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Physics · Motion in Plane

JEE Main 2026 — 4 April, Evening Shift — Question 4

If x and y coordinates of a projectile as a function of time (t) are given as 24t24t and 43.6t−4.9t243.6t - 4.9t^2 respectively, then the angle (in degrees) made by the projectile with horizontal when t=2t = 2 s is

  1. Option A:

    60

  2. Option B:

    45

    Correct
  3. Option C:

    30

  4. Option D:

    75

Answer: B

Step-by-step solution

x=24tx = 24t, y=43.6t−4.9t2y = 43.6t - 4.9t^2. vx=dx/dt=24v_x = dx/dt = 24, vy=dy/dt=43.6−9.8tv_y = dy/dt = 43.6 - 9.8t. tan⁡θ=vy/vx=(43.6−9.8t)/24\tan \theta = v_y/v_x = (43.6 - 9.8t)/24. At t=2t=2, tan⁡θ=(43.6−19.6)/24=1\tan \theta = (43.6-19.6)/24 = 1, so θ=45∘\theta = 45^\circ.

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
4 April, Evening Shift
Subject
Physics
Chapter
Motion in Plane
Topic
Oblique and Horizontal Projectile Motion

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