Physics · Atomic Physics

JEE Main 2025 — 3 April, Morning Shift — Question 52

The work function of a metal is 3 eV . The color of the visible light that is required to cause emission of photoelectrons is

Answer: D

$\lambda=\frac{12400}{3} Å=4133 Å$

and $\lambda_{\text {visible }} \in(3800-7600) Å$

                                                    VIBGYOR

Therefore, most appropriate response is blue.

Answer key and solution verified before publishing.

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