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Physics · Units, Dimensions & Error Analysis

JEE Main 2025 — 2 April, Morning Shift — Question 54

Match List-I with List-II. Choose the correct answer from the options given below.

LIST-ILIST-II
(A)Coefficient of viscosity(I)[ML0  ⁣ ⁣  ⁣ ⁣ T−3]\left[ \text{M}{{\text{L}}^{0}}\text{ }\!\!~\!\!\text{ }{{\text{T}}^{-3}} \right]
(B)Intensity of wave(II)[ML−2  ⁣ ⁣  ⁣ ⁣ T−2]\left[ \text{M}{{\text{L}}^{-2}}\text{ }\!\!~\!\!\text{ }{{\text{T}}^{-2}} \right]
(C)Pressure gradient(III)[M−1LT2]\left[ {{\text{M}}^{-1}}\text{L}{{\text{T}}^{2}} \right]
(D)Compressibility(IV)[ML−1  ⁣ ⁣  ⁣ ⁣ T−1]\left[ \text{M}{{\text{L}}^{-1}}\text{ }\!\!~\!\!\text{ }{{\text{T}}^{-1}} \right]
  1. Option A:

    (A)-(IV), (B)-(I), (C)-(II), (D)-(III)

    Correct
  2. Option B:

    (A)-(II), (B)-(III), (C)-(IV), (D)-(I)

  3. Option C:

    (A)-(IV), (B)-(II), (C)-(I), (D)-(III)

  4. Option D:

    (A)-(I), (B)-(IV), (C)-(III), (D)-(II)

Answer: A

Step-by-step solution

η≡FrV≡[ML−1 T−1]A→IV\eta \equiv \frac{F}{r V} \equiv\left[\mathrm{ML}^{-1} \mathrm{~T}^{-1}\right] \quad \mathrm{A} \rightarrow \mathrm{IV}

I≡PA≡[MT−3]B→IdPdx≡[ML−2 T−2]C→ II K≡1P≡[M−1LT2]D→ III \begin{array}{ll}I \equiv \frac{P}{A} \equiv\left[\mathrm{MT}^{-3}\right] & \mathrm{B} \rightarrow \mathrm{I} \\ \frac{d P}{d x} \equiv\left[\mathrm{ML}^{-2} \mathrm{~T}^{-2}\right] & \mathrm{C} \rightarrow \text { II } \\ K \equiv \frac{1}{P} \equiv\left[\mathrm{M}^{-1} \mathrm{LT}^{2}\right] & \mathrm{D} \rightarrow \text { III }\end{array}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
2 April, Morning Shift
Subject
Physics
Chapter
Units, Dimensions & Error Analysis
Topic
Units and Dimensions Analysis

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