Physics · Units, Dimensions & Error Analysis

JEE Main 2024 — 9 April, Shift 1 — Question 39

The dimensional formula of latent heat is:

Option A:
$\left[\mathrm{M}^{0} \mathrm{LT}^{-2}\right]$
Option B:
$\left[\mathrm{MLT}^{-2}\right]$
Option C:
$\left[\mathrm{M}^{0} \mathrm{~L}^{2} \mathrm{~T}^{-2}\right]$
Correct
Option D:
$\left[\mathrm{ML}^{2} \mathrm{~T}^{-2}\right]$

Answer: C

Step-by-step solution

Latent heat is specific heat $\Rightarrow \frac{\mathrm{ML}^{2} \mathrm{~T}^{-2}}{\mathrm{M}}=\mathrm{M}^{0} \mathrm{~L}^{2} \mathrm{~T}^{-2}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 9 April, Shift 1
Subject: Physics
Chapter: Units, Dimensions & Error Analysis
Topic: Units and Dimensions Analysis

One main scale division of a vernier caliper is equal to m units. If n^ th division of main scale coincides with ( n+1)^ th division of…

The dimensional formula of latent heat is: | JEE Main 2024 PYQ with Solution · DhiX AI