Physics · Magnetism and Matter

JEE Main 2025 — 2 April, Morning Shift — Question 52

The relationship between the magnetic susceptibility (χ)(\chi) and the magnetic permeability (μ)(\mu) is

given by: ( μ0\mu_{0} is the permeability of free space and μr\mu_{r} is relative permeability)

  1. Option A:

    χ=μr+1\chi=\mu_{r}+1

  2. Option B:

    χ=μμ0−1\chi=\frac{\mu}{\mu_{0}}-1

    Correct
  3. Option C:

    χ=μrμ0+1\chi=\frac{\mu_{r}}{\mu_{0}}+1

  4. Option D:

    χ=1−μμ0\chi=1-\frac{\mu}{\mu_{0}}

Answer: B

Step-by-step solution

μ=μrμ0\mu=\mu_{r} \mu_{0} μr=(χ+1)\mu_{r}=(\chi+1) μ=(χ+1)μ0\mu=(\chi+1) \mu_{0} χ=(μμ0−1)\chi=\left(\frac{\mu}{\mu_{0}}-1\right)

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Physics
Chapter
Magnetism and Matter
Topic
Magnetization and Magnetic Intensity, Hysteresis
The relationship between the magnetic susceptibility (chi) and the… | JEE Main 2025 PYQ with Solution · DhiX AI