Physics · Electrostatics

JEE Main 2026 — 2 April, Morning Shift — Question 9

Two short electric dipoles A and B having dipole moment $\mathbf{p}_1$ and $\mathbf{p}_2$ respectively are placed with their axis mutually perpendicular as shown in the figure. The resultant electric field at a point $\mathbf{x}$ is making an angle of $60^{\circ}$ with the line joining points O and $\mathbf{x}$ . The ratio of the dipole moments $\mathbf{p}_2 / \mathbf{p}_1$ is ______.

Option A:
$\frac{\sqrt{3}}{2}$
Option B:
$2\sqrt{3}$
Correct
Option C:
$\frac{1}{\sqrt{3}}$
Option D:
$\sqrt{3}$

Answer: B

Step-by-step solution

$\vec{\mathrm{E}}_{\mathrm{A}} = \frac{2\mathrm{kP}_{1}}{\mathrm{x}^{3}}\left(-\hat{\mathrm{i}}\right)$ , $\vec{\mathrm{E}}_{\mathrm{B}} = \frac{\mathrm{kP}_{2}}{\mathrm{x}^{3}}\left(-\hat{\mathrm{j}}\right)$ , $\tan 60^{\circ} = \frac{\mathrm{P}_{2}}{2\mathrm{P}_{1}}$ → $\frac{\mathrm{P}_{2}}{\mathrm{P}_{1}} = 2\sqrt{3}$

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Exam: JEE Main 2026
Paper: 2 April, Morning Shift
Subject: Physics
Chapter: Electrostatics
Topic: Electric Dipole

Two charged conducting spheres S 1 and S 2 of radii 8 cm and 18 cm are connected to each other by a wire. After equilibrium is established…

Answer: B

Step-by-step solution

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