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Physics · Newton's Laws of Motion

JEE Main 2024 — 8 April, Shift 1 — Question 45

A player caught a cricket ball of mass 150 g moving at a speed of 20 m/s20 \mathrm{~m} / \mathrm{s}. If the catching process is completed in 0.1 s , the magnitude of force exerted by the ball on the hand of the player is:

  1. Option A:

    150 N

  2. Option B:

    3 N

  3. Option C:

    30 N

    Correct
  4. Option D:

    300 N

Answer: C

Step-by-step solution

F=ΔPΔt=mv−00.1\mathrm{F}=\frac{\Delta \mathrm{P}}{\Delta \mathrm{t}}=\frac{\mathrm{mv}-0}{0.1}

=150×10−3×200.1=30 N=\frac{150 \times 10^{-3} \times 20}{0.1}=30 \mathrm{~N}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
8 April, Shift 1
Subject
Physics
Chapter
Newton's Laws of Motion
Topic
Application of NLM and Impulse
A player caught a cricket ball of mass 150 g moving at a speed of 20… | JEE Main 2024 PYQ with Solution · DhiX AI