Physics · Gravitation

JEE Main 2026 — 4 April, Evening Shift — Question 5

The height in terms of radius of the earth $(R)$ , at which the acceleration due to gravity becomes $g/9$ (where $g$ is acceleration due to gravity on earth's surface), is

Option A:
$\sqrt{3}R$
Option B:
$2\sqrt{2}R$
Option C:
$2R$
Correct
Option D:
$\frac{4}{9}R$

Answer: C

Step-by-step solution

$g_h = g/(1+h/R)^2$ . Setting $g_h = g/9$ gives $1+h/R = 3$ , hence $h = 2R$ .

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Exam: JEE Main 2026
Paper: 4 April, Evening Shift
Subject: Physics
Chapter: Gravitation
Topic: Gravitational Field and Gravity