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Physics · Magnetism and Matter

JEE Main 2024 — 6 April, Shift 2 — Question 47

Match List-I with List-II

List-I (Y vs X)List-II (Shape of Graph)
(A)Y=\text{Y}= magnetic susceptibility X=\text{X}= magnetisingfield(I)figure
(B)Y=\text{Y}= magnetic fieldX=\text{X}= distance from centre of a current carryingwire for x<a\text{x}<\text{a} (where a=\text{a}= radiusof wire)(II)figure
(C)Y=\text{Y}= magnetic fieldX=\text{X}= distance from centre of acurrent carrying wire for x>a\text{x}>\text{a} (where a=\text{a}=radius of wire)(III)figure
(D)Y=\text{Y}= magneticfield insidesolenoid X=\text{X}= distancefrom center(IV)figure

Choose the correct answer from the options given below :

  1. Option A:

    (A)-(III), (B)-(I), (C)-(IV), (D)-(II)

  2. Option B:

    (A)-(I), (B)-(III), (C)-(II), (D)-(IV)

  3. Option C:

    (A)-(IV), (B)-(I), (C)-(III), (D)-(II)

  4. Option D:

    (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

    Correct

Answer: D

Step-by-step solution

1.Graph between magnetic susceptibility and magnetising field is :

figure

2.Magnetic field due to a current carrying wire for x< a :

B=μ0ir2πaB=\frac{{{\mu }_{0}}ir}{2\pi a}

figure

3.Magnetic field due to a current carrying wire for x > a :

B=μ0i2πaB=\frac{{{\mu }_{0}}i}{2\pi a}

figure

4.Magnetic field inside solenoid varies as :

figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
6 April, Shift 2
Subject
Physics
Chapter
Magnetism and Matter
Topic
Magnetization and Magnetic Intensity, Hysteresis
Match List-I with List-II List-I (Y vs X) List-II (Shape of Graph)… | JEE Main 2024 PYQ with Solution · DhiX AI