Physics · Fluid Mechanics

JEE Main 2024 — 8 April, Shift 1 — Question 44

Correct Bernoulli's equation is (symbols have their usual meaning) :

  1. Option A:

    P+mgh+12mv2=\mathrm{P}+\mathrm{mgh}+\frac{1}{2} \mathrm{mv}^{2}= constant

  2. Option B:

    P+ρggh+12ρv2=\mathrm{P}+\rho g \mathrm{gh}+\frac{1}{2} \rho v^{2}= constant

    Correct
  3. Option C:

    P+ρgh+ρv2=P+\rho g h+\rho v^{2}= constant

  4. Option D:

    P+12ρgh+12ρv2=P+\frac{1}{2} \rho g h+\frac{1}{2} \rho v^{2}= constant

Answer: B

Step-by-step solution

P+ρgh+12ρV2=P+\rho g h+\frac{1}{2} \rho V^{2}= constant

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Physics
Chapter
Fluid Mechanics
Topic
Bernoulli's Equation and its Applications
Correct Bernoulli's equation is (symbols have their usual meaning) : | JEE Main 2024 PYQ with Solution · DhiX AI