A light unstretchable string passing over a smooth light pulley connects two blocks of masses m 1 and m 2 . If the acceleration of the system is frac g 8 , then the ratio of the masses frac m 2 m 1 is:

Physics · Newton's Laws of Motion

JEE Main 2024 — 9 April, Shift 1 — Question 38

A light unstretchable string passing over a smooth light pulley connects two blocks of masses $m_{1}$ and $\mathrm{m}_{2}$ . If the acceleration of the system is $\frac{\mathrm{g}}{8}$ , then the ratio of the masses $\frac{\mathrm{m}_{2}}{\mathrm{~m}_{1}}$ is:

Option A:
$9: 7$
Correct
Option B:
$4: 3$
Option C:
$5: 3$
Option D:
$8: 1$

Answer: A

Step-by-step solution

$\quad a_{\text {sys }}=\left(\frac{m_{2}-m_{1}}{m_{1}+m_{2}}\right) g=\frac{g}{8}$

$\Rightarrow \frac{\mathrm{m}_{2}}{\mathrm{~m}_{1}}=\frac{9}{7}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 9 April, Shift 1
Subject: Physics
Chapter: Newton's Laws of Motion
Topic: Pulley - Block Problems