Physics · Atomic Physics

JEE Main 2024 — 30 January, Shift 1 — Question 34

The ratio of the magnitude of the kinetic energy to the potential energy of an electron in the $5^{\text {th }}$ excited state of a hydrogen atom is :

Option A:
4
Option B:
$\frac{1}{4}$
Option C:
$\frac{1}{2}$
Correct
Option D:
1

Answer: C

Step-by-step solution

$\quad \frac{1}{2}|P E|=K E$ for each value of n (orbit)

$\therefore \frac{K E}{|P E|}=\frac{1}{2}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 30 January, Shift 1
Subject: Physics
Chapter: Atomic Physics
Topic: Hydrogen Spectrum

The work function of a substance is 3.0 eV . The longest wavelength of light that can cause the emission of photoelectrons from this…
A electron of hydrogen atom on an excited state is having energy E n=-0.85 eV . The maximum number of allowed transitions to lower energy…

Answer: C

Step-by-step solution

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