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Physics · Motion in one Dimension

JEE Main 2026 — 4 April, Evening Shift — Question 3

At t=0, mass 100g starts moving under force (5i+10j) N. After 2s position is (2x i + 5y j) m. Ratio x:y?

  1. Option A:

    1:2

  2. Option B:

    2:5

  3. Option C:

    5:2

  4. Option D:

    5:4

    Correct

Answer: D

Step-by-step solution

a = F/m = (50i+100j) m/s², s = ½ a t² = 100i+200j ⇒ 2x=100→x=50, 5y=200→y=40? Wait 5y=200→y=40, but given 5y j, so y=40, then x:y=50:40=5:4

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
4 April, Evening Shift
Subject
Physics
Chapter
Motion in one Dimension
Topic
Uniformly Accelerated Motion

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At t=0, mass 100g starts moving under force (5i+10j) N. After 2s… | JEE Main 2026 PYQ with Solution · DhiX AI