Physics · Units, Dimensions & Error Analysis

JEE Main 2025 — 2 April, Morning Shift — Question 51

The equation for real gas is given by $\left(P+\frac{a}{V^{2}}\right)(V-b)=R T$ , where $P, V, T$ and $R$

are the pressure, volume, temperature and gas constant, respectively. The dimension of $a b^{-2}$

is equivalent to that of

Answer: D

$P \equiv \frac{a}{V^{2}}$ $a \equiv P V^{2}$ $b \equiv V$ $\frac{a}{b^{2}} \equiv P$ Dimensions of $P$ is same as energy density.

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