For a double strand DNA, one strand is given below: The amount of energy required to split the double strand DNA into two single strands is \ \ \ \ \ kcal mol -1 . [Given: Average energy per H-bond for A-T base pair =1.0 kcal mol -1 , G-C base pair =1.5 kcal mol -1 , and A-U base pair =1.25 kcal mol -1 . Ignore electrostatic repulsion between the phosphate groups.]

Chemistry · Biomolecules

JEE Advanced 2024 — Paper 2 — Question 32

For a double strand DNA, one strand is given below: The amount of energy required to split the double strand DNA into two single strands is $\_\_\_\_\_$ $\mathrm{kcal} \mathrm{mol}^{-1}$ . [Given: Average energy per H-bond for A-T base pair $=1.0 \mathrm{kcal} \mathrm{mol}^{-1}$ , G-C base pair $=1.5 \mathrm{kcal}$ $\mathrm{mol}^{-1}$ , and A-U base pair $=1.25 \mathrm{kcal} \mathrm{mol}^{-1}$ . Ignore electrostatic repulsion between the phosphate groups.]

Answer: 41

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Step-by-step solution

Seven A, T and Six G, C pairs are there. Energy required $=7 \times 2 \times 1+6 \times 3 \times 1.5=41 \mathrm{kcal}$

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Exam: JEE Advanced 2024
Paper: Paper 2
Subject: Chemistry
Chapter: Biomolecules
Topic: Nucleic Acids and Other Biomolecules

In the following reaction sequence, the major product Q is L-Glucose xrightarrow[ ii) CuO, 775 K,\ 10 --20 atm] i) H, Delta P xrightarrow[…

Answer: 41

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