\ and X be the set of all relations R from S to S… | JEE Advanced 2024 PYQ with Solution · DhiX AI