Pressure inside a soap bubble is greater than the pressure outside by an amount : (given : R = Radius of bubble, S = Surface tension of bubble)

Physics · Mechanical Properties of Matter

JEE Main 2024 — 6 April, Shift 2 — Question 46

Pressure inside a soap bubble is greater than the pressure outside by an amount : (given : $\mathrm{R}=$ Radius of bubble, $\mathrm{S}=$ Surface tension of bubble)

Option A:
$\frac{4 S}{R}$
Correct
Option B:
$\frac{4 R}{S}$
Option C:
$\frac{S}{R}$
Option D:
$\frac{2 S}{R}$

Answer: A

Step-by-step solution

There are two liquid-air surfaces in bubble so

\Delta \mathrm{P}=2\left(\frac{2 \mathrm{~S}}{\mathrm{R}}\right)=\frac{4 \mathrm{~S}}{\mathrm{R}}

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Exam: JEE Main 2024
Paper: 6 April, Shift 2
Subject: Physics
Chapter: Mechanical Properties of Matter
Topic: Surface Tension and Surface Energy

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Answer: A

Step-by-step solution

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