Physics · Motion in Plane

JEE Main 2026 — 4 April, Evening Shift — Question 21

A gun mounted on the ground fires bullets in all directions with same speed. The farthest distance the bullets could reach is $6.4\ \mathrm{m}$ . The speed of the bullets from the gun is $\mathrm{m/s}$ (take $g=10\ \mathrm{m/s}^2$ ).

Answer: 8

Numerical answer — enter this value.

Step-by-step solution

Maximum range $R_{\max} = v^2/g$ . So $v^2 = 6.4 \times 10 = 64$ , $v = 8\ \mathrm{m/s}$ .

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Exam: JEE Main 2026
Paper: 4 April, Evening Shift
Subject: Physics
Chapter: Motion in Plane
Topic: Oblique and Horizontal Projectile Motion

If x and y coordinates of a projectile as a function of time (t) are given as 24t and 43.6t - 4.9t^2 respectively, then the angle (in…

Answer: 8

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