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Physics · Units, Dimensions & Error Analysis

JEE Main 2024 — 6 April, Shift 2 — Question 48

In a vernier calliper, when both jaws touch each other, zero of the vernier scale shifts towards left and its 4th 4^{\text {th }} division coincides exactly with a certain division on main scale. If 50 vernier scale divisions equal to 49 main scale divisions and zero error in the instrument is 0.04 mm then how many main scale divisions are there in 1 cm ?

  1. Option A:

    40

  2. Option B:

    5

  3. Option C:

    230

    Correct
  4. Option D:

    10

Answer: C

Step-by-step solution

0.004 cm=4VSD−3MSD0.004 \mathrm{~cm}=4 \mathrm{VSD}-3 \mathrm{MSD}

49MSD=50VSD49 \mathrm{MSD}=50 \mathrm{VSD}

1MSD=1 N cm1 \mathrm{MSD}=\frac{1}{\mathrm{~N}} \mathrm{~cm}

0.004=4{4950MSD}−3MSD0.004=4\left\{\frac{49}{50} \mathrm{MSD}\right\}-3 \mathrm{MSD} 0.004=(19650−3)(1 N)0.004=\left(\frac{196}{50}-3\right)\left(\frac{1}{\mathrm{~N}}\right)

N=4650×10004=46×1000200=230N=\frac{46}{50} \times \frac{1000}{4}=\frac{46 \times 1000}{200}=230

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
6 April, Shift 2
Subject
Physics
Chapter
Units, Dimensions & Error Analysis
Topic
Vernier Calipers and Screw Gauge

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