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Physics · Electromagnetic Induction

JEE Main 2026 — 2 April, Morning Shift — Question 10

When a coil is placed in a time dependent magnetic field the power dissipated in it is P. The number of turns, area of the coil and radius of the coil wire are N, A and r respectively. For a second coils number of turns, area of the coil and radius of the coil wire are 2N, 2A and 3r respectively. When the first coil is replaced with second coil the power dissipated in it is 2αP\sqrt{2}\alpha \mathrm{P} . The value of α\alpha is

  1. Option A:

    36

    Correct
  2. Option B:

    128√2

  3. Option C:

    16

  4. Option D:

    64

Answer: A

Step-by-step solution

P∝NA3/2r2\mathrm{P}\propto \mathrm{NA}^{3 / 2}\mathrm{r}^2 → P′P=362\frac{P'}{P} = 36\sqrt{2} → α=36\alpha = 36

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
2 April, Morning Shift
Subject
Physics
Chapter
Electromagnetic Induction
Topic
Magnetic Flux, Faraday's Law and Lenz's Law
When a coil is placed in a time dependent magnetic field the power… | JEE Main 2026 PYQ with Solution · DhiX AI