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Physics · Thermodynamics

JEE Main 2024 — 9 April, Shift 1 — Question 40

The volume of an ideal gas (γ=1.5)(\gamma=1.5) is changed adiabatically from 5 litres to 4 litres. The ratio of initial pressure to final pressure is:

  1. Option A:

    45\frac{4}{5}

  2. Option B:

    1625\frac{16}{25}

  3. Option C:

    855\frac{8}{5 \sqrt{5}}

    Correct
  4. Option D:

    25\frac{2}{\sqrt{5}}

Answer: C

Step-by-step solution

For Adiabatic process

PiVi=PfVfγP_{i} V_{i}=P_{f} V_{f}^{\gamma}

Pi(5)1.5=Pf(4)1.5P_{i}(5)^{1.5}=P_{f}(4)^{1.5}

PiPf=(45)32=45⋅(45)12⇒855\frac{\mathrm{P}_{\mathrm{i}}}{\mathrm{P}_{\mathrm{f}}}=\left(\frac{4}{5}\right)^{\frac{3}{2}}=\frac{4}{5} \cdot\left(\frac{4}{5}\right)^{\frac{1}{2}} \Rightarrow \frac{8}{5 \sqrt{5}}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
9 April, Shift 1
Subject
Physics
Chapter
Thermodynamics
Topic
Different Thermodynamic Processes

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