The electric field of an electromagnetic wave in free space is represented as vec E =E 0 cos (ω t-k z) hat i . The corresponding magnetic induction vector will be :

vec B =frac E 0 C cos (ω t-k z) hat j

vec B =E 0 C cos (ω t-k z) hat j

vec B =E 0 C cos (ω t+k z) hat j

vec B =frac E 0 C cos (ω t+k z) hat j

Physics · Electromagnetic Waves

JEE Main 2024 — 30 January, Shift 1 — Question 35

The electric field of an electromagnetic wave in free space is represented as $\vec{E}=E_{0} \cos (\omega t-k z) \hat{i}$ . The corresponding magnetic induction vector will be :

Option A:
$\vec{B}=E_{0} C \cos (\omega t-k z) \hat{j}$
Option B:
$\vec{B}=\frac{E_{0}}{C} \cos (\omega t-k z) \hat{j}$
Correct
Option C:
$\vec{B}=E_{0} C \cos (\omega t+k z) \hat{j}$
Option D:
$\vec{B}=\frac{E_{0}}{C} \cos (\omega t+k z) \hat{j}$

Answer: B

Step-by-step solution

Given $\vec{E}=E_{0} \cos (\omega t-k z) \hat{i}$ $\vec{B}=\frac{E_{0}}{C} \cos (\omega t-k z) \hat{j}$

$\hat{C}=\hat{E} \times \hat{B}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 30 January, Shift 1
Subject: Physics
Chapter: Electromagnetic Waves
Topic: Displacement Current and Equation of EM Waves