The equation of a plane progressive wave is given by y = 5cos π (200 t - frac x 150 ) where x and y are in cm and t is in second. The velocity of the wave is m/s

Physics · Sound Waves

JEE Main 2026 — 2 April, Morning Shift — Question 8

The equation of a plane progressive wave is given by $\mathrm{y} = 5\cos \pi \left(200\mathrm{t} - \frac{\mathrm{x}}{150}\right)$ where $\mathbf{x}$ and $\mathbf{y}$ are in cm and t is in second. The velocity of the wave is m/s

Option A:
120
Option B:
150
Option C:
200
Option D:
300
Correct

Answer: D

Step-by-step solution

$\mathrm{v} = \frac{\mathrm{coeff~of~t}}{\mathrm{coeff~of~x}} = \frac{200}{\frac{1}{150}\times 100} = 300\mathrm{m / s}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 2 April, Morning Shift
Subject: Physics
Chapter: Sound Waves
Topic: Introduction, Equation of Sound Waves as Pressure Wave