Physics · Units, Dimensions & Error Analysis

JEE Main 2025 — 3 April, Morning Shift — Question 53

Match the List-I with List-II Choose the correct answer from the options given below:

List-IList-II
A.Gravitational constantI.[LT−2]\left[ \text{L}{{\text{T}}^{-2}} \right]
B.Gravitational potential energyII.[L2  ⁣ ⁣  ⁣ ⁣ T−2]\left[ {{\text{L}}^{2}}\text{ }\!\!~\!\!\text{ }{{\text{T}}^{-2}} \right]
C.Gravitational potentialIII.[ML2  ⁣ ⁣  ⁣ ⁣ T−2]\left[ \text{M}{{\text{L}}^{2}}\text{ }\!\!~\!\!\text{ }{{\text{T}}^{-2}} \right]
D.Acceleration due to gravityIV.[M−1  ⁣ ⁣  ⁣ ⁣ L3  ⁣ ⁣  ⁣ ⁣ T−2]\left[ {{\text{M}}^{-1}}\text{ }\!\!~\!\!\text{ }{{\text{L}}^{3}}\text{ }\!\!~\!\!\text{ }{{\text{T}}^{-2}} \right]
  1. Option A:

    A-II, B-IV, C-III, D-I

  2. Option B:

    A-IV, B-III, C-II, D-I

    Correct
  3. Option C:

    A-I, B-III, C-IV, D-II

  4. Option D:

    A-III, B-II, C-I, D-IV

Answer: B

Step-by-step solution

(A) F=Gm2r2≡G=Fr2m2≡MLT−2L2M2=M−1L3T−2F=\frac{G m^{2}}{r^{2}} \equiv G=\frac{F r^{2}}{m^{2}} \equiv \frac{M L T^{-2} L^{2}}{M^{2}}=M^{-1} L^{3} T^{-2}

A→IVA \rightarrow \mathrm{IV}

(B) G.PE≡G . P E \equiv Energy ≡ML2T−2\equiv M L^{2} T^{-2}

B→ III B \rightarrow \text { III }

(C) G.P=mghm=gh≡V2≡L2T−2G . P=\frac{m g h}{m}=g h \equiv V^{2} \equiv L^{2} T^{-2}

C→IC \rightarrow I

(D) g≡LT−2g \equiv L T^{-2} D →\rightarrow I

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Physics
Chapter
Units, Dimensions & Error Analysis
Topic
Units and Dimensions Analysis
Match the List-I with List-II Choose the correct answer from the… | JEE Main 2025 PYQ with Solution · DhiX AI