A electron of hydrogen atom on an excited state is having energy E n =-0.85 eV . The maximum number of allowed transitions to lower energy level is \ \ \ \ \ \ \ .

Physics · Atomic Physics

JEE Main 2024 — 30 January, Shift 1 — Question 48

A electron of hydrogen atom on an excited state is having energy $\mathrm{E}_{\mathrm{n}}=-0.85 \mathrm{eV}$ . The maximum number of allowed transitions to lower energy level is $\_\_\_\_\_\_\_$ .

Answer: 6

Numerical answer — enter this value.

Step-by-step solution

$E_{n}=-\frac{13.6}{n^{2}}=-0.85$

$\Rightarrow n=4$

No of transition $=\frac{n(n-1)}{2}=\frac{4(4-1)}{2}=6$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 30 January, Shift 1
Subject: Physics
Chapter: Atomic Physics
Topic: Hydrogen Spectrum

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Step-by-step solution

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