Physics · Atomic Physics

JEE Main 2024 — 30 January, Shift 1 — Question 33

The work function of a substance is 3.0 eV . The longest wavelength of light that can cause the emission of photoelectrons from this substance is approximately:

Option A:
215 nm
Option B:
414 nm
Correct
Option C:
400 nm
Option D:
200 nm

Answer: B

Step-by-step solution

For P.E.E. : $\lambda \leq \frac{h c}{W_{e}}$ $\lambda \leq \frac{1240 \mathrm{~nm}-\mathrm{eV}}{3 \mathrm{eV}}$ $\lambda \leq 413.33 \mathrm{~nm}$ $\lambda_{\max } \approx 414 \mathrm{~nm}$ for P.E.E.

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Exam: JEE Main 2024
Paper: 30 January, Shift 1
Subject: Physics
Chapter: Atomic Physics
Topic: Photoelectric Effect

The ratio of the magnitude of the kinetic energy to the potential energy of an electron in the 5^ th excited state of a hydrogen atom is :
A electron of hydrogen atom on an excited state is having energy E n=-0.85 eV . The maximum number of allowed transitions to lower energy…

Answer: B

Step-by-step solution

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